Sir, I been following all you classes in TH-cam. But I Can’t able to find any video based on picfxxx. Sir Make a video about picf4xxx block diagram and use of and ports. sir I can’t understand anything from text book. Your teaching is good. You are teaching exactly what is necessary
First of all, thank you for following my content so keenly. I am surprised to read your statement that you did not find any data on PIC18F. I have complete playlist on PIC18F th-cam.com/play/PLEacQ4Oes1V1mQRMswz27qyFKrHCoExbR.html This list has around 60 lectures only on PIC18F features. For block diagrames you should consider to reivew early 10 videos . you will find block diagrams of working register, file register , program memory , bank selection and so on. Furthermore, I have covered PORTS CONFIGURATION, INTERRUPTS, SERIAL PORT COMMUNICATION, FILE SELECT REGISTER. You can also find implementations of various PIC18F projects in this play list th-cam.com/play/PLEacQ4Oes1V1M5dLf_eTJspR_TneNa7SW.html Additionally, you can find instruction set series exclusively on PIC18F th-cam.com/play/PLEacQ4Oes1V2ygQyi-jQKuXNIZQLfc75V.html
in 2nd example shouldnt step size be 17.5mV (4.5/256)? and why are we getting Dout not again as 256 like if we consider all the decimal points of the step size we will be getting 2^8 again ie 256 so why are we not doing that and intentionally getting the error? please I'm a bit confused can you explain?
Dear you are confusing two different steps. Step 1: we estimated step size that's 19mV . Here I have to use the maximum analog voltage that's 5V. So I used it. But you need to remember that thing that analogue signal is varrying signal it will vary from 0 to 5 volts so analogue signal may have any value in this range. Step 2: We estimate the digital value that's Dout. It will be varrying in between 0-255 (00000000-1111111) and they do represent (min voltage 0V- max voltage 5V). So I took an aribtraty value 4.5 V and it and it's not maximum. I hope I made it clear.
Legend
Thank you my friend : )
Sir, I been following all you classes in TH-cam. But I Can’t able to find any video based on picfxxx.
Sir
Make a video about picf4xxx block diagram and use of and ports. sir
I can’t understand anything from text book. Your teaching is good. You are teaching exactly what is necessary
First of all, thank you for following my content so keenly. I am surprised to read your statement that you did not find any data on PIC18F. I have complete playlist on PIC18F th-cam.com/play/PLEacQ4Oes1V1mQRMswz27qyFKrHCoExbR.html
This list has around 60 lectures only on PIC18F features.
For block diagrames you should consider to reivew early 10 videos . you will find block diagrams of working register, file register , program memory , bank selection and so on.
Furthermore, I have covered PORTS CONFIGURATION, INTERRUPTS, SERIAL PORT COMMUNICATION, FILE SELECT REGISTER.
You can also find implementations of various PIC18F projects in this play list
th-cam.com/play/PLEacQ4Oes1V1M5dLf_eTJspR_TneNa7SW.html
Additionally, you can find instruction set series exclusively on PIC18F
th-cam.com/play/PLEacQ4Oes1V2ygQyi-jQKuXNIZQLfc75V.html
Well explained ✅
Thank you sir ji. I am honored if you liked it.
in 2nd example shouldnt step size be 17.5mV (4.5/256)? and why are we getting Dout not again as 256 like if we consider all the decimal points of the step size we will be getting 2^8 again ie 256 so why are we not doing that and intentionally getting the error?
please I'm a bit confused can you explain?
Dear you are confusing two different steps.
Step 1: we estimated step size that's 19mV . Here I have to use the maximum analog voltage that's 5V. So I used it. But you need to remember that thing that analogue signal is varrying signal it will vary from 0 to 5 volts so analogue signal may have any value in this range.
Step 2: We estimate the digital value that's Dout. It will be varrying in between 0-255 (00000000-1111111) and they do represent (min voltage 0V- max voltage 5V). So I took an aribtraty value 4.5 V and it and it's not maximum. I hope I made it clear.
@@LearnOnline1 thank you so much sir