Designing a Heat Exchanger Network

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  • เผยแพร่เมื่อ 26 ส.ค. 2024
  • Organized by textbook: learncheme.com/
    Using MER targets and pinch point determined in prior screencast, setup a heat exchanger network with utilities. Made by faculty at the University of Colorado Boulder Department of Chemical and Biological Engineering. Reviewed by faculty from other academic institutions.
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ความคิดเห็น • 113

  • @akosbacso2187
    @akosbacso2187 ปีที่แล้ว +4

    All I need to know for the exam in 5 minutes. You saved for me time, nervousness and a good grade. Thank you... really.

  • @LearnChemE
    @LearnChemE  11 ปีที่แล้ว +5

    Actually, that rule only applies at the pinch. Heat exchange between H2 and C1 do break the convention of Ch>Cc on the cold side but this is okay since the other exchanger is internal to this at the pinch. The minimum approach temperature dTmin is not broken.

    • @alexyong9060
      @alexyong9060 4 ปีที่แล้ว

      what if the dTmin is also broken ?
      does it mean that we cannot apply heat exchanger like you did and there are no solution ?

  • @nihalsonagara
    @nihalsonagara 3 ปีที่แล้ว +3

    My professor took more than 6 lec still no output but from this video..work like a charm

  • @kalyansaivarma842
    @kalyansaivarma842 2 ปีที่แล้ว +6

    Great video 👏 small correction at 8:15 is required cold stream can be heated to 75°C not 35°C

    • @rohanchess8332
      @rohanchess8332 11 หลายเดือนก่อน +1

      No, it 35 deg only, i think you took temperature difference as (t-30) instead of (80-t).

  • @Colino712
    @Colino712 11 ปีที่แล้ว +4

    This is very helpful. As mentioned by another viewer, I would really appreciate a video on the heat loops. Thanks!

  • @malinidasgupta8419
    @malinidasgupta8419 8 ปีที่แล้ว +20

    While evaluating in the cold side, the connection is made between H2 and C1. but the rule specifically says that Ch>=C1. In this case 1!>2. How can one connect these two streams? and what did you exactly mean by crossing over at that point?[8:12]

    • @satchitkulkarni7077
      @satchitkulkarni7077 6 ปีที่แล้ว

      same doubt here

    • @duschty
      @duschty 5 ปีที่แล้ว +7

      For those who are still wandering: If you look at the derivation at 2:50, we say that DeltaT2 corresponds to DeltaTmin. So we know that DeltaT1 needs to be bigger than that hence, c_c has to be smaller than c_h. But at 8:12, DeltaT2 does NOT correspond to DeltaTmin, but is (90-35=55K) and DeltaT1 is (80-30=50K). So if you look at the derivation at 2:50 you would only be allowed to do this transfer if c_c is bigger than c_h even though we are at the cold side of the pinch. So always check if the temperature difference after the transfer is bigger or smaller than before than check if c_c has to be bigger or smaller than c_h according to the two formulas mentioned around 2.50.

  • @philanintuli817
    @philanintuli817 8 ปีที่แล้ว +2

    I've watched both screen casts, this helped a lot. Thank you very much

  • @hannahwilson4022
    @hannahwilson4022 2 ปีที่แล้ว +2

    For the hot pinch, what do you do if the hot energy is greater than the cold? I guess it means the hot has enough energy to cool the hot stream to its target temp, but how does it change the way I draw this? Do I add a utility on the hot stream? do i write the cold stream energy under the circle instead of the hot stream energy?

  • @salimfm1
    @salimfm1 7 ปีที่แล้ว +1

    This is a great material of explanation basics of pinch approach. Very clear and helpful.

  • @bluehat001
    @bluehat001 11 ปีที่แล้ว +4

    Thanks for the educative screen cast. i think the estimated temperature of C1 in the cold side of the pinch should be 90/2 + 30 = 75. Pls check

  • @moneebalbanna
    @moneebalbanna 8 ปีที่แล้ว +1

    Where is the video that follows this about the heat loops to minimise the amount of heat exchangers?

