The backwards convoluted hieroglyphic nonsense my professor was confounding us with makes your beautiful explanation even more beautiful, divine even. Thank you sir.
Jesus this is pretty much the absolute definitive bode plot video on TH-cam. I was about to go insane trying to figure out how to do this with the hundreds of damn pages of incomprehensible theory on this when it can just be explained this simply LOL. That's the downside of learning control theory or any engineering discipline in general. Trying to find the no-BS guides on how to do things instead of wasting time through notes of everything being broken down into incomprehensible theory salad.
I'm glad you found it helpful. I like to live by the motto " If you can't explain it simply, then you don't know it well enough". It's nice to know you found this simple and good to learn from. Cheers! ~Andrew
why did you guys stop posting this kind of videos?. This helped me a lot. Keep doing the good work, please. It's a great way to teach with a big transparent board and inverting the video afterwards, genius.
It is the night before my microelectronics exam and I was stressing because I couldn't figure out how to do one of these (bode plots are the main focus of the exam). This video gave me hope, and the confidence to say I know what I'm doing. Thank you so much.
Zeros are positive increase homie, so that's why your first breakpoint for magnitude is an increasing slope as opposed to a pole. Great video other than that error.
Every video out there only discusses the individual components, constant gains, pole/zeros at zero, real, and complex. While they are fundamental to understanding what is happening. Your video is the only one that shows how to draw a complete bode plot from a transfer function. Thank you. Awesome job. Specifically, your break down of drawing the phase shift plot. Great job.
I'm trying to understand how we get a negative from changing 1/200 to 200, if anyone can help me with that, at 4:10 EDIT: All good! I reviewed the log rules, and it makes sense now. For anyone wondering: 1/200 equals 200^-1, and exponents (in this case, the value of -1) can be pulled out of logs. This was a very helpful video, wish my prof explained it like that! Thanks.
Is there a difference between the analod discovery packags offered from diligent? What package should I get to perform these tests? Awesome video btw. Much more informative than the rest on this subject.
hi dude i think in phase plotting u should shift it to -180 in order to the negative singe in the gain pls correct me if i am wrong i have final exam in the next week :)
I know neg and pos frequencies are the same because of the way it wraps around the the unit circle but I lack an intuitive understanding. I couldn’t explain it to someone else and that’s my test of understanding. Any hints?
You never graph the origin on these plots anyway, because it is a logarithmic scale. The origin of zero frequency would be infinitely far to the left. The de-facto "origin" on a Bode plot, is the frequency of 1 Hz or 1 rad/s, whichever units you use. A pole at the actual origin would start with a downward sloping line at -20 dB/decade, until other poles or zeros apply. You'd find your starting point by evaluating the magnitude of the transfer function at unit frequency, and mark that as your vertical axis intercept.
If the poles and zeros are (s - p) or (s - z), which are positive poles and zeros, then the magnitude plot would be the same as if they were negative poles and zeros. But the phase would be reversed. This means positive poles would add phase, and positive zeros would subtract phase. Unlike how they normally do it, with negative (s + p) poles subtracting phase, and negative (s + z) zeros adding phase. Normally in control systems, you want negative roots, for a stable system.
Hope to God somebody replies here: how do you introduce a regulator to cancel/decrease/ compensate for steady state error. Like does anybody know of a vid, or book on it.
The y-axis is the phase in degrees, while the x-axis is the frequency in decades. The slope = rise/run = (y2-y1)/(x2-x1). Therefore, a slope of -90 degrees per decade means that the phase must drop 90 degrees WITHIN 1 decade, not instantly.
8 years later and you're still saving lives, much appreciated.
It's my pleasure
This is by far the best bode plot video, at least that I could find. Thank you!
True
It always blows my mind how my profs can make something thats actually so simple seem so complicated. Thank you so much man 🙏
This was poetry compared to what my Professor tried to teach us lol
agreed
I watched these videos back when I was going through undergrad and back again because I have to take my FE.
Thanks again!
The backwards convoluted hieroglyphic nonsense my professor was confounding us with makes your beautiful explanation even more beautiful, divine even. Thank you sir.
The best explanation, very practical and easy to remember.
At 6:24 he means "zero" for w=+10
Here from uva, you guys are awesome, not only are you helping the students at uconn, you're helping students across the country as well. Keep it up.
