#22 Python Tutorial for Beginners | Break Continue Pass in Python

[@nujranujranujra]

My college life would be great if I had a professor like you in my college

[@arjunchavan9669]

Hey Arjun! Never met another Arjun

[@anmol3457]

Arjun siva it really wouldn’t because we usually find another problem with the professor.

[@akash6327]

damn really :) i would not study at all or daily 1 hour would be enough to get a rank :)

[@faridhaf8626]

Agreed

[@PaWoW-PW]

@@arjunchavan9669 cap, Arjun's are everywhere

[@AmitKhuranaSir]

i am experienced programmer so watching on 2x speed but for your bbye i slow down the speed!!!!! your way of saying bbye is awesome

[@jurrulokeshyadav842]

I will complete my python within 1 week by your teaching sir.
I thank you very much sir for teaching this course.

[@siddharthrajan616]

yeah I am planning to complete it in a single night lol

[@tudos9209]

@@siddharthrajan616 quite possible though

[@shyamjaiswal3432]

@@siddharthrajan616 😂😂🤣 exectly

[@rraushan1000]

I had literally searched whole TH-cam in search of a video that could explain me loops but I didn't get one. Then, I found this channel and finally I understood loops and even make programs using while and for loops.
Thank you Navin sir :)

[@pradeepchandertiwari2883]

My vending machine is not working even with the same code

[@tirthshah3350]

I had just started your python tutorial and it was the best. One request is that at last please also show how to make games and software in python.

[@flamboyantperson5936]

When you will start with "Machine Learning"? It's going to be awesome if you teach us.

[@anindian4601]

Not only machine learning we want Artificial Intelligence TOO.

[@ashwiniambhore3056]

+1

[@divyanshusingh6105]

You are a really great man.... I learned from you and practise some programs and i did it... First time in my life i can create the logic..🙌🙌🙌

[@BhuveshDhiman]

x=int(input("Enter a no."))
s=0
i=1
while(i

[@suryanshugarg10]

good one

[@BhuveshDhiman]

@@suryanshugarg10 thank you

[@darshitthakar7999]

Nice one .

[@divyasree24]

why do we need to check s==2:;why not s==1?

[@joseph481994]

@@divyasree24 a prime number is divisible by 1 and itself implying that the "if" block would have executed twice if the number was prime.

[@stmpcol]

Teaching is an art. You've got it man👍 very logical progression for beginners.

[@rohithsardar187]

2.
a=int(input("enter a integer"))
count=0
for i in range(1,a+1):
if(a%i==0):
count=count+1
if count==2:
print(a)

[@DevendraSingh-xt2wn]

#fibonacci
list1 = [0, 1]
for i in range(48):
list1.append(list1[-1]+list1[-2])
print('bye')
print(list1)

[@rajjoshi4302]

Smart Logic

[@anon5788]

This is very nice approach. learnt a new thing

[@chandhrusrinivasan9595]

Woow

[@rubanaugastin9049]

What's out put of this code

[@viswa_mulukutla]

hey, looks simple but whats the logic here.. can you explain

[@ahilanbhattacharya3402]

sir you are a very great teacher i am 13 years old and i am learning python and as well i could understand each and every thing you say..you're teaching style is really great..

[@sainikhila4027]

fibonacci solution
a = [0,1]
for i in range(0,49):
b = a[-1]+a[-2]
a.append(b)
print(a)

[@babasahebbhosale7908]

b=a [0]+a [1] is also right na

[@Bharathsuru]

@@babasahebbhosale7908 no it's wrong if you do like that you will get [0,1,1,1,1,1,1...........]

[@hjjkgdgfdgf]

@@babasahebbhosale7908 If you do that, it will keep adding only first 2 numbers and that would be 0+1 always. Doing a[-1] + a[-2] would do a sum of last 2 digits, which is what is needed for fibonacci series

[@DineshKumar-xi8rv]

Sir I am in 7th grade and you are one of the best coding teacher ever as well as your examples make easy to understanding coding in py.

[@rajtiwari6645]

av=6
x=int(input('how many candies do you want'))
for i in range(0,x):
if i

[@bsmaheshkumar5328]

Why we need udemy when we have a professor like you. Outstanding explanation.

[@frenchfatfather]

for real?

[@omkarpathak4759]

Sir the way of your teaching has just made learning python so easy and I'm blessed to learn from you sir.
Hope i could meet you some day.

