This dude does everything. Mathematics, General Chemistry, Organic Chemistry, Physics 1 mechanics, Physics 2 electromagnetism, and even modern Physics .
@@alanpeter5527quantum mechanics related . it's like photoelectric effect , Heisenberg uncertainty principle, dual nature of matter and radiation, etc..
I cant put into words how thankful I'am that I have found you! seriously, you explain things more simply and more fun than my professor. God bless you for these videos
Bro, you don't understand how much I've been trying to understand the fringe spacing equation's derivation. This video has helped so much cause I couldn't find any other derivation on any other website/video which I honestly understood. Now it makes sense but the letters I use are slightly different. Appreciate it a lot brother!
Two days away from the test, I couldn't understand from both the teacher and the book for a long time, but now I can thanks to your video. Life saver for so many of us students!!
To be fair this guy probably has the most consistent income to ever exist on youtube even if he stopped doing videos. He gets a new batch of students each year at each level for each video. And roughly the same amount each year
i never see a teacher like u ...... teaching is yours....u have no idea how much i tried to understand this chapter...i just wanna to say keep it up bro..........................
Look at the TH-cam video "Double Slit Experiment" by Todd Grigsby. It uses an interferometer to show that light waves can bounce off another. This applies to the double slit experiment thus the title.
Hey, on question 2, I got the answer as 3.3*10^-11 meters, could there have been a conversion error on your part because I converted all the values into meters via calculator converter.
for the final example, when calculating for d, why are you not dividing by m? I see you are leaving it on the numerator side of the equation when dividing by the remaining left side, but not including it on the denominator.... which would cancel m out entirely... maybe I am missing something.. someone explain pls
A wave is spread across. In a double slit experiment, if the wavefunction representing the electron, hits the slits, shouldn’t that be a measurement and shouldn’t that collapse the wavefunction? Now, you'll say it's not a physical wave, it's a probability wave. But then how does a probability wave split into two after the slits? Then, it should be like, the wave hits the slits, the electron says, dude I'm going through the slits, so don't collapse, but you can split into two and diffract. When does it decide that it's going through the slit?
Thank you sir for this veryy understanding video! But you only teach about the bright fringe and i want to know about dark fringe. Im having problem with determining the m of dark fringe.
Remember how he drew that triangle on the figure first and then erased it? They are equivalent because the angle the light is travelling at, was determined by using the triangle. So thus he drew the triangle, got the angle, erased it and then used the same angle again, as it was determined that they're the same thing
What would happen if the constructive interferencing from 1 set of double slits passed through another set of double slits? Would the universe break because of energy being created?
😂😂😂 it's very likely that's you'd not be able to align the double slits at the exact same spot where the waves are in phase, but if you do... You'll just get another interference pattern where the intensity/amplitude is lesser than the last interference pattern you saw. The highest intensity in an interference pattern is achieved at the centre of the double slits (projected on the screen) but if you plan on using another 'Double' slit, the starting intensity of the light would be less than the original, and hence you'd only get a fainter interference pattern :)
No, because white light is a mixture red, blur, green, ect., which are at different wavelengths. This experiment uses light at just one wavelength. If you use light with different wavelengths, then each wavelength is going to be diffracting at different angles and interfering with each other so you won't get the neat maximum-minimum pattern on the screen
Yes, you can use white light, it will just produce an even cooler looking interference pattern as the different colours will diffract at a different angle, leaving you with something similar to a horizontal looking rainbow
Monochromatic light is preferred because the resulting interference pattern is more sharper when compared to a white light (which is a mixture of other colours). White would give you interference, but not as sharp and distinct as a monochromatic source.
Final Exams and Video Playlists: www.video-tutor.net/
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THE WAY U WORDED IT
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This dude does everything. Mathematics, General Chemistry, Organic Chemistry, Physics 1 mechanics, Physics 2 electromagnetism, and even modern Physics .
wtf modern physics
@@alanpeter5527 physics but new or something
You're hilarious 😂😂😂😂 made my day@@seagull6636
@@alanpeter5527quantum mechanics related . it's like photoelectric effect , Heisenberg uncertainty principle, dual nature of matter and radiation, etc..
@@alanpeter5527 same as regular physics just taught without a chalkboard and books. The use a smart board and e-books.
I cant put into words how thankful I'am that I have found you! seriously, you explain things more simply and more fun than my professor. God bless you for these videos
Nou
this video is the reason Im not drinking before my physics final so thanks homie
Bro, you don't understand how much I've been trying to understand the fringe spacing equation's derivation. This video has helped so much cause I couldn't find any other derivation on any other website/video which I honestly understood. Now it makes sense but the letters I use are slightly different. Appreciate it a lot brother!
Two days away from the test, I couldn't understand from both the teacher and the book for a long time, but now I can thanks to your video. Life saver for so many of us students!!
Such a natural tutor, I can so follow everything- the clearest, most consistent explanations I have found. Thank you SO much :)
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@@ratubgn1237 yup!
To be fair this guy probably has the most consistent income to ever exist on youtube even if he stopped doing videos. He gets a new batch of students each year at each level for each video. And roughly the same amount each year
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i never see a teacher like u ...... teaching is yours....u have no idea how much i tried to understand this chapter...i just wanna to say keep it up bro..........................
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12:45
Multiply 8.5 x 3
Multiply with wavelength
Divide number with 0.5
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why is theta equivalent to theta 1 at 4:00 minutes into the video? I wanted to know why those 2 angles are equivalent. tks
Thank you bro it is cool
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anwer of the third question : 1.76*10^-3 m/1.33 = 1.32*10^-3
right?! that is what i got as well, i am unsure why he isnt dividing by the m (canceling m)
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Look at the TH-cam video "Double Slit Experiment" by Todd Grigsby.