Fuck UVA, go Hokies
absolute legend, I finally found someone that can explain bode plots so clearly big up my man
I had been struggling to understand the bode plot but your explanation made it so easy. This was very helpful. Thank you.
Jesus this is pretty much the absolute definitive bode plot video on TH-cam. I was about to go insane trying to figure out how to do this with the hundreds of damn pages of incomprehensible theory on this when it can just be explained this simply LOL. That's the downside of learning control theory or any engineering discipline in general. Trying to find the no-BS guides on how to do things instead of wasting time through notes of everything being broken down into incomprehensible theory salad.
I'm glad you found it helpful. I like to live by the motto " If you can't explain it simply, then you don't know it well enough". It's nice to know you found this simple and good to learn from. Cheers!
~Andrew
Not all heroes wear capes. You good sir are a hero.
Your chill nature calmed me down, thank you.
Amazing video! I waited until last minute on my homework and I wouldn't have been able to get it done on time without this video.
That me right now, have assignment due in a few hours haha
I had an assignment due 2 days ago and I'm doing it right now
brother single-handedly saved my mechatronics exam
The best explanation of the bode plot on the internet!!! Thank you very much😁
Much better explanation than every professor out there has to offer.
why did you guys stop posting this kind of videos?. This helped me a lot. Keep doing the good work, please.
It's a great way to teach with a big transparent board and inverting the video afterwards, genius.
It is the night before my microelectronics exam and I was stressing because I couldn't figure out how to do one of these (bode plots are the main focus of the exam). This video gave me hope, and the confidence to say I know what I'm doing. Thank you so much.
Damn this is the best video out there
This dude is amazing ,the explanation is so vivid and simple.I want to be his friend .
So concise, definitely beat the "you should remember this from 2nd year" our prof gave
Zeros are positive increase homie, so that's why your first breakpoint for magnitude is an increasing slope as opposed to a pole. Great video other than that error.
Perfect example, perfect explanation: straight to the point
i think this is one of the best explanations of bode plots
god bless u brother, underrated channel
only explanation i understood
Every video out there only discusses the individual components, constant gains, pole/zeros at zero, real, and complex. While they are fundamental to understanding what is happening. Your video is the only one that shows how to draw a complete bode plot from a transfer function. Thank you. Awesome job. Specifically, your break down of drawing the phase shift plot. Great job.
This literally changed my life
This is awesome, simple and straightforward!
the best bode plot tutorial in youtube
You sir are a gentleman and scholar !! thank you !!
Man Iam not Native speaker and either good student but you explain so good that even I understand the concept
Thanks a lot ❤️
This was absolutely perfect. Helped me finally understand Bode Diagrams. 13/10
Great explanation. Complex made simple. Well done!
I'm trying to understand how we get a negative from changing 1/200 to 200, if anyone can help me with that, at 4:10
EDIT: All good! I reviewed the log rules, and it makes sense now. For anyone wondering: 1/200 equals 200^-1, and exponents (in this case, the value of -1) can be pulled out of logs.
This was a very helpful video, wish my prof explained it like that! Thanks.
Absolutely incredible explanation. This is the best out there. Thanks!
Dude, right off the bat, you are amazing for writing backwards like that for your students. Love those paint boards.
lol they just flip the video... much easier and smarter dont you think?
@@TheMatias2 fucking genius!
best bode plot video i’ve seen
Best Bode Plot video, thank you!
you sir are amazing!! you explained it is such a simple way!!! thank you!
best bode plot vid i found, sending it to the class groupme lol
Is this dude writing backwards.
In a mirror I am! - Andrew
u are awesome ! every thing is so easy now thanks
Thanks pal, very helpful 👍
I LOVE YOU YOU ARE THE MAN BEST BODE PLOT VIDEO EVER
GOD SENT YOU AS A GIFT TO US
This guys the GOAT
Is there a difference between the analod discovery packags offered from diligent? What package should I get to perform these tests?
Awesome video btw.
Much more informative than the rest on this subject.
call me mega mind cuz my brain just got bigger. thank u so much!
Whenever you encounter a pole or a zero, your slope changes by 20dB/dec
Extremely helpful! Thank you so much!
Really good video. thank you . One thing 6.23 its a zero not a pole .... (Zeros/Poles).
