The hero we don't deserve, insane output and wish you all the best. Nice to see someone passionate about helping people instead of just stroking their ego
hi! just wanted to drop a comment to say that i love your videos! your production quality is excellent and the work that you put into making this material available freely is really awesome. it's really helpful to see worked answers and get an insight into your method for breaking down questions and i feel much more confident when approaching challenging practice questions after having binged a bunch of your videos 😊 thanks for this awesome content!
I am beyond grateful for all the questions and walkthroughs and crash courses you have put out! They have helped me a lot so thank you so much! I just had a question regarding q7: Was hydrostatic pressure not in (N/m^2) or Pascals, instead of in N? Given how the question also had not specified what the area the pressure is acting on, I did not consider hydrostatic pressure at all for Q7. Thanks again!
Hello Jesse, as a person who’s taking GAMSAT later this year, I extremely appreciate your content and how you explain your approach on tackling s3 questions. Regarding q8 I am a bit stumped on how you calculated the buoyancy force of the vessel (taking account of your errors in the converting tonnes to g rather than kg). Shouldn’t it be 1 x 3.0 x 10^7 x 10 for the buoyancy force? Cheers
Hey Lachlan, sorry I haven't been able to get to comments in a while. You're absolutely right about Q8 and weirdly, I must've just never updated the video link on the Notion page with the re-upload that I did back then haha. It's been sitting on YT with barely any views haha You can see it here and you'll notice that I have corrected the calculation in Q8 to having V = 3 x 10^7 th-cam.com/video/4Eq96PiPcLM/w-d-xo.html Thanks for checking this with me!
Hey Jesse, really enjoying your videos they've been a fantastic help with study. I'm just a bit confused on question 6. Would 2.5 tonnes not be equal to 2500kg and therefore 2.5 x 10^3 instead? Also when "weight" is mentioned in the GAMSAT should we assume that it may be equal to mass rather than strictly being mass x gravity, as I did Question 6 as Fb = Weight of object(mass x gravity). => 2.5 x 10^3 = - (1)(10)(V). Thanks again for the content!
Haha oops! Yep, looks like I went into chemistry autopilot and converted tonnes to grams! 🤦♂️ I'll do a reshoot of these questions to fix this because they demonstrate a few important points. Thanks for pointing this out And yep always assume weight is a weight force measured in newtons unless the question specifically defines mass as being measured in kg or some other unit of mass. From what I've seen though, ACER are pretty consistent in using the word 'mass' in the bio focused questions to avoid this confusion
@@megaparajuli4693 Yep this is a standard physics term which refers to the force applied by some mass due to gravity. Mass is constant for any object, regardless of which gravitational field it is in, but weight is the force applied = mg so can vary with varying gravitational fields. Eg. A person whose mass is 60kg will have a mass of 60kg on the moon (g = 1.6) and the same mass of 60kg on Earth (g = 9.8) but the same person will be said to be 'lighter' on the moon in that their 'weight' will be less than on Earth due to gravity (60*1.6 < 60*9.8). It's worth practising making the distinction between the use of mass and weight in everyday use as outside of science, casual speaking often treats mass and weight as equal, incorrectly.
Hi Jesse, so if I'm understanding it correctly for question 8 buoyancy force is the force required to keep the vessel afloat in a liquid (pgV) and hydrostatic force is the force of a liquid acting on a vessel (pgh)? In that case would the hydrostatic force be acting in all directions on the vessel and each direction would be 400N? But adding up all the 400Ns would still be an insignificant number so you left it out. And thanks so much for the plethora of super helpful content!
Q7: Surprising followed along and understood everything except for the end ... What is meant by 3X10^10 - 2.5X10^6, because of orders of magnitude, the subtraction is irrelevant? I would have attempted calculating that.... but also not to sure how given the bases are different!