[@selvib7634]

I have never heard a explanation about loop... Brilliant explanation 👌... Thanks a lot sir.

[@princeraj7106]

x=int(input('enter a number'))
i=2
while i

[@vivekrenikunta2398]

According to your code, 9 is a prime no which it is not.

[@princeraj7106]

@@vivekrenikunta2398 Recheck it.. Its certainly giving not a prime number as 9 as an input... I think u misinterpreted the output...Try again using proper indentation...!

[@vivekrenikunta2398]

Yeahh... I'm sorry'😅

[@princeraj7106]

@@vivekrenikunta2398 no issues...

[@divyanshusingh6105]

1-n=int(input("Enter no of Sequence:"))
def fib(n):
a,b=0,1
while b

[@dharmishtabasita666]

n=int(input("enter the number for checking it is prime or not:"))
i=2
while i

[@Ihsan_almohsin]

Break : to end the loop. It uses with if statement to put a condition so you can break the loop and exit.
Continue : to skip the remaining code of the loop when a certain condition happen (like in if statement), but still looping.
Pass: uses for impty blocks when you don't have a code to write.

[@alejrandom6592]

thx!

[@YourHotMan]

can someone explain me...why he use * while i

[@goutambanerjee185]

@@YourHotMan i means no. of candies & x is the Limit of candies no. i.e. total candies want

[@uday2159]

@@YourHotMan it's not * bro it is colon :

[@publicenemy1415]

Here it looked like continue & pass are the same. Whats the difference? Used continue to skip number div. by 3 & used pass to skip odd numbers.

[@anindian4601]

av=6
x=int(input("how many candies you want :"))
i = 1
while iav:
print("Please Collect",i-1,"Candies &",x-av," Candies are Out of Stock ")
break
print(i,"Candy")
i+=1

[@akarshasudheer6626]

To check if a given number is prime or not:
i=2
p = int(input("Enter a number:"))
while i

[@ankitrawat_data]

your code will fail on 0 and 1

[@nakeebraut8676]

a=int(input('How many candies?'))
av=5
i=1
While iav:
Print('candies left=, end='')
Print (av)
break
Print ('candy')
i=i+1

[@vaishnavigoswami2891]

you r the only one best teacher....thank u so much, sir....just because of u all the concept are clear now

[@vernanonix]

I made my previous prime checker better. Super satisfied:
x=int(input("For what number would you like to check primeness? "))
factor=2
while factorx/factor:
print(x,"is a prime number.")

[@androygaminghk1197]

Tq for your teachings sir....u made python easy to learn and understand...
Waiting for machine learning teachings...

[@sankalparora7254]

a=int(input("enter a number"))
if(a==2):
print('prime number')
else:
for i in range (2,a):
if(a%i==0):
print('not a prime')
break
if(i==(a-1)):
print("prime number")

[@sandeepch]

i like i(i==a-1)

[@vernanonix]

@@sandeepch If you limit your range to the square root of a, you'll go faster. Granted, I don't think range will take a float number so you might need to ceil it. But essentially half of the factors exist before the square root and half exist after. But if you check everything in the first half, you'll find their pair in the second half. Thus you only need to check the first half.

[@alejrandom6592]

I love that you use analogies to explain abstract concepts, great video!

[@venkatahariprasad8753]

n = int(input('enter the no fibonnacci num'))
n1=0
n2=1
print(n,"first fibonacci numbers are",)
print(n1,' ',n2,end='\t')
i=0
while i

[@indranujdas5917]

1. Fibonacci Series Code:
x=0
y=1
print('The Fibonacci Series will be:
')
print(x)
print(y)
i=1
while i

[@rohansinha6309]

Thanks buddy 😄

[@bmguitarhub6135]

why 48 not 50?

[@akarshasudheer6626]

@@bmguitarhub6135 Because we are already printing value 0 and 1 before entering while loop so that leaves us with 48 more values to complete first 50 fibonacci numbers

[@bmguitarhub6135]

@@akarshasudheer6626 yeah, thank youuu

[@Manoj_Max]

Can you explain 'pass' statement clearly....for yy we are use that condition??...plz anybody

[@mtromanff320]

You are just rocking🔥....the way of teaching is out of world 🫡

[@mahmoudamin8534]

1st 50 fib numbers :
first = 1
second = 1
temp = 0
for i in range (50):
if i == 0 or i == 1 :
print(1)
else:
print(first+second)
temp = first+second
first = second
second = temp

[@syedaqib2912]

super it really works...

