physics Top 30 MCQ || physics MCQS with answers || Multiple choice Questions
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- เผยแพร่เมื่อ 12 พ.ค. 2024
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Hi viewer! Today I have covered complete physics mcqs with answers. these Mcqs are very important for all upcoming Exams, especially for class part I & part II,
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Ans.of 12th qus. Wrong
2m/ss is correct
Yeah sure! To determine the acceleration of an object when a force is applied, you can use Newton's second law of motion, which is given by the formula: F=ma F=ma where: F F is the force applied, m m is the mass of the object, a a is the acceleration of the object.
Given:
Force
F=10 N
F=10N
Mass
m = 5 kg
m=5kg
We need to find the acceleration
a
a.
Rearranging the formula to solve for
a
α:
a=Fm
α =
m
F
Substituting the given values:
a=10 N5 kg
α =
5kg
10N
a=2 m/s2
a=2m/s
2
So, the acceleration of the object is
2 m/s2
2m/s
2
Nice pyq 👍👍
♥️♥️♥️
Nice Mcqs sir/m
🌻
Thankuuu sir 🙏 its nice ....nd very gud for basics 👌 😊
🌻
Sir All is well so always be happy
🌻
12 me a Hoga
Yeah sure!To determine the acceleration of an object when a force is applied, you can use Newton's second law of motion, which is given by the formula:
𝐹=𝑚𝑎
F=ma
where:
𝐹
F is the force applied,
𝑚
m is the mass of the object,
𝑎
a is the acceleration of the object.
Given:
Force
𝐹=10 N
F=10N
Mass
𝑚=5 kg
m=5kg
We need to find the acceleration
𝑎
a.
Rearranging the formula to solve for
𝑎
a:
𝑎=𝐹𝑚
a=
m
F
Substituting the given values:
𝑎=10 N5 kg
a=
5kg
10N
𝑎=2 m/s2
a=2m/s
2
So, the acceleration of the object is
2 m/s2
2m/s
2
.
12 A
♥️
F=10 Nm=5 kg2 lines; Line 1: cap F equals 10 space N; Line 2: m equals 5 space kg end-lines;
𝐹=10 N𝑚=5 kg
Plug-in values

10 N=5 kg⋅a10 space N equals 5 space kg center dot a
10 N=5 kg⋅𝑎
Divide both sides by the same factor

10 N5 kg=5 kg⋅a5 kgthe fraction with numerator 10 space N and denominator 5 space kg end-fraction equals the fraction with numerator 5 space kg center dot a and denominator 5 space kg end-fraction
10 N𝟓 kg=5 kg⋅𝑎𝟓 kg
Simplify

a=2 N/kga equals 2 space N / kg
𝑎=2 N/kg
Convert units

a=2 m/s2a equals 2 space m / s squared
𝑎=2 m/s2
❤️❤️❤️
All is well sir ❤❤❤batameez student kabhi kamiab ni hotay
Much love 💓
12 no answer 2m/s²
🌻
12 Quistion Ans is wronG its Ans is 2m/s
♥️
Question 9 you discuss speed and acceleration not centripetal acceleration
I am so sorry Brother, I don't understand what you are talking about, explain to me a little so that I can answer you.
@@studyRoom31 sir g my question is that in your question is confusion b/c you talking about the speed and acceleration not centrepetal acceleration plz don`t mind and check your answer
@@syedsaliman2195 Acceleration is defined as the rate of change of velocity with respect to time. Velocity includes both speed and direction. If an object is moving at a constant speed, its speed does not change. However, for the object to have zero acceleration, its direction must also remain constant.
Thus, when an object moves at a constant speed in a straight line (constant velocity), there is no change in its velocity, and hence its acceleration is zero.
In summary:
Constant speed implies no change in the magnitude of velocity.
For acceleration to be zero, the direction must also be constant.
Therefore, constant speed in a straight line results in zero acceleration.
Es trah ky channel monitize hoty hn????
I don't know
Q12 is also wrong
Yeah sure.It is the correct answer option A
answer are wrong
Which answer is wrong tell me to see the book quickly?
Ans.of 12th qus. Wrong
2m/ss is correct
20 k a hoga
Determine the net displacement
direction and distance:
Moving 10 meters north is a positive displacement in the north direction.
Moving 5 meters south is a negative displacement in the north direction.
Calculate the net displacement:
Net displacement
=
10
meters north
−
5
meters south
=
5
meters north
Net displacement=10meters north−5meters south=5meters north
Magnitude of the displacement:
The magnitude of the displacement is the absolute value of the net displacement.
Magnitude of displacement
=
∣
5
meters
∣
=
5
meters
Magnitude of displacement=∣5meters∣=5meters
Thus, the magnitude of the displacement is 5 meters.
Correct answer option A