Hey Jesse I love your content. For question 9 I think your reasoning for the fourth patient may have gotten mixed up. If the aim was to Prevent blood clots and we did want faster moving blood then wouldn't we want a higher blood pressure? This would be wanting more Angiotensin II. Whereas the question asks who could we treat with ACE Inhibitors which cancels out Angiotensin II, lowering BP. Thanks!
Hey Asher, good catch! Yep, I must've just jumbled ACE inhibitor with Angiotensin in my head on this question and been thinking about treating with Angiotensin.
In question 2 when cancelling out the natural log 2 on both sides of the equation: I am confused as to why it becomes 1 over lambda z instead of just lambda z = Vd / C Thanks again to Jesse the peoples champ
Hey Luke, yeah so the reason for this is because the lambda z is still in the denominator so we cannot cancel out the ln(2) and express the fraction as lambda z but instead have to retain a '1' as a placeholder. We are only really dividing the numerators by ln(2) so on top ln(2)/ln(2) = 1 but the lambda underneath is unaffected If you weren't sure about something similar and needed to test this idea on the fly, you could check it by writing out a simple fractional equation like 2/3 = (2 x 6)/18 If you divide both sides by 2 and cancel it out it should be 1/3 = 6/18 rather than 3 = 6/18
Hi Jesse, thanks for your video! I'm a bit confused by question 4, can we assume T1/4=2*T1/2 here ? it's only valid for first order reaction, right? if it's a second order, or zero order, the relationship between T1/2 and T1/4 would be different.
Just wondering for q5, you said for option III that kidney failure pt needs less frequent dosage interval to achieve steady state. Since all dosage intervals are shown to achieve steady state on the graph, couldn't you conclude that regardless of the dosage interval, the kidney pt will also achieve steady state? reducing dosage interval can be justified on the grounds that in order to be above a certain threshold of plasma concentration, you only need minimal dosage interval. However it seems that steady state is achieved for all intervals.
Remember that Q12 refers to a patient with kidney failure but the graph does not. The kidney failure is an additional change brought in later at Q5 so you cannot rely entirely on the initial graph for justification. A patient with kidney failure would have lower plasma clearance so they would require less frequent dosage for the reasons explained in the video
would the terminal halflife actually be shorter because it happens after the kidney does something to it? It seems the endpoint of the terminal halflife is the same as a normal halflife but it starts after the normal halflife.
It’s certainly possible but there’d be no confirming evidence of this in the graph or the stem info Often the tricks to questions are that some answers are reasonable assumptions but when there is no confirming evidence given they are often lower value than an option that has confirming that evidence. This would be an example that
hey Boss you said 2.5 tons weight instead of mass (in the stem) which was super confusing for me. also I’ve never seen a question like 8 before. i wonder if the force mg would be combined with buoyancy. if we knew area and pressure we could know F=pressure x area also you said that rho x g x h is in newtons (you didn’t use in answer anyway) but i don’t think units are correct.
Hey Ryan! Great catch on the wording of the question. Arguably the unit best implies its use, given physics applies a special distinction between mass and weight whereas general outside use uses mass/weight interchangeably, but this is more of an excuse for my error 😂. I've changed it to 'mass' on the resources page to avoid the confusion Yeah with question 8 I wanted to connect buoyancy to spring constants to bridge the two concepts in a novel way. Yep, absolutely if we either were given the area or if it were a uniform shape like a sphere with known dimensions, we could calculate the area and therefore the force that is applied. Whoops, I must've been jumbling 𝜌gh for pressure with 𝜌gV for force
The hero we don't deserve, insane output and wish you all the best. Nice to see someone passionate about helping people instead of just stroking their ego
Thanks so much! Glad to see it's helping a lot of people :)
hi! just wanted to drop a comment to say that i love your videos! your production quality is excellent and the work that you put into making this material available freely is really awesome. it's really helpful to see worked answers and get an insight into your method for breaking down questions and i feel much more confident when approaching challenging practice questions after having binged a bunch of your videos 😊 thanks for this awesome content!