[@sardarrashid639]

print(i) it will work

[@fatihavc8453]

from math import sqrt
x = int(input('Enter a number to check primeness: '))
n = 2
for i in range(1,x-1):
if x%n==0:
print("not a prime")
break
elif n==x-1:
print("prime")
break
n += 1

[@naumanhameed900]

list = [0,1]
for i in range(49):
list.append(list[-1]+list[-2])
print("Fibonacci Sequence is = ", end="")
for i in list:
print(i, end=" ")

[@aravindtnpsc4568]

Your condition will print 51 fibonacci numbers

[@ezhilan1]

awesome logic sir.Great

[@viveksonkar3033]

import math
total = 0
P_num = int(input("Enter the value"))
for i in range(1,P_num + 1):
remainder = P_num % i
if remainder == 0:
total = total + 1
if total == 2:
print(f"{P_num} is prime Number")
else:
print (f"{P_num} is not Prime number")
Thank you so much Teluskon

[@khairahammed5187]

This is the only channel which made me satisfied :) Thanks dude

[@FactsDiscoveryIND]

availableCandy = 20
numberCandy =int(input("How many candies you want"))
#i =1
#while iavailableCandy:
print("sorry!out of Stock")
break
print("Candy")
i=i+1


print("Bye!Have a good Day")

[@abusaeedansari7231]

x = int(input("Enter the Number : "))
# To find the given number is prime for not
z = 2
for i in range(1, x):
if x % z == 0:
if x == z:
print(z, " Is a prime number..")
else:
print(x, " is not a prime number...")
break
else:
z += 1
#Finally done

[@cv5033]

But 4 also gives 0 remainder but it is not prime

[@prabhatranjan1078]

@@cv5033 Then it will print not prime

[@sumant5588]

this code fails for input 1.

[@linuso77]

@@sumant5588 aap batao 1 prime ya not prime .....1 ko consider nhi karte ...i want to just add command for 1 input from user it will show invalid or u can show any thing u want to

[@J.S.W0822]

n=int(input ("enter the any number"))
i=1
List=[]
for i in range (1,n+1):
if (n%i==0):
List.append (i)
print (List)
if len(List)

[@shantiratha6276]

You are the best teacher of python on this planet 🌍🌍🌍

[@sandeepraghuvir]

2:52
x = int(input(" How many Candies you want :"))
i = 1
if x

[@ayushjim3000]

nice

[@nagapranithasamudrala2224]

first=0
second=1
print(first)
print(second)
for i in range(0,48):
next=first+second
print(next)
first=second
second=next

[@tanzimulayaantanaf8969]

0 is not included in a fibonacci series

[@sombithsen177]

Ass 2:
i=int(input('Enter a number: '))
n=2
while n

[@Staab0]

a = 10007
b = a
if a==1:
print(a, "Is not prime")
while b > 2:
b -= 1
if a%b==0:
print(a, "is divisible by", b, ",", a, "is not prime")
break
if b==2:
print(a, "Is a prime")

[@arunavsen2234]

brilliant

[@tejas1674]

print("WE HAVE 10 CANDY ONLY")
a=10
x=int(input("Enter the number of candy?"))
i=1
while ia:
print("Out of stock")
break
print("candy")
i +=1
print("Thank you for visiting")

[@alirezafahama9299]

a,b=0,1
for i in range(0,51,1):
print(a,end=' ')
a,b=b,a+b

[@peacefullmusic8374]

is it correct?

[@Rajadahana]

This is how I understood the three concepts.
break - terminates the loop, or comes out of the loop
continue - goes to the start of the loop
pass - as the word suggests, goes to the next step in the loop

[@nshul16]

Sir I am Agrim of class 8 and I want to learn python because I like coding and programming (as you say programming is so fun😉)and I am learning by your videos. Thank you a lot sir and please keep guiding us.

[@easydatascience2508]

You can check mine too. The detailed Python playlist provides all the tuturials, and source files.

[@ML.ArtificialIntelligence]

x=int(input("enter a number"))
i=2
while i

[@maisharubaiat5012]

Hello. My question is couldn't we use continue for the code you've written for pass and vice versa? Isn't the logic same for both continue and pass?

[@harishharidas8504]

Even i was thinking the same :
Got an Anwser ... "Continue forces the loop to start at the next iteration while pass means "there is no code to execute here" and will continue through the remainder or the loop body.
Continue will jump back to the top of the loop. pass will continue processing.."

