Bro nuvvu views and likes assalu pattinchukoku nee videos kosam wait chesevallam chala mande unnam .. so please continue the series... Sry views and likes antunna ani em anukoku but memu unnam ani chepthunna anthe ❤❤❤. Nee video okkariki use ayina chalu kada bro ..🙌 we always support u.🙇♂️
Supper bro I really like ur explanation and thanks for ur efforts and giving this videos for free . It will be very useful for many students around. Tq u bro❤❤❤
super explanation thamudu, mi valla nenu first time leetcode problem solve chesanu ,thanks and i am 2018 passout batch......i am looking for best course and am always following your videos
First time oka problem own ga think cheyagalgina , all thanks to you, you are making everything clear, meru epatiki ila help cheyal ani korukuntuna , Mi videos walane nak Coding meli meliga ostundi matchaaa❤❤ , Please don't stop making videos 🙇♀
you are the person sending by god at right time,your explanation vere level,i am 2023 passedout only one request is try to complete this playlist as early as possible becuase year gap is increasing ,may i know when will this completed because in one day i am able to complete 5 videos due to interest by teaching.
class Solution { public int scoreOfString(String s) { int sum = 0; for (int i = 0; i < s.length() - 1; i++) { int diff = Math.abs(s.charAt(i + 1) - s.charAt(i)); sum += diff; } return sum; } } my logic . THANKS MACHA LOVE FROM KMIT 💗💗
Hi anna ee free course chala bagundhii 🛐❤️ Nenu 1st yr anna Nak computer lo zero knowledge undhi Asal em start cheyalo ardham kavatledhu emaina guide chesthava pls anna🙂oka vdo dheni meedha cheyi anna btech 4yrs ela plan cheskovali ani scratch nunchi Thank you🥹
really u r teaching the topics smoothly in a simple way... impressed with the teaching..but i'm facing a problem while building the logic due to lack of knowledge that when to use, how to use and where to use the methods like length method in string..
Frnds manamu andaramu taluchukunte e channel ki 100k subscribes tevachu so andariki share cheyandi.naku telisi idi kuda future lo oka strive dsa sheet laga avutundi
public class Main { public static void main(String[] args) { String s="hello";
int c1='h'; int c2='e'; int c3='l'; int c4='l'; int c5='o'; int ans=Math.abs((c1-c2))+Math.abs((c2-c3))+Math.abs((c3-c4))+ Math.abs((c4-c5)); System.out.println("ans is:"+Math.abs(ans));
import java.util.Scanner; class Main { public static void main(String[] args) { int sum=0; Scanner sc = new Scanner(System.in); String s = sc.nextLine(); for(int i = 1 ;i
System.out.println ('b'); rasinappudu adhi 98 ani endhuku print cheyyale I mean System.out.println ('b' - 'a'); rasinappudu adhi characters ni ascii values ga marchukoni Mari 1 ani output isthundhi. But second case lo endhuku adhi string ga teeskoni b print chesindhi.
Bro nuvvu views and likes assalu pattinchukoku nee videos kosam wait chesevallam chala mande unnam .. so please continue the series...
Sry views and likes antunna ani em anukoku but memu unnam ani chepthunna anthe ❤❤❤.
Nee video okkariki use ayina chalu kada bro ..🙌 we always support u.🙇♂️
Supper bro
I really like ur explanation and thanks for ur efforts and giving this videos for free . It will be very useful for many students around.
Tq u bro❤❤❤
anna nuvvu thop evadu panikikuda raru i found gem person in my life explaination was vere level macha keep going on macha never stop posting videos..
Anna already DSA concept vachhina valla mu kuda chustunnam ... because become a Deep learner in DSA ...so please don't stop uploading the videos ❤❤
super explanation thamudu, mi valla nenu first time leetcode problem solve chesanu ,thanks and i am 2018 passout batch......i am looking for best course and am always following your videos
class Main {
public static void main(String[] args) {
String s="hello";
int count=0;
for(int i=0;i
First time oka problem own ga think cheyagalgina , all thanks to you, you are making everything clear,
meru epatiki ila help cheyal ani korukuntuna , Mi videos walane nak Coding meli meliga ostundi matchaaa❤❤ , Please don't stop making videos 🙇♀
@@CSKatt1108 All the best macha 🎊
class Solution {
public int scoreOfString(String s) {
int t=0;
for(int i=0;i
Very good explanation bro,asalu time eh teliyatle video chustunte,
Thank you is not enough 🙌
class HelloWorld {
public static void main(String[] args) {
String s="zaz";
int sum=0;
for(int i=0;i
Each day one video of engineering animuthyam keeps unemployment away. #dsa #java
free ga chptunnanduku tnx bro anthaku minchi emi chppagalamu❤
Broh.... Keep rocking broh.......... Waiting for your viedos.....❤❤
Bro its very useful to solve the dsa problem.Tq bro🤝🥳u r efforts on teching topics was excellent.💯
Bro, super bro ni classes , That we are going to make you PROUD for sure..❤
Machaaa.....chaalaa baga cheptunnavv!!! ni dagara vere a youtuber sariporuu...nuv next level antheyy
Bro leetcode lo problem submit chestunte aah feel ee heaven bro 😊
Macha super explanation macha 🎉🎉🎉
tried Macha :
class Solution {
public int scoreOfString(String s) {
char []a= s.toCharArray();
int res = 0;
for(int i=0;i
you are the person sending by god at right time,your explanation vere level,i am 2023 passedout only one request is try to complete this playlist as early as possible becuase year gap is increasing ,may i know when will this completed because in one day i am able to complete 5 videos due to interest by teaching.