Thanks for your comment! To have 'bingeworthy' content is genuinely mind boggling to me 😂 but thank you, I really appreciate it
I am beyond grateful for all the questions and walkthroughs and crash courses you have put out! They have helped me a lot so thank you so much! I just had a question regarding q7: Was hydrostatic pressure not in (N/m^2) or Pascals, instead of in N? Given how the question also had not specified what the area the pressure is acting on, I did not consider hydrostatic pressure at all for Q7. Thanks again!
Great to hear! Sorry yes, just a small typo. I must've been thinking pgV in my head and switching over to units of force!
@@jesseosbourne Ohhh okay 👌 thank you!!
Hello Jesse, as a person who’s taking GAMSAT later this year, I extremely appreciate your content and how you explain your approach on tackling s3 questions. Regarding q8 I am a bit stumped on how you calculated the buoyancy force of the vessel (taking account of your errors in the converting tonnes to g rather than kg). Shouldn’t it be 1 x 3.0 x 10^7 x 10 for the buoyancy force? Cheers
Hey Lachlan, sorry I haven't been able to get to comments in a while. You're absolutely right about Q8 and weirdly, I must've just never updated the video link on the Notion page with the re-upload that I did back then haha. It's been sitting on YT with barely any views haha
You can see it here and you'll notice that I have corrected the calculation in Q8 to having V = 3 x 10^7
th-cam.com/video/4Eq96PiPcLM/w-d-xo.html
Thanks for checking this with me!
I’m a bit confused as to why we need the original volume if we need the new density? Won’t be need the new volume ?
Hey Jesse, really enjoying your videos they've been a fantastic help with study. I'm just a bit confused on question 6. Would 2.5 tonnes not be equal to 2500kg and therefore 2.5 x 10^3 instead? Also when "weight" is mentioned in the GAMSAT should we assume that it may be equal to mass rather than strictly being mass x gravity, as I did Question 6 as Fb = Weight of object(mass x gravity). => 2.5 x 10^3 = - (1)(10)(V). Thanks again for the content!
Haha oops! Yep, looks like I went into chemistry autopilot and converted tonnes to grams! 🤦♂️ I'll do a reshoot of these questions to fix this because they demonstrate a few important points. Thanks for pointing this out
And yep always assume weight is a weight force measured in newtons unless the question specifically defines mass as being measured in kg or some other unit of mass. From what I've seen though, ACER are pretty consistent in using the word 'mass' in the bio focused questions to avoid this confusion
@@jesseosbourne hey, so Weight in acer is usually 'mass * gravity' right ?
@@megaparajuli4693 Yep this is a standard physics term which refers to the force applied by some mass due to gravity. Mass is constant for any object, regardless of which gravitational field it is in, but weight is the force applied = mg so can vary with varying gravitational fields.
Eg. A person whose mass is 60kg will have a mass of 60kg on the moon (g = 1.6) and the same mass of 60kg on Earth (g = 9.8) but the same person will be said to be 'lighter' on the moon in that their 'weight' will be less than on Earth due to gravity (60*1.6 < 60*9.8).
It's worth practising making the distinction between the use of mass and weight in everyday use as outside of science, casual speaking often treats mass and weight as equal, incorrectly.
Hi Jesse, so if I'm understanding it correctly for question 8 buoyancy force is the force required to keep the vessel afloat in a liquid (pgV) and hydrostatic force is the force of a liquid acting on a vessel (pgh)? In that case would the hydrostatic force be acting in all directions on the vessel and each direction would be 400N? But adding up all the 400Ns would still be an insignificant number so you left it out.
And thanks so much for the plethora of super helpful content!
Hey pearl, yep exactly right! Well done
Glad it's all helping! :)
Q7: Surprising followed along and understood everything except for the end ... What is meant by 3X10^10 - 2.5X10^6, because of orders of magnitude, the subtraction is irrelevant? I would have attempted calculating that.... but also not to sure how given the bases are different!
Hey Jesse I love your content.
