Why do we use I common the same as I primary. I primary = I common + I secondary In the problem you hv considered I primary equal to I common which means secondary current is zero as per KCL. Pls clear my confusion.
I believe we cannot use Ip and Is from orignal single phase transformer. We dont we derive primary and secondary current again when we hv kVA and new Voltages for auto transformer.
This is an auto-transformer that is being made from a single-phase transformer. Picture opening up a single-phase transformer and shorting the windings together on one end and changing where your tap termainls are in order to use both windings as an auto-transformer. Each winding on the single-phase transformer cannot exceed it's rating, so the full load current of each winding will be the same with respect to the voltage direclty across it when we reconfigure the single-phase transformer into an auto-transformer. The common current (Ic) of the new auto-transformer will equal the primary current of the previous single-phase transformer that it was made from (Ip). The primary current of the auto-transformer is designed as Ipri to avoid confusion. Take a look at a new video we published earlier this year that goes through all of the circuit analysis relationships of auto-transformers, I think it will help clear up any confusion: th-cam.com/video/XB9yTOtIzDc/w-d-xo.html
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The breakdown of how you go from a typical single phase transformer to this is fantastic. Haven't found a better explanation of it. Thank you Zach!
My pleasure. Glad you found it helpful
This is my new favorite explanation video. How simple you make things is beyond me!
Thanks for your comment, glad it helped!
I like the way you described it. Awesome
Thanks Shahryar, glad you enjoyed it
This video helped me understand this concept. When in doubt, use circuit analysis! Always better than memorizing formulas.
Zach, another great video and help understanding the subject.
This helped me understand this topic.
Great Video Zach
Thank you for this amazing explanation
Great video, thank you so much. I kept wondering what the "c" subscript in the NCEES manual was!
Hi Julia, thanks for your comment. Glad to hear you enjoyed the video.
Beyond necessary. Was one of my harder topics
Great Video
Hi my name is Nish I am doing electrical engineering N1 and need help could you please assist me with tutoring me?
Couldn't you also use the common:series turn ratio to find the input/output power rating? Using Nseries = 480 and Ncommon = 4160
You sure can
Why do we use I common the same as I primary.
I primary = I common + I secondary
In the problem you hv considered I primary equal to I common which means secondary current is zero as per KCL. Pls clear my confusion.
I believe we cannot use Ip and Is from orignal single phase transformer. We dont we derive primary and secondary current again when we hv kVA and new Voltages for auto transformer.
This is an auto-transformer that is being made from a single-phase transformer. Picture opening up a single-phase transformer and shorting the windings together on one end and changing where your tap termainls are in order to use both windings as an auto-transformer.
Each winding on the single-phase transformer cannot exceed it's rating, so the full load current of each winding will be the same with respect to the voltage direclty across it when we reconfigure the single-phase transformer into an auto-transformer.
The common current (Ic) of the new auto-transformer will equal the primary current of the previous single-phase transformer that it was made from (Ip).
The primary current of the auto-transformer is designed as Ipri to avoid confusion.
Take a look at a new video we published earlier this year that goes through all of the circuit analysis relationships of auto-transformers, I think it will help clear up any confusion:
th-cam.com/video/XB9yTOtIzDc/w-d-xo.html