  • @Aziz-rj6xb
    @Aziz-rj6xb 8 ปีที่แล้ว +5

    At 5:10 u said we can't go from 80 to 140 degree celsius for C2 , why ?

  • @srihasvelpuri
    @srihasvelpuri 8 ปีที่แล้ว +6

    In cold side networking you have to remove heat from H1 and add heat to C2 . 90kW Adding to C1 heats it from 30 degrees to 75 degrees. How can you get 35 deg , you are not cooling down the cold stream i suppose, and the remaining 10kW is supplied by H2 making the cold utility 50kW.

    • @mustafak4b
      @mustafak4b 8 ปีที่แล้ว +1

      +Srihas Velpuri
      yeah your right i caught that also, its just a mistake

    • @AC-uv9uc
      @AC-uv9uc 6 ปีที่แล้ว +4

      Yeah, it's 90 = 2 (x - 30), not 90 = 2 (80 - x).

    • @prasenjitghosh218
      @prasenjitghosh218 6 ปีที่แล้ว +2

      Yes if you start from 30 DegC cold water inlet and match C2 with H3 you will get cold water outlet as 75 degree but then there will be a discontinuity in stream temperature at the pinch point which is 80 degC.. So how do you account for the the temperature rise of cold water from 75 deg to 80 deg C. You have to add a hot utility then which is against the rules of pinch analysis as one should not add hot utilities in cold section and vice versa because they in turn increase utility requirements on the other side to maintain energy balance. So one should always start from the pinch temperature. The theory on the web cast is correct. Moreover if you do that you may not be able to utilise 10 kw of C1 to cool H2.

    • @arvindrannagasparan8353
      @arvindrannagasparan8353 5 ปีที่แล้ว +1

      @@mustafak4b Nope, that's not a mistake. He is right. In his case, the 90kW from H1 can heat up C2 completely to 80 celcius only if the starting temperature starts from 35 celcius. That is why he calculated the 35 celcius there. So from 30 celcius to 35 celcius in C2, you will need additional 10kW heat which he took from stream H2. This is why he linked H2 with C2 (In between 30-35 celcius)

  • @slayerz2067
    @slayerz2067 6 ปีที่แล้ว +1

    Is that possible to have multiple pinch point? And how to solve the problem if it has two pinch?

  • @mongand02
    @mongand02 6 ปีที่แล้ว +1

    after all these years i keep coming back

  • @KevinTurabian
    @KevinTurabian 11 ปีที่แล้ว +2

    This is an excellent video, however you make a slight error in your final exchanger. You can't have a heat exchanger going from a hot stream with a lower specific heat to a cold stream with a higher specific heat on the cold side of the pinch.
    Keep up the good work and I can't wait for the heat loop breaking video!

    • @xining3710
      @xining3710 9 หลายเดือนก่อน

      Could you explain a little bit why?

  • @itaufique
    @itaufique 11 ปีที่แล้ว +7

    Hi there.. Was wondering how do you calculate the estimated temperatures at the pinch points; i.e. 90 deg for H1 and H2 as well as 80 deg for C1 and C2?

    • @AMAR-pc6ht
      @AMAR-pc6ht 11 หลายเดือนก่อน

      its actually from the last video, taken reference from that.

  • @eilatanarroyo
    @eilatanarroyo 7 ปีที่แล้ว +1

    Question: Is it possible to use this method with 3 streams to be heated and 3 streams to be cooled?

  • @smilerh
    @smilerh 10 ปีที่แล้ว +2

    how do you determine the minimum heat lost to a heat sink :(

  • @sulinwu6016
    @sulinwu6016 6 ปีที่แล้ว +2

    Hi you mentioned you would post a video of identifying heat loops and minimizing the amount of heat exchangers. Do you know where can I find the video?