ini=[]
for i in range(len(s)-1):
b=ord(s[i])-ord(s[i+1])
c=abs(b)
ini.append(c)
return sum(ini)
ascii
int ans = 'b';
int an = 'a';
System.out.println(ans - an);
ouput: 1
nee videos chala bagunayi bro really good
class Solution {
public int scoreOfString(String s) {
int sum = 0;
for (int i = 0; i < s.length() - 1; i++) {
int diff = Math.abs(s.charAt(i + 1) - s.charAt(i));
sum += diff;
}
return sum;
}
} my logic . THANKS MACHA LOVE FROM KMIT 💗💗
super bro chela easy ga artham avvutundi ne way of explanation❣super
tq you
n=String.length();
Int add=0;
For(int I=0;I
class HelloWorld {
public static void main(String[] args) {
String str = "hello";
int sum = 0;
for(int i=0; i
chala baga ardam avutunayi broo
int a=' a';
int b='b';
c=a-b;
System.out.println(c);
Best explanation ever 👏
Btw happy teachers day bruh
anna nuvvu super anna chala baga ardam ayala chappavu thank u so much e series elene continue chey plz stop cheyaku anna
public int scoreOfString(String s)
{
int score =0;
for(int i=0 ;i
Thank you so much 🎉
Super Explanation bro💗💗
class Main {
public static void main(String[] args) {
String s="madhav";
int count=0;
for(int i=0;i
fantastic explanation brooooooo
Hi anna ee free course chala bagundhii 🛐❤️
Nenu 1st yr anna
Nak computer lo zero knowledge undhi
Asal em start cheyalo ardham kavatledhu emaina guide chesthava pls anna🙂oka vdo dheni meedha cheyi anna btech 4yrs ela plan cheskovali ani scratch nunchi
Thank you🥹
class Solution:
def scoreOfString(self, s: str) -> int:
score=0
for i in range(len(s)-1):
score=score+abs(ord(s[i])-ord(s[i+1]))
return score . python lo kuda chesa bro . present nenu ml and data science chesthunna so python use chesa
really u r teaching the topics smoothly in a simple way... impressed with the teaching..but i'm facing a problem while building the logic due to lack of knowledge that when to use, how to use and where to use the methods like length method in string..
@@himabindubontha4066 haa next rep video lo 3 more problems solve chedham so ala chesthu unte logic improve avthundhi
@@engineeringanimuthyam sure..thank you for the boost up👍
Int n='a';
Int n='b';
Int dif=a-b;
System.out.println(dif);
Macha daily 2 videos upload chey epudu nenu 4-1 so please
Same bro nenu kuda plz 2 videos upload cheyu
Bro 4th yr lo unte.. Ila videos chustu time waster avtadi.. best option is to do self learn from websites like w3 schools, and start Leetcode on own
Same hear broh......plzzzz make it fast maccha.......😢
class Solution {
public static int scoreOfString(String s) {
int array[]=new int[100];
for(int i=0;i
class Solution {
public int scoreOfString(String s) {
int temp = 0;
for(int i=1;i
Anna literally saying ur teaching skills are superb.asalu time teliyatledhu anna
Int s='b';
Int p='a';
Int r=s-p;
System .out .println(r);
Anna motham questions anni cover cheye anna interview plus neeku vunna motham knowledge its very helpful annaaaaaaaaa....
