Double for loop Leetcode Problem | Part 17 | DSA in python in telugu | Engineering Animuthyam
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- เผยแพร่เมื่อ 30 ก.ย. 2024
- Free python dsa course in Telugu | Engineering Animuthyam
Free python dsa course in Telugu
Website link:
vigneshreddyjulakanti.in/python
Insta:
Engineering Animuthyam
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#coding #telugu #job #python #telugumemes #trendingreels #btech #college #java #javacoding #iit #pythontutorialtelugu
#nit #jee #eamcet #dsa
please extend the videos to 30 or 40 minutes bro
Anna chinna suggestion oka topic complete ga 1-2 hours one shot videos chesi next problems cheppu anna. 20-30 mins antey kastam avtundi ❤
Bro java dsa ..irojati video ralee inka???
l = [3,2,10]
max_diff = -1 # print if no differences
for i in range(len(l)-1):
if l[i] < l[i+1]:
max_diff = max(max_diff, (l[i+1] - l[i]))
print(f'max difference = {max_diff}')
Name="jahnavi"
Print(name[::-1])
o/p:
Ivanhaj
super teaching bro...
this is my first comment on your videos
name = "surendra"
print(name[::-1])
output:-
ardnerus
Bro java video rale ninati di???
Rendering bro video inko 1-2 hrs lo osthundhi
Ninatnundi konchem health issue so time petalekapoya
@@engineeringanimuthyam ok bruh !! Thanks for the reply and take care guru ❤️
Java video petu macha
machaa java dsa lo eeroju vdeo unavailable vostundiiii
Name="swathi"
Print(name[::-1]
O/p:-
Ihtaws
Bro please do clear video on leetcode 157,158 problems
anna nenu palindrome video lo unna daantlo nvcheppina code try chesa anni crct ga kani "maddama" is not a palindrome ayina result yes ane vastundhi,plz chusi rply iyyi anna,here's the code :
s="maddama"
n=3
prod=n*2
valid = True
for i in range(n):
l=s[i]
r=s[prod-1-i]
if l != r:
valid = False
if valid:
print("yes")
else:
print("no")
o/p: yes
If valid== True :
mama ne motivation tho Dopamine📈
Inka gatiga ekidham mawa dopmine 🔥
Anna please give reply nuvvu dsa ekkada nerchukunnav
Details ga na 4 years oka video chesa bro e channel lone peta chudu.
Nen one source antu ekkada nerchukole
@@engineeringanimuthyam ok anna
Inka enni videos unnai bro
3months daily 1