[@kirubhaharkannan5461]

Diff b/w Continue and Pass:
Continue skip the loop , will not executes the below statements and goes to top of loop, where pass executes the remaining logic. Example below.
Continue :
for i in range(11):
if (i%2==0):
continue
print( i , " is odd")
----------------------------------------
1 is odd
3 is odd
5 is odd
7 is odd
9 is odd
Pass :
for i in range(11):
if (i%2==0):
pass
print( i , " is an number")
---------------------------------------------
0 is an number
1 is an number
2 is an number
3 is an number
4 is an number
5 is an number
6 is an number
7 is an number
8 is an number
9 is an number
10 is an number

[@shivanshpandey7239]

FIBONACCI SERIES:
a,b=0,1
while a

[@adityajaiswal2891]

Thanks sir, I'm from Mechanical background and just joined Infosys..... Ur videos are helping me alot in my training period. 🙏🏼

[@abpkl609]

QUIZ ANSWER :
1.
fib1=0
fib2=1
for i in range(0,50):
if i

[@touristknud5434]

Great course! The answer beneath looks correct to find out if a number is prime.
x=int(input("is this number prime?"))
for i in range (2,x):
if x%i==0:
print (x, " is not prime")
break
else :
print (x, "is prime")
break

[@radmonk8843]

a dude can u explain me the logic plz

[@lokeshsharma4363]

this will throw an error for values like 9

[@DonaldOkonkwo-n5e]

No output would be visible if for a number like 2

[@Sumanth30796]

fibonacci series
a=0
b=1
print(a)
print(b)
for i in range(0,10):
c=a+b
print(c)
a=b
b=c

[@Sagarnamaa]

Fib:
x=0
y=1
for i in range(0,50):
print(x," ", end="")
next=x+y
x=y
y=next

[@adarshsahani1947]

well but 0 is not first in series

[@Sagarnamaa]

@@Svcollections941 crt ?

[@jhz5071]

Candy program using for loop:
available = 5
x = int(input('How many candies you want? '))
for i in range(1, x + 1):
if i > available:
print('Out of stock!')
break
else:
print(i, 'candy!!')

[@jhz5071]

@Capt. John Price Where I missed that? I don't think we need i==1 anywhere in this program?

[@jhz5071]

@Capt. John Price You mean I should initialize it first? As per my understanding, i is an iterator here and range function gives it an initial value as well which is 1 in this case because I have mentioned it, otherwise it'd have been 0.
Please correct me if I am wrong.

[@hrpasisia3033]

1. Print first 50 fibonacci numbers
lim = 50
count = 0
n1 = 0
n2 = 1
while count < lim:
print(n1)
last_number = n1 + n2
n1 = n2
n2 = last_number
count += 1
2. Check a given number is prime or not
num = int(input("Enter Number : "))
if(num==2):
print('Prime')
else:
for i in range(2,num):
if num % i == 0:
print("Not prime")
break
else:
print("Prime")

[@tejasteja6653]

# for prime number
x=int(input("enter the no."))
b=False
if x==1 or x==2:
print("prime number")
elif x==0:
print('zero')
else:
for i in range(2,x):
if x%i==0:
b=True
if b:
print('not prime')
else:
print('prime')

[@Sagarnamaa]

Prime Number:
x = int(input("Enter Number"))
if x==0 or x==1:
print("NP")
else:
i=2
while i

[@prithvirajmaity4600]

easiest solution for fibonacci
x,y=0,1
while y

[@paharididi6501]

Cool bro

[@prithvirajmaity4600]

@ENTERTAINMENT WORLD i ran the loop till 50, it will run fibonacci numbers till 50

[@sandeepsahu8743]

avg=20
x=int(input("ENter number of candies you want:"))
i=1
while iavg:
print("SOrry! we only have" + " " + str(avg) + " " + "candies left")
break
print("candy")
i+=1

[@talhaordukaya2204]

For the first one:
a = 1
b = 1
for i in range(50):
print(a)
print(b)
a = a + b
b = b + a

[@lalithkumar4794]

niceee

[@YashhC]

Epic. But this code prints 100 Fibonacci numbers because we print a and b both till i=50. so use range(25).
IDK how to do it with odd numbers like 51 because we can't take 25(50 nos), 26(52 nos) and 25.5 is not a thing.