If you have a zero at the origin, what would the plots look like?
A zero at the origin means the left-most slope is +20 dB per decade.
how did you know it started out at 0 degrees before 10^0 for the phase plot (at 10:50) ?
The phase plot begins at 0 and remains 0 till you reach the range of the first breaking frequency. That's 1 in this case.
thank you so much, great video
THANK YOU SO MUCH SJSJDJJD finally phase makes sense 🥺❤️
Good job man, thanks a lot. This explanation is awesome.
Keep going ;)
dis lit, bru u make my professer look like str8 trash... u my homie-cron 4eva
How come matlab/octave shows different plots when we write for example (1+s/20)**2 compared to (1+s/20)(1+s/20) in the poles section of the fraction?
Excuse me but can you explain how the zeros are positive. (s+10=0. So s=-10)
+1
Thank you so much, I think this will help a ot with my exam.
bro i fucking love you
Excellent, so much easier than Nisa book!!!
Didn’t get the phase part!
hi dude i think in phase plotting u should shift it to -180 in order to the negative singe in the gain pls correct me if i am wrong i have final exam in the next week :)
Thank you man you really good teacher
Thank you sir for this awesome video
thank you so much! the video is great and clear!
This was so helpful! Thank you!
clear explanation! Thanks for sharing!
I know neg and pos frequencies are the same because of the way it wraps around the the unit circle but I lack an intuitive understanding. I couldn’t explain it to someone else and that’s my test of understanding. Any hints?
I plotted this on Matlab and I got the same gain, but very different phase. :o
Yes, there is a big difference between the asymptotic and real plot in this case, check out my comment and the comments to it :)
You rock Andrew
Thanks for the great video. But what if the system has a pole at the origin?
You never graph the origin on these plots anyway, because it is a logarithmic scale. The origin of zero frequency would be infinitely far to the left.
The de-facto "origin" on a Bode plot, is the frequency of 1 Hz or 1 rad/s, whichever units you use. A pole at the actual origin would start with a downward sloping line at -20 dB/decade, until other poles or zeros apply. You'd find your starting point by evaluating the magnitude of the transfer function at unit frequency, and mark that as your vertical axis intercept.
how you find the range on the phase part?
Thank you sir, but I have a question: in your example all your zeros and poles are (s+...), what is they are (s-....), are the rules still valid?
If the poles and zeros are (s - p) or (s - z), which are positive poles and zeros, then the magnitude plot would be the same as if they were negative poles and zeros. But the phase would be reversed. This means positive poles would add phase, and positive zeros would subtract phase. Unlike how they normally do it, with negative (s + p) poles subtracting phase, and negative (s + z) zeros adding phase.
Normally in control systems, you want negative roots, for a stable system.
he says we go -90deg yet he only slopes the line at about 45deg
yeah because the slope at that time was +45 degrees, so +45 -90 = -45 degrees
U r the best man
Very neat thanks exam today
Ma come sfaccimma ti amo
Can someone pls. explain, why is ist zero after 200 rad/s? Shouldnt it be -20.
Very well done
great explaination but i think it needs a revision cause u might have messed the phase plote
brilliant
I wanted to know what to do in -40log(S/100-1)
Can you please give advice?
excellent
Thanks a lot man.
Actually it is the solution of the problem. I cannot call this an explanation.
This was in English. For some reason professors seem to teach this in Chinese or something.
ok but what is its in the form for example 1-s/1+s, how does the -1 effect it
Gain plot would be the same.
phase plot will be different: +pole will behave as a -very zero and vice versa
How are these vídeos made? do you have a crystal in front of you or something?
Homie OG :D
Hope to God somebody replies here: how do you introduce a regulator to cancel/decrease/ compensate for steady state error. Like does anybody know of a vid, or book on it.
Thank you sir 😁
thanks so much!
Im confused is a dropp of 90 degrees not a line straight down.
The y-axis is the phase in degrees, while the x-axis is the frequency in decades. The slope = rise/run = (y2-y1)/(x2-x1). Therefore, a slope of -90 degrees per decade means that the phase must drop 90 degrees WITHIN 1 decade, not instantly.
Your -45 and -90 slope looks the same.
Great explanation but I think the phase plot is wrong.
What pen you using teacher?
Amazing