  • @YifanLyu-kn5me
    @YifanLyu-kn5me ปีที่แล้ว

    Hi, I just wondering if one temperature change is exactly between the two pinch temperature, how to deal with this situation?

  • @rohitsil123
    @rohitsil123 8 ปีที่แล้ว +3

    Question at around 5:00. Why can't we increase the cold stream from 80 C to 140 C? (@C2) I didn't understand the reasoning behind that :)

    • @LearnChemE
      @LearnChemE  8 ปีที่แล้ว +15

      Great question! So the duty to cool the hot stream from 180 to 90 C is 270kW as shown in the video. This means that it can only take 270kW of out of another stream. However, the duty required to heat the cold stream from 80 to 140 is 300kW. This means that the duty of 270 kW from the hot stream is not enough to completely heat the cold stream.
      Please let me know if I can clear this up any more!

  • @fishmc2729
    @fishmc2729 ปีที่แล้ว

    Well done. Is it possible to calculate a flash with 5 components the same way?

  • @swamchem
    @swamchem 9 ปีที่แล้ว

    Dear Prof,
    I have the following discrepancies in your presentations
    1.In Step 1 procedure, you actually swap the values of H1 and H2 streams.
    1.In HEN Network Formation, You would not be able to connect H2 with C1 because, C of H2 is less than C of C2

    • @LearnChemE
      @LearnChemE  9 ปีที่แล้ว

      Swami Nathan On the hot side, you need to connect ones where C of the cold stream is greater than or equal to the hot stream. As for swapping the values of the H1 and H2 streams, I think you are referring to the previous screencast that is linked to this one. Yes, that is a problem and we hope to correct it soon.

    • @swamchem
      @swamchem 9 ปีที่แล้ว

      LearnChemE Thanks for your reply. I still agree with your comments, But I was referring for cold side section. Please kindly check the second connectivity ie H2 with C1.

  • @zihnigur2449
    @zihnigur2449 2 ปีที่แล้ว

    Hello, if our temps. are between pinch temps., how should we do? For example, pinch temps. are 90C-80C and we have from 120C to 80C in the table. How is it possible?

  • @rohanchess8332
    @rohanchess8332 11 หลายเดือนก่อน

    Such an amaing video, really made my concepts clear , thanks a lot, subscribed!

  • @jen_anjali
    @jen_anjali 3 ปีที่แล้ว

    Can you please tell how can I design a heat exchanger network whose delta T min at the threshold ..like the minimum cold utility requirement is zero..
    There will be no pinch matches right?

  • @LearnChemE
    @LearnChemE  10 ปีที่แล้ว +1

    This screencast has been reviewed by faculty from other academic institutions.

    • @abbeykalio9037
      @abbeykalio9037 8 ปีที่แล้ว +1

      +LearnChemE shouldn't the temperature on the cold side of the pinch be 75 rather than 35? 90=2(x-30) instead of 90=2(80-x)

    • @mattbourge
      @mattbourge 8 ปีที่แล้ว

      +Tu mi You are incorrect. 90kW added to C1 is 80 - (90/2) = 35.

    • @santiagoacosta5027
      @santiagoacosta5027 7 ปีที่แล้ว

      yeah but aren't you actually heating C1from 30 to 75 not cooling it from 80 to 35?

    • @prasenjitghosh218
      @prasenjitghosh218 6 ปีที่แล้ว +1

      Yes if you start from 30 DegC cold water inlet and match C2 with H3 you will get cold water outlet as 75 degree but then there will be a discontinuity in stream temperature at the pinch point which is 80 degC.. So how do you account for the the temperature rise of cold water from 75 deg to 80 deg C. You have to add a hot utility then which is against the rules of pinch analysis as one should not add hot utilities in cold section and vice versa because they in turn increase utility requirements on the other side to maintain energy balance. So one should always start from the pinch temperature. The theory on the web cast is correct. Moreover if you do that you may not be able to utilise 10 kw of C1 to cool H2.

