Math Tricks for SI Prefixes | MCAT Math

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  • เผยแพร่เมื่อ 22 ส.ค. 2024

ความคิดเห็น • 15

  • @martinriva5775
    @martinriva5775 2 ปีที่แล้ว +9

    I found you on my last two weeks of studying for this MCAT, I take it next friday. Don't stop making these!

    • @EightfoldMCAT
      @EightfoldMCAT  2 ปีที่แล้ว +1

      Good luck next Friday and thanks for leaving a comment!!!

  • @premedhelps
    @premedhelps 2 ปีที่แล้ว +9

    YOUR videos are AMAZING!!!! I am giving my MCAT soon and cannot emphasize how good your videos are. please do not stop making them. You will definitely blow up soon :)

  • @Eldarin
    @Eldarin 2 ปีที่แล้ว +1

    Really appreciate your videos, i hope your channel gets even more traffic as it certainly deserves it

  • @inconspicuouscockatiel1983
    @inconspicuouscockatiel1983 2 ปีที่แล้ว +1

    As always, this video is so helpful, thank you so much! I was always curious about squaring and cubing, but do you have any specific tips on how to cube root or square root a scientific notation number?
    Say that you have to find concentration of product concentration [X] given pH of x value and other terms. I sometimes ended up with an equation like x^2 = 1.2 x 10^4
    I know that square rooting means dividing exponents by 2, but how does one deal with the 1.2? and say the exponent is odd. Do you have any tips for this?

    • @EightfoldMCAT
      @EightfoldMCAT  2 ปีที่แล้ว +1

      I will eventually make a video on this concept, but here is how I would go about approaching this.
      For math such as √1.2 you can just estimate that to closest perfect square so in this case √1.2 = √1 = 1. We know that we rounded this down so I would expect the actual answer to be a bit bigger than 1 but that is good enough for the MCAT.
      When taking the square root or cube root of non-divisible number you will want to change the exponent by adding zeros to the number out front. For example, √5 x 10^-5 we will turn this into √50 x 10^-6. The √50 = √49 = 7 and the √10^-6 = 10^-3 so overall √5 x 10^-5 = 7 x 10^-3.
      You can use the same technique for cube roots, but I suspect that the math for cube roots would be easier since these values are harder to estimate.
      Hope that helps!

    • @inconspicuouscockatiel1983
      @inconspicuouscockatiel1983 2 ปีที่แล้ว

      It does, thank you again!

    • @EightfoldMCAT
      @EightfoldMCAT  2 ปีที่แล้ว

      Of course.

  • @vishalmishra3046
    @vishalmishra3046 ปีที่แล้ว

    What about Ronna and Ronto ?
    The SI prefix name for 10^30 was originally proposed to be *Quecca* and then replaced by *Quetta* , since the former is inappropriate in some languages.

    • @EightfoldMCAT
      @EightfoldMCAT  ปีที่แล้ว +3

      I only included the MCAT relevant units so poor Ronna got left out this time.

  • @sahar846
    @sahar846 2 ปีที่แล้ว

    Thank you sooo much! By any chance will you be posting physics lessons? I’m horrible at it!

    • @EightfoldMCAT
      @EightfoldMCAT  2 ปีที่แล้ว +4

      For now my current in-progress videos are mostly gen chem, math, and strategy. I will eventually get around to physics, but I don’t have anything planned at the present. If there is enough interest in physics I would be more than happy to cover topics during Monday live sessions. They aren’t as polished as the regular videos but I can get content out a lot faster since since I don’t have to create all the visuals, script them, master the audio, etc.

    • @sahar846
      @sahar846 2 ปีที่แล้ว

      Thank you!!!!!