For question 9 I think your reasoning for the fourth patient may have gotten mixed up. If the aim was to Prevent blood clots and we did want faster moving blood then wouldn't we want a higher blood pressure? This would be wanting more Angiotensin II. Whereas the question asks who could we treat with ACE Inhibitors which cancels out Angiotensin II, lowering BP.
Thanks!
Hey Asher, good catch! Yep, I must've just jumbled ACE inhibitor with Angiotensin in my head on this question and been thinking about treating with Angiotensin.
In question 2 when cancelling out the natural log 2 on both sides of the equation: I am confused as to why it becomes 1 over lambda z instead of just lambda z = Vd / C
Thanks again to Jesse the peoples champ
Hey Luke, yeah so the reason for this is because the lambda z is still in the denominator so we cannot cancel out the ln(2) and express the fraction as lambda z but instead have to retain a '1' as a placeholder.
We are only really dividing the numerators by ln(2) so on top ln(2)/ln(2) = 1 but the lambda underneath is unaffected
If you weren't sure about something similar and needed to test this idea on the fly, you could check it by writing out a simple fractional equation like 2/3 = (2 x 6)/18
If you divide both sides by 2 and cancel it out it should be 1/3 = 6/18 rather than 3 = 6/18
Hi Jesse, thanks for your video! I'm a bit confused by question 4, can we assume T1/4=2*T1/2 here ? it's only valid for first order reaction, right? if it's a second order, or zero order, the relationship between T1/2 and T1/4 would be different.
Correct
Just wondering for q5, you said for option III that kidney failure pt needs less frequent dosage interval to achieve steady state. Since all dosage intervals are shown to achieve steady state on the graph, couldn't you conclude that regardless of the dosage interval, the kidney pt will also achieve steady state? reducing dosage interval can be justified on the grounds that in order to be above a certain threshold of plasma concentration, you only need minimal dosage interval. However it seems that steady state is achieved for all intervals.
Remember that Q12 refers to a patient with kidney failure but the graph does not. The kidney failure is an additional change brought in later at Q5 so you cannot rely entirely on the initial graph for justification. A patient with kidney failure would have lower plasma clearance so they would require less frequent dosage for the reasons explained in the video
for Q8 how are you measruing hydrostatic pressure in Newtons? pgh does not give newtons?
Oops sorry, just a small typo. I must've been thinking pgV in my head and switching over to units of force!
would the terminal halflife actually be shorter because it happens after the kidney does something to it? It seems the endpoint of the terminal halflife is the same as a normal halflife but it starts after the normal halflife.
It’s certainly possible but there’d be no confirming evidence of this in the graph or the stem info
Often the tricks to questions are that some answers are reasonable assumptions but when there is no confirming evidence given they are often lower value than an option that has confirming that evidence. This would be an example that
question 6 is soo difficult !!
hey Boss
you said 2.5 tons weight instead of mass (in the stem) which was super confusing for me.
also I’ve never seen a question like 8 before. i wonder if the force mg would be combined with buoyancy. if we knew area and pressure we could know F=pressure x area
also you said that rho x g x h is in newtons (you didn’t use in answer anyway) but i don’t think units are correct.
Hey Ryan! Great catch on the wording of the question. Arguably the unit best implies its use, given physics applies a special distinction between mass and weight whereas general outside use uses mass/weight interchangeably, but this is more of an excuse for my error 😂. I've changed it to 'mass' on the resources page to avoid the confusion
Yeah with question 8 I wanted to connect buoyancy to spring constants to bridge the two concepts in a novel way. Yep, absolutely if we either were given the area or if it were a uniform shape like a sphere with known dimensions, we could calculate the area and therefore the force that is applied.
Whoops, I must've been jumbling 𝜌gh for pressure with 𝜌gV for force
I feel bad pointing out some areas to improve. Your resources are second to none!
Nah all good man! This kinda feedback helps me improve them further :)
isnt 1 tonne 1000kg so 2.5 tonne is 2.5x10^3kg?
I had the same Q
q7 is soo difficult
Haha I definitely put some tricky ones in these haha