  • @luispimentel9817
    @luispimentel9817 11 ปีที่แล้ว +2

    Thanks a lot! Excellent explanation. Have you done the heat loop video already?

  • @alecbates1554
    @alecbates1554 6 ปีที่แล้ว

    What if there are is only one feasible match for the hot side?

  • @geen13
    @geen13 3 ปีที่แล้ว

    at 8:20 i thought it is a must for Ch >= Cc at the cold site? can anyone explain

  • @annac777
    @annac777 5 ปีที่แล้ว

    Hello, I'm a Chemical Engineering student. I have a question, we are required to design a heat exchanger network based on an already reported process, what I don't really know is if we can only apply this method to the flows of the heat exchangers that we already have, or if we can also include the flows coming from other equipments (like reactors o flash separation devices)

  • @eckertdavid4
    @eckertdavid4 10 ปีที่แล้ว

    Quick Question. On the hot side, can you have a heat exchanger where Ch>Cc but part of the Ch stream has already been cooled by another Cc stream?

  • @gildaenguyen2740
    @gildaenguyen2740 ปีที่แล้ว

    you saved me. Thanks a alot

  • @engvdo5297
    @engvdo5297 4 ปีที่แล้ว

    Sir, why you took ∆T1 as a hot side and ∆T2 as a cold side ?

  • @user-nw6kd5oz5v
    @user-nw6kd5oz5v 6 ปีที่แล้ว

    Where is the next video about the minimisation of heat ex and identify heat loop? I can't find it..
    Thanks for video, it helps me a lot though the exam :)

  • @maximilianwirth6257
    @maximilianwirth6257 ปีที่แล้ว

    how or where do you get the values for c (kw/°C)?

  • @karenemyra
    @karenemyra 10 ปีที่แล้ว

    is the order of the temperature must be from large to small in each stream?

  • @febriyantipuspitasari2393
    @febriyantipuspitasari2393 5 ปีที่แล้ว

    Your video is really helpful for my task, thank you so much❤️

  • @saurabhdeshpande7410
    @saurabhdeshpande7410 7 ปีที่แล้ว +1

    On the cold side of heat exchanger network
    Ch>= Cc
    Then how did you do the last heat exchanger

    • @prasenjitghosh218
      @prasenjitghosh218 6 ปีที่แล้ว

      Yes if you start from 30 DegC cold water inlet and match C2 with H3 you will get cold water outlet as 75 degree but then there will be a discontinuity in stream temperature at the pinch point which is 80 degC.. So how do you account for the the temperature rise of cold water from 75 deg to 80 deg C. You have to add a hot utility then which is against the rules of pinch analysis as one should not add hot utilities in cold section and vice versa because they in turn increase utility requirements on the other side to maintain energy balance. So one should always start from the pinch temperature. The theory on the web cast is correct. Moreover if you do that you may not be able to utilise 10 kw of C1 to cool H2.

  • @tariqtahir1301
    @tariqtahir1301 8 ปีที่แล้ว

    i already watched this video and this helped me alot... but i asked you for the Network Optimization

    • @LearnChemE
      @LearnChemE  8 ปีที่แล้ว

      Unfortunately, optimization of these networks is more of an art than a science, other factors like equipment cost are important to truly optimize a system. At this time we only have to two videos on the the subject of heat intrgration

    • @tariqtahir1301
      @tariqtahir1301 8 ปีที่แล้ว

      ok, thanks alot for your response

  • @satishlukka1454
    @satishlukka1454 6 ปีที่แล้ว

    what if one stream dosent reach pinch temperatures at all?

  • @shuaibbalogun4154
    @shuaibbalogun4154 6 ปีที่แล้ว

    what is the following screencast to this please?

  • @joshhurwitz1732
    @joshhurwitz1732 6 ปีที่แล้ว

    What if you don't get a pinch point?