[@talhaordukaya2204]

@@YashhC Yes, you are right. Here is the code. It works exactly like you want. I arranged for you :)
a, b = 1, 1
print(a)
for i in range(49):
print(b)
b, a = a + b, b

[@YashhC]

@@talhaordukaya2204 Yes that makes more sense! This can do any amt of numbers ^^

[@kr.vinay4669]

Please replace a= 0 to start sequence with 0

[@hallo-xp2wh]

first one answer
c=0
i=1
print(c+1)
while i

[@DeshDeepak08]

num = int(input("enter number of digits you want in series (minimum 2): "))

first = 0
second = 1

print("
fibonacci series is:")
print(first, ",", second, end=", ")

for i in range(2, num):
next = first + second
print(next, end=", ")

first = second
second = next

[@HighVibez01]

Just started learning.. converted to for loop
x=int(input("enter the value"))
for i in range(0,x):
if x>av:
print('out of stock')
break
print("candy")

[@yashm05]

x = int(input("how many candies you want?"))
if x

[@adarshsahani1947]

still print 10 candies but the avialble candy is 5

[@Hydgodharollu]

in else statement print('
candies'*5) instead of print('
candies'*x) or first take available=5, then print('
candies'*available)
x = int(input("how many candies you want?"))
available=10
if x

[@kashifrahman8819]

a=list(range(1,51))
a[0]=0
a[1]=1
i=2
while i

[@gianluigi5828]

This video is awesome. I understood everything thanks a lot

[@zakiasmaa6834]

Teaching is an art. thank youuuuuuuuuuu

[@sanjag]

This has been so incredibly helpful. Thank you!!!

[@kirubhaharkannan5461]

Diff b/w Continue and Pass:
Continue skip the loop , will not executes the below statements and goes to top of loop, where pass executes the remaining logic. Example below.
Continue :
for i in range(11):
if (i%2==0):
continue
print( i , " is odd")
----------------------------------------
1 is odd
3 is odd
5 is odd
7 is odd
9 is odd
Pass :
for i in range(11):
if (i%2==0):
pass
print( i , " is an number")
---------------------------------------------
0 is an number
1 is an number
2 is an number
3 is an number
4 is an number
5 is an number
6 is an number
7 is an number
8 is an number
9 is an number
10 is an number

[@riaz_ay]

Prime no checking:
x=int(input("enter no:")
for i in range(2,x,1):
If x%i==0:
print("no not prime")
break
else:
print("no is prime")

[@anandhisiva93]

Its not working for x=1

[@anandhisiva93]

x=int(input("Enter an ineger: "))
if x>1:
for i in range(2,x):
if (x%i == 0):
print("Its not a prime number")
break
else:
print("Its a Prime number")
else:
print("Its not a prime number")

[@angelo90th]

@@anandhisiva93 1 is not a prime number

[@neerajbaishya781]

This doesn't work for 15

[@webbrain19]

fib50 = [0, 1]
for i in range(2, 50):
fib_next = fib50[-1] + fib50[-2]
fib50.append(fib_next)
print(fib50)

[@harshalyeole7008]

Hello Navin, I am basically Mechanical Design Engineer having 6+Years of experience. I am learing python from your videos on youtube. Your concept explanation is fantastic. How i can download practice examples?

[@vernanonix]

And one last pass at the prime number question because I'm having fun with this one in particular. Readded the upper variable to cut down on operations while only storing one more variable. Added checks for anything less than 2. I had fun with this one.
x=int(input("For what integer would you like to check primeness? "))
from math import sqrt
if x

[@satwikdua]

how about this?
x = int(input("give a number"))
i = 2
while i

[@harshvora1922]

Number is prime or not:
x = int(input("Enter a number: "))
i = 2
while i

[@janandanyoganadan616]

superb

[@janandanyoganadan616]

but does not work for negative nubers

[@vernanonix]

For prime numbers:
x=int(input("For what number would you like to check primeness? "))
factor=2
upper=x
while factorupper:
print(x,"is a prime number.")
The point of the upper variable is to limit the number of actual operations needed to check. I'm checking one by one going up a list. But I know for a fact that once the numbers are dividing by are bigger than their results, it's a pointless task. So I'm basically constantly updating my upper bound for what I can check. Granted, I could also just set the while loop to only work when factor is less than x/factor, which does save memory. But I got way too much pleasure figuring out this method.

