I love the video, especially the steps, it's very helpful and constructive. But I have 1 question about valve coefficient c = 50 kg/s /% open. Do you mean 100% open means the valve can deliver 50 times 100 or 50 times 1? Thanks before.
Thanks for the helpful tutorial! Would you please tell me why you stored the result in 'z'? why we cannot plot level plot itself instead of z? One more thing that I got confused is that, why did you use another variable, valve, instead of u in the model?
It is emulating discrete sampled systems like PID control or MPC control where a measurement is taken every 0.1 or 1.0 sec. In the Process Dynamics and Control course, a new value of the controller output is injected into the simulation model every sample time so we integrate in steps. apmonitor.com/pdc
Hi, I don't understand why the final result is not equal to 25 cm. Since the valve opening rate is constant from two to seven sec, we can easily calculate the final height by the following equation: 50*100%*(7-2)=1000*1.0*h. Then the answer should be 0.25 m instead of 0.245. Could you please consider it if you saw the review. I am very confused.
It isn't exactly 5 seconds opened. It is between time points 21 and 69. Try it with time points 21 to 71 and see if that gives you an answer that is consistent with your calculation. Change the line u[21:70] to u[21:72] for 21 to 71 time points.
At 15:38, I use u[i+1] because the starting conditions are already specified and I am computing the next step. I could have used 'i' instead if I change the loop on line 28 to: "for i in range(1,101)".
There is one step missing which is the most important of all steps which is ** Type of model to be obtained ** I would place it as number 2 as you know there are 4 kinds models
There is the course web-site available at apmonitor.com/pdc - unfortunately, I don't have a way for online participants to join this class directly. The dynamic optimization course does have an online option to join. The next class starts January 2019.
I'd recommend the course web-site at apmonitor.com/pdc - the videos are grouped by topic with a natural progression. You can also build a playlist from these videos if you have a suggestion about how they should be organized.
thanks for the presentation, just note that the tank level axis is in cm.
Thank you very much for this sir! Very useful! Thank you for your helpful videos.
I love the video, especially the steps, it's very helpful and constructive. But I have 1 question about valve coefficient c = 50 kg/s /% open. Do you mean 100% open means the valve can deliver 50 times 100 or 50 times 1? Thanks before.
So is it correct to say that we are programming a Level Transmitter in the python script part?
No, this video doesn’t cover programming a level transmitter. Here is more information on transmitters: apmonitor.com/pdc/index.php/Main/SensorSignals
amazing work sir
Thanks for the helpful tutorial!
Would you please tell me why you stored the result in 'z'? why we cannot plot level plot itself instead of z?
One more thing that I got confused is that, why did you use another variable, valve, instead of u in the model?
I commonly use 'u' as the input of a function and 'x', 'y', or 'z' as the output. You could change the code to be more readable.
Thanks for the tips
Can someone help me. Why am I getting this error: can't multiply sequence by non-int of type 'float'
after running the same code
Try converting it to a numpy array first before multiplying by a float such as f * np.array(x)
Is there a reason for why you integrate 0.1 secs at a time?
It is emulating discrete sampled systems like PID control or MPC control where a measurement is taken every 0.1 or 1.0 sec. In the Process Dynamics and Control course, a new value of the controller output is injected into the simulation model every sample time so we integrate in steps. apmonitor.com/pdc
Hi, I don't understand why the final result is not equal to 25 cm. Since the valve opening rate is constant from two to seven sec, we can easily calculate the final height by the following equation: 50*100%*(7-2)=1000*1.0*h. Then the answer should be 0.25 m instead of 0.245. Could you please consider it if you saw the review. I am very confused.
It isn't exactly 5 seconds opened. It is between time points 21 and 69. Try it with time points 21 to 71 and see if that gives you an answer that is consistent with your calculation. Change the line u[21:70] to u[21:72] for 21 to 71 time points.
@@apm Thank you very much! I have tried and it worked.
Thank you for the tutorial. I have a quick question. Why does valve = u[i+1] ? Why is the first value of the open % is being skipped?
At 15:38, I use u[i+1] because the starting conditions are already specified and I am computing the next step. I could have used 'i' instead if I change the loop on line 28 to: "for i in range(1,101)".
@@apm Ok, that makes sense. Thats what i was thinking. Thanks you!
There is one step missing which is the most important of all steps which is ** Type of model to be obtained ** I would place it as number 2 as you know there are 4 kinds models
Thanks for the valuable insight, Moaz!
sir can us enroll online from your class ,seminar as face to face free or just seeing online from youtube videos or website videos
There is the course web-site available at apmonitor.com/pdc - unfortunately, I don't have a way for online participants to join this class directly. The dynamic optimization course does have an online option to join. The next class starts January 2019.
ok sir
sir please make different playlist for different topics and sir please more playlist
I'd recommend the course web-site at apmonitor.com/pdc - the videos are grouped by topic with a natural progression. You can also build a playlist from these videos if you have a suggestion about how they should be organized.
thanks sir