  • @Dynera.co_official
    @Dynera.co_official 9 ปีที่แล้ว

    How to design HEN away from pinch?

  • @ravenli8688
    @ravenli8688 7 ปีที่แล้ว

    Amazingly helpful. Prof u made my life easier in just 10min

  • @Colino712
    @Colino712 11 ปีที่แล้ว

    I made the same mistake, you need to use the 1kW/deg C not the 2 kW/deg C. Then you can get 80 deg C. The 2 kW/deg C is used to obtain the excess 10 kW.

  • @arinaazyr6347
    @arinaazyr6347 4 ปีที่แล้ว

    Is there any vidoe of stream splitting and loop breaking, i really understand on this video , i hope so there is screencast on what i mention before

    • @ayushsaxena7770
      @ayushsaxena7770 3 ปีที่แล้ว

      Check nptel lec on process integration

  • @mashegoanadoreen6076
    @mashegoanadoreen6076 5 ปีที่แล้ว

    How do are go to previous class

  • @VanillaWiki
    @VanillaWiki 7 ปีที่แล้ว +1

    can u pls upload the screencast showing how 2 minimize heat exchangers like u promised? thx

  • @aminulhakim1524
    @aminulhakim1524 8 ปีที่แล้ว

    Hello! I've a question over here. We know that AspenTech Plus has this utility to execute pinch analysis. Does Aspen works exactly like what u've expained? It's just for making sure of what Aspen does exactly. Thank you :)

    • @salimfm1
      @salimfm1 7 ปีที่แล้ว

      This is made by Aspen Energy Analyzer. This program takes data from simulation and can perform pinch analysis interactively.

  • @rossmcnulty3608
    @rossmcnulty3608 9 ปีที่แล้ว +1

    Did you ever make the video explaining the loops and paths?

    • @LearnChemE
      @LearnChemE  9 ปีที่แล้ว

      I'm very sorry. We still do not have this screencast.

    • @Volymart
      @Volymart 7 ปีที่แล้ว

      LearnChemE Did you already do this? I would be very, very grateful!

  • @swamchem
    @swamchem 9 ปีที่แล้ว

    How do you say that the C1 to H2 is 10 kw, in Cold section. Is the pinch temperature of C2 is changed is from 80 to 35 deg C in Cold Station?...... Then It make sense.
    Kindly share your feedback.

    • @LearnChemE
      @LearnChemE  9 ปีที่แล้ว

      Swami Nathan For the first exchange of that stream, the temperature of the cold stream is lowered from 80 to 35 deg C. The remaining 5 deg C difference is then used to cool the H2 stream to 80 deg C, but a further cooling utility is needed to bring H2 down to 30 deg C. Thank you for your questions.

    • @swamchem
      @swamchem 9 ปีที่แล้ว

      LearnChemE . Do you have any additional videos on Heat exchanger networks (Pinch Technology). If possible can you pass your website so that I can follow it effectively.
      Thanks

  • @meetnagar7822
    @meetnagar7822 4 ปีที่แล้ว

    Nice explained

  • @amjidkhan7370
    @amjidkhan7370 6 ปีที่แล้ว

    thanks a lot for saving my time

  • @mongand02
    @mongand02 6 ปีที่แล้ว

    another great watch!

  • @kierannurmi5488
    @kierannurmi5488 9 ปีที่แล้ว

    Are some videos hidden from channel page? I can't seem to find this video on the video tab of your channel page.

    • @LearnChemE
      @LearnChemE  9 ปีที่แล้ว

      +Kieran Nurmi I'm sorry. We're not intentionally hiding anything. How were you able to locate this one? I found it when I searched on the video section of the LearnChemE TH-cam channel. If you can give me some further information, I'd love to fix this. Thanks!