[@vernanonix]

@Papa Bear Your logic is fine, but you end up checking a lot of unnecessary numbers when in reality, if you find a factor n such that 1

[@harithareddy1731]

Really great effort Sir..It was really amazing ..!

[@purveshxd]

Everyone explains about the loop but sir you explained the workflow of loop and that's the best. Thank you so much for this course
I just started now 😊

[@chaparalasrinivasrao7503]

Hi,
Your python videos are very useful.
Can you guide me how to improve my program skills because I don't have any programming knowledge before.

[@BensLab]

I like your delivery style. For some reason Indian people present this stuff better for me. Thanks for the concise explanation.

[@vinaybojjalwar]

For 50 fibonacci series
First=0
Second=1
Temp=0
For i in range(49)
Print(temp)
First=second
Second=temp
Temp=first+second

[@ashish7750]

0
1
2
3
5
8
13
21
output is not the correct Fibonacci series.

[@bhajanmandlimumbai]

though the logic is correct

[@ankursahu4731]

x = [0,1]
for i in range(0,50,1):
if (i

[@ManishSharma-lt6ig]

a=0
b=1
c=1
print(a,end=' ')
print(b,end=' ')
while c

[@kibreabhaileselassie5136]

When you will start with "Machine Learning"?pls

[@anindian4601]

Not only machine learning we want Artificial Intelligence TOO.

[@ProgFaiz]

import math as m
n = int(input("Enter number 'n': "))
i = 2
while i 1 and i > m.sqrt(n):
print("Prime")

[@samarthsaxena3998]

#Check the number is prime or not
num = int(input("Enter no"))
for i in range(2,num):
if num % i == 0:
print("Not prime")
break
else:
print("Prime")

[@urvi.sharma]

1) First 50 Fibonacci Numbers
x = [0,1]
for i in range(1,50):
y = x[-1]+x[-2]
x.append(y)
print(x)
2)
import math as m
x = int(input("Enter a number"))
if x == 1:
print("Neither")
else:
for i in range(2,int(m.sqrt(x))+1):
if x % i == 0:
print(x, "is not Prime")
break
else:
print(x, " is Prime")

[@smitparthe2341]

its (1,51) because 50 gets excluded

[@madhavmishra6937]

Hi Navin,
First of all kudos on your wonderful work!
I have a doubt here regarding the difference b/w "pass" & "continue".
Even if we look at the example in this video....even if we had used "continue" instead if "pass", odd numbers could have got printed.
So, my doubt is that if both the keywords (pass & continue) are asking to ignore the remaining code of the loop 'for that iteration', then what is exactly different about them??
Thanks in advance!

[@madhavmishra6937]

Thanks...that cleared the air considerably....

[@vedhakrishnapanchami2026]

if we use continue it completely skips the whole process and proceeds for the next iteration in the for loop but whereas
pass gets exit from that particular block and execute the remaining block

[@vedhakrishnapanchami2026]

like wise in the given code , pass goes to else block and if we use continue it doesnt go to else block

[@AcuitSrishaGr]

q1:
a=1
b=2
print(a,b,end=" ")
for i in range(3,51):
c=a+b
print(c, end=" ")
a=b
b=c
q2:
num=int(input("enter your number to check: "))
for i in range(2,num):
if num%i==0:
print("not a prime")
break
else:
print("is a prime")

here is mine:)

[@srikrithibharadwaj6779]

Hi Sir, all your sessions are awesome 👏 Thanku so much🙏🏻 I’ve a question.. can’t we use continue instead of pass statement ?

[@abharani7283]

I have also the same doubt as both works in A same way 😳

[@srikrithibharadwaj6779]

Yup

[@tanzimulayaantanaf8969]

no, you can't use. Those are two different thing. Try to use debug to see what's the difference.

[@IndianForestService-1]

First 50 fibonacci numbers
##
C=int(input("Enter the value of c:"))
If c>0:
i=1
a=0
While i

[@subhayansinha4417]

Amazingly explained! Thank you sir!

[@narapareddy4998]

x= int(input("how many candies do u want"))
while x81:
print("candies aren't available")

[@sufiyanmogal1527]

# 2nd assignment Prime Number Finder
num = int(input('enter a number
'))
prime = True
for i in range(2,num):
if(num%i==0):
prime = False
break
if prime:
print("This Number is prime")
else:
print("This Number is not prime")

[@BhuveshDhiman]

i=1
a=0
b=1
print(a)
print(b)
while i