Ok bro sure
class Solution {
public int scoreOfString(String s) {
int sum =0;
for(int i =0;i
maccha idhi na approach but memory ekkuva tesukuntundhi
Emle bro efficient approach ae
char a='a';
char b='b';
int res=(int)(b)-(int)(a);
System.out.print(res);
Super explaination bro ❤😊
int ans=0;
for(int i=0;i
class Test {
public static void main(String[] args) {
String s="DON";
int sum=0;
for(int i=0;i
class LCp1 {
public static void main( String []args){
String s ="hello";
int temp ,add=0;
for(int i=0;i
int a = 'a';
int b = 'b';
System.out.println(a-b);
class Solution {
public static void main(String[] arg) {
String s="hello";
int count=0;
for(int i=0;i
artham ayindi raja
class HelloWorld
{
public static void main(String[] args)
{
String a="hello";
int score=0,temp;
for(int i=0;i
class Solution {
public int scoreOfString(String s) {
int temp=0;
int result =0;
for (int i=0; i
class leela{
public static void main(String args[ ])
{
int l = 'a';
int m='b';
int n=m-l;
System.out.println(n);
}
}
mundhe vachindhi macha
class Solution {
public int scoreOfString(String s) {
int a;
int b;
int c=0;
int t=0;
for(int i=0;i
int m = 'a';
int n = 'b';
int diff = n - m;
class Solution {
public int scoreOfString(String s) {
int w = 0;
int sum = 0;
for(int i=0;i
class Solution {
public int scoreOfString(String s) {
int sum=0;
for(int i=0;i
class Solution {
public int scoreOfString(String s) {
int count=0;
for(int i=0;i
class Solution {
public int scoreOfString(String s) {
char[] ch=s.toCharArray();
int ans=0;
for(int i=0;i
class Solution {
public static void main(String[] args) {
String S="Hello";
int dif=0;
for (int i=0;i
Hi bro..daily concepts tho paatu oka leetcode code problem solve chesi post chey bro pls. Maak kuda koncham use avtundhi🙏🏼🙏🏼🙏🏼
Great explanation
public class AsciiValue {
public static void main(String[] args) {
int a = 'a';
int b = 'b';
int c = 'a'-'b';
System.out.println(c);
}
}
public class Main
{
public static void main(String[] args) {
String a="hello";
int count=0;
for(int i=0; i
class Main{
public static void main(String[] args){
int n='a';
int n2='b';
int res=n2-n;
System.out.println(res);
}
}
public int scoreOfString(String s) {
int sum=0;
for(int i=0;ii;j--){
int n=Math.abs(s.charAt(i)-s.charAt(j));
sum=sum+n;
}
}
return sum;
class HelloWorld {
public static void main(String[] args) {
int a='a';
int b='b';
System.out.println(b-a);
}
}
Tq Macha❤
Frnds manamu andaramu taluchukunte e channel ki 100k subscribes tevachu so andariki share cheyandi.naku telisi idi kuda future lo oka strive dsa sheet laga avutundi
Thankyou macha 🥹
@@engineeringanimuthyam yes bro ne efforts ki cumpulsory worth untadi future lo.so plz keep doing videos 📷
Anna thankyou so much for hardwork 🎉🎉😢😢
super
Class bunny {
Public static void main(String args[ ] ){
Int n = 'a' ;
Int m = ' b' ;
Int c = m - n;
System.out.println(c);
}
}
O/p : 1
class HelloWorld {
public static void main(String[] args) {
String c="hello";
int d=0;
for(int i=0;i
class Animuthyam {
public static void main(String[] args) {
int ch='b';
int c='a';
System.out.println(ch-c);
}
}
public class Main {
public static void main(String[] args) {
String s="hello";
int c1='h';
int c2='e';
int c3='l';
int c4='l';
int c5='o';
int ans=Math.abs((c1-c2))+Math.abs((c2-c3))+Math.abs((c3-c4))+
Math.abs((c4-c5));
System.out.println("ans is:"+Math.abs(ans));
}
}
Here's the solution -
public int scoreOfString(String s) {
char ch[] = s.toCharArray();
int ans = 0;
for(int i=0;i
import java.lang.Math;
class Solution {
public int scoreOfString(String s) {
int x=0;
for(int i=0;i
Macha🔥🔥🔥🔥
class Solution {
public int scoreOfString(String s) {
int temp = 0;
for(int i=0;i
class HelloWorld {
public static void rahul( int b,String f){
// System.out.println(b);
for(int i=0;i
char[] chars=s.toCharArray();
int result=0;
for(int i=0;i
import java.util.Scanner;
import java.lang.Math;
class Solution {
public static int scoreOfString(String s) {
int temp=0,ab=0;
for(int i=0;i
class HelloWorld {
public static void main(String[] args) {
int n ='b';
int s ='a';
System.out.println(n-s);
}
}
class Solution {
public int scoreOfString(String s) {
int i,sum=0;
for(i=0;i
class HelloWorld {
public static void main(String[] args) {
int k ='a';
int c='b';
int d=c-k;
System.out.println(d);
}
}
class HelloWorld {
public static void main(String[] args) {
int A = 'b';
int B ='a';
int C = A-B;
System.out.println(C);
}
}
literally so nice .
Mi patience ki🫡
import java.lang.*;
class ascii{
public static void main(String[] args){
int n='b'-'a';
System.out.println(n);
}
}
import java.util.Scanner;
class Main {
public static void main(String[] args) {
int sum=0;
Scanner sc = new Scanner(System.in);
String s = sc.nextLine();
for(int i = 1 ;i
System.out.println ('b'); rasinappudu adhi 98 ani endhuku print cheyyale
I mean System.out.println ('b' - 'a'); rasinappudu adhi characters ni ascii values ga marchukoni Mari 1 ani output isthundhi.
But second case lo endhuku adhi string ga teeskoni b print chesindhi.
class HelloWorld {
public static int find(String input)
{
//hello
int sum=0;
for (int i=0;i
package Strings.strings_B;
import java.util.*;
public class ScoreOfString {
public static int check(String s){
int temp =0;
for(int i =0; i
🙌