what actually damaneged the led, voltage or Current? cuz resistor in series reduces current and in parallel reduces voltage. that means 12v is still being delivered to the led . explain why it didn't blow off too
Didier Tekum 12v is not being applied to the second led. There is a voltage drop across the resistor the voltage drop is equal to the current flowing through the resistor times it's resistance. I hope to do a video on circuit analysis to explain some of these ideas. Check out kirchhoff's voltage law and ohm's law it will help explain this. To answer your question though, the current damaged the LED. Because of ohm's law since the first LED had 12V across it, the current was large enough to destroy the LED.
what actually damaneged the led, voltage or Current? cuz resistor in series reduces current and in parallel reduces voltage. that means 12v is still being delivered to the led . explain why it didn't blow off too
Didier Tekum 12v is not being applied to the second led. There is a voltage drop across the resistor the voltage drop is equal to the current flowing through the resistor times it's resistance. I hope to do a video on circuit analysis to explain some of these ideas. Check out kirchhoff's voltage law and ohm's law it will help explain this. To answer your question though, the current damaged the LED. Because of ohm's law since the first LED had 12V across it, the current was large enough to destroy the LED.