    • @kierannurmi5488
      @kierannurmi5488 9 ปีที่แล้ว

      I originally found this episode via the search function as I was looking for a tutorial on pinch analysis. The videos that were previously missing are on the list now it seems. Must have been a glitch with youtube. Sorry for any inconvenience this has caused.

    • @LearnChemE
      @LearnChemE  9 ปีที่แล้ว

      +Kieran Nurmi Great. And thanks, we appreciate the input when our site isn't properly functioning, even if it turns out to be a youtube glitch.

  • @Rob18183
    @Rob18183 11 ปีที่แล้ว

    Thanks! Very clear and helpfull

  • @demekedemelie6420
    @demekedemelie6420 3 ปีที่แล้ว

    thank you

  • @siddesh1991
    @siddesh1991 10 ปีที่แล้ว

    How do we find pinch temperature?

    • @LearnChemE
      @LearnChemE  10 ปีที่แล้ว +2

      This video might help explain this...
      th-cam.com/video/7PpysQMD0WE/w-d-xo.html

    • @siddesh1991
      @siddesh1991 10 ปีที่แล้ว

      Thanks!

  • @Sweetiepie4life101
    @Sweetiepie4life101 5 ปีที่แล้ว

    hello has the loops and path video been made?

    • @LearnChemE
      @LearnChemE  5 ปีที่แล้ว

      No, I'm afraid it hasn't yet. Let me move that up on the list. Thanks for asking!

    • @adamschatz8205
      @adamschatz8205 5 ปีที่แล้ว

      @@LearnChemE please make it!

  • @maryar.5636
    @maryar.5636 10 ปีที่แล้ว

    Did you make a video on identifying heat loops? I can't seem to find it on your video list.

    • @LearnChemE
      @LearnChemE  10 ปีที่แล้ว +1

      We should posting that soon this week.

    • @LearnChemE
      @LearnChemE  10 ปีที่แล้ว

      Working on heat loops video

    • @maryar.5636
      @maryar.5636 10 ปีที่แล้ว

      Sweet! This stuff is still confusing me hehe. Thanks for your help!

    • @griffithsqwerty
      @griffithsqwerty 10 ปีที่แล้ว +1

      LearnChemE was the heat loops video ever posted? cant seem to find it, thanks.

    • @LearnChemE
      @LearnChemE  10 ปีที่แล้ว

      Sorry for the delay. Hope to have it up this summer.

  • @sharvilvaidya8857
    @sharvilvaidya8857 8 ปีที่แล้ว

    Links to the heat loop video?

    • @LearnChemE
      @LearnChemE  8 ปีที่แล้ว

      Unfortunately we don't currently have a screencasts regarding heat loops at this time. This is however a topic we are considering.

    • @sharvilvaidya8857
      @sharvilvaidya8857 8 ปีที่แล้ว

      Okay :( any alternative links I really needed some insight into breaking loop and stream splitting methods

    • @LearnChemE
      @LearnChemE  8 ปีที่แล้ว

      Unfortunately this kind of analysis is based a lot more on the intuition of the person doing it than a specific procedure. In general, a heat loop occurs when there is a clear circular connection between multiple heat exchangers. Alternative exchanger configurations can break them, stream splitting, or replacing an exchanger that is part of a loop with one or more utilities. How these loops are broken, or if they are broken at all, typically has a lot to do with the cost of doing or not doing so. I'm not aware of any specific links that offer more detailed guidelines. I hope this is at least somewhat helpful!

  • @shaikhdon4931
    @shaikhdon4931 3 ปีที่แล้ว

    Thks sir

  • @mizanprasiefa
    @mizanprasiefa 3 ปีที่แล้ว

    😍

  • @nurulatfadhly
    @nurulatfadhly 11 ปีที่แล้ว

    thanks a lot for this.. :)

  • @benazrojaws3360
    @benazrojaws3360 3 ปีที่แล้ว

  • @ouzytheoriginal
    @ouzytheoriginal 2 ปีที่แล้ว

    sorry dude but NPTEL makes hands down better videos