It uses an interferometer to show that light waves can bounce off another.
This applies to the double slit experiment thus the title.
Big Thanks. Btw, my suggestion for the viewers, don't skip question 3.
V good as always....Sir plz also record lecture on Michelson interferometer.
I'm taking a long break from physics.
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for 10:35 instead of using dy(1)=lambda m D you could've just used tan1.5 times 4.5 (make your life easier)
Hey, on question 2, I got the answer as 3.3*10^-11 meters, could there have been a conversion error on your part because I converted all the values into meters via calculator converter.
You make me like physics fr
Is sine-product which is the dark of the pupil sight
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If the distance between the two points is 6cm and the angle of reflection, is 30⁰ what is the wavelength?
who else feels so accomplished after getting the practice problems correct?
ecxactlyy
Thank you!
Thank you!
04:00 why are the angles equal
Some other guy was saying that's the squared magnitude of a complex function. I've seen them rounded, if that's the case.
thx bro
it helps a lot
for the final example, when calculating for d, why are you not dividing by m? I see you are leaving it on the numerator side of the equation when dividing by the remaining left side, but not including it on the denominator.... which would cancel m out entirely... maybe I am missing something.. someone explain pls
A wave is spread across. In a double slit experiment, if the wavefunction representing the electron, hits the slits, shouldn’t that be a measurement and shouldn’t that collapse the wavefunction? Now, you'll say it's not a physical wave, it's a probability wave. But then how does a probability wave split into two after the slits? Then, it should be like, the wave hits the slits, the electron says, dude I'm going through the slits, so don't collapse, but you can split into two and diffract. When does it decide that it's going through the slit?
can you please make a video about thin films.
Thank you sir for this veryy understanding video! But you only teach about the bright fringe and i want to know about dark fringe. Im having problem with determining the m of dark fringe.
for dark fringe, change lambda to lambda/2 in the equations
6:19 You mean in degrees not in radians, sin(theta) is ~theta
No it is radians and not degrees
now i am convinced that you know *everything*
Thank u very very very very very much bro
What mode is your calculator? Mine seems to be not corresponding.
On the last example, why didn't we multiple m=4 on the left side of the equation?
Is it normal to have an average of 17 lessons per subject for finals?
A little high. We have 14
Thank you man
How to consider angle is small?
what about darker sides? do we just add 1/2lamda ?
its more helpful👏
Your awesome!!
very clear
Why did they divide the distance of the two slits by 10^3??
WHY ARE THE TWO ANGLES THE SAME I DONT GET IT HE JUST 3:58 4:00 4:02 ARGH WHY PLS
Remember how he drew that triangle on the figure first and then erased it? They are equivalent because the angle the light is travelling at, was determined by using the triangle. So thus he drew the triangle, got the angle, erased it and then used the same angle again, as it was determined that they're the same thing
What would happen if the constructive interferencing from 1 set of double slits passed through another set of double slits? Would the universe break because of energy being created?
😂😂😂 it's very likely that's you'd not be able to align the double slits at the exact same spot where the waves are in phase, but if you do... You'll just get another interference pattern where the intensity/amplitude is lesser than the last interference pattern you saw.
The highest intensity in an interference pattern is achieved at the centre of the double slits (projected on the screen) but if you plan on using another 'Double' slit, the starting intensity of the light would be less than the original, and hence you'd only get a fainter interference pattern :)
Can we use white light in this expriment ? If yes how ? If not why ?
No, because white light is a mixture red, blur, green, ect., which are at different wavelengths. This experiment uses light at just one wavelength. If you use light with different wavelengths, then each wavelength is going to be diffracting at different angles and interfering with each other so you won't get the neat maximum-minimum pattern on the screen
Yes, you can use white light, it will just produce an even cooler looking interference pattern as the different colours will diffract at a different angle, leaving you with something similar to a horizontal looking rainbow
Monochromatic light is preferred because the resulting interference pattern is more sharper when compared to a white light (which is a mixture of other colours).
White would give you interference, but not as sharp and distinct as a monochromatic source.
I have a question please, why did he divide 2.29*10^-5 by 10^-3
bro i came here to ask the same question i dont understand whyyyyy
@@bakedpiexzigzag1652To convert it to millimeters. You divide by 10^-3 if you want the mm conversion of any value
8:47 getting 2.29 x 10 ^ -7 ???
make sure your calculator is in degrees NOT radian , PEACE ♥
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try this new 2 edge diffraction setup, over 100 nodes can be seen: th-cam.com/video/HFDs85cEiKI/w-d-xo.html
If we are asked to calculate lamda or width fringe of first minima are we going to use m=0
Or m=1
Helppppp
I believe you have to use one of these 2
How the two angles are equal??
Assume that the angle is very small then tan theta =Y/D and sin theta= lamda/d are equal
If not mistaken
Because the interference pattern is symmetric.
I don't understand why we assumed that Θ is close to zero, it's not zero, it's 1.5 degrees which is kind of a large number relatively?
i don't get why the two angles (theta 1) are equivalent. could you help me to prove it please?
thank you
It has to do with the geometry of similar triangles
so helpful!
Hey does anyone know why he multiplied 0.05mm 0.05x10 to the power of -3? I don’t understand that part.
To convert from mm to m
@@umr4h138 Oh I see now thanks.
Could I know the reason triangle’s base line is λ ? Why that length could be λ 😭