EEVacademy #8 - Howland Current Pump

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  • เผยแพร่เมื่อ 30 พ.ย. 2024

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  • @dough9950
    @dough9950 6 ปีที่แล้ว +24

    Thanks, the family is very proud of this circuit...

    • @power-max
      @power-max 5 ปีที่แล้ว +1

      Username checks out. :P

    • @michsol
      @michsol 3 ปีที่แล้ว +1

      damn, why was the username changed though xD

  • @deusimperator7692
    @deusimperator7692 6 ปีที่แล้ว +3

    I used one of these in a design at work recently. I needed a very tightly regulated low current output that was tolerant of wide variations in load, both resistive and inductive. This circuit worked great.

  • @DrFrank-xj9bc
    @DrFrank-xj9bc 6 ปีที่แล้ว +1

    Nice video with good, lucid explanations.
    4 very versatile aspects have to be added:
    1. the current source differential output resistance will become infinite, only if these four 100k have pairwise the same ratio.
    So add a trim pot between 2 of the 100k, wiper into the OpAmps input, to trim the circuit for a precision constant current source, i.e no change of current at varying load resistor .
    2. the circuit operates symmetrically to GND. Trivial, but explicitly to be mentioned, therefore it's a GND related current source. It also can act as AC constant current source, if a constant AC voltage is applied at the input.
    3. The circuit acts as a precise voltage to current transformer, so it's also possible to create a DC + AC current by providing an additional summing input for separate VDC and VAC inputs.
    4. There's a more precise circuit, called modified Howland current source, implementing a 2nd OpAmp, so the common mode voltages at the 1st OpAmp are zero, and the input voltages are related to GND also, that's more convenient for AC / DC voltage sources. Additionally, the small error from the current through the 100k vanishes, AND you can realize the current shunt resistor as a decade switching ladder, so to switch the output current decade wise.

  • @istvan.design
    @istvan.design 6 ปีที่แล้ว +2

    A little bit of feedback: 1. You should start with interesting applications of a circuit, for instance we need an improved Howland pump for either a dc constant current source (boring) or if we need to measure skin impedance (impedance imaging/tomography), we can also control muscles or stimulate nerves very precisely even if the impedance changes. 2. An improved Howland pump is difficult to implement in real life, you usually need to isolate it with a linear optocoupler or an opamp if you want to drive it with an audio signal. 3. You should actually warn people NOT TO breadboard a howland pump because it will most likely oscillate and show this on the scope, the resistors must be 0.1% matched in real life, this is very important, 1% doesn't cut it. The 10nF caps are actually mandatory because they are cheap to add and they eliminate a source of oscillation. 4. You could show how to buffer a howland pump for higher current output or how to bridge higher voltage (many opamps won't cut it in the 25-30V limit for most applications). 4. With infinite resistance or higher resistance than you can afford with the opamp's capability the circuit will oscillate and draw maximum current (even kill the opamp). 5. High voltage opamps are expensive, low voltage opamps are not that useful.

  • @ThyAnon
    @ThyAnon 6 ปีที่แล้ว

    We need more EEV academy

  • @steverobbins4872
    @steverobbins4872 6 ปีที่แล้ว +9

    Nice video. I gave it thumbs-up. But I'd like to offer a few constructive criticisms:
    1. You never showed the original (basic) Howland circuit. In the basic Howland, the load is connected to the non-inverting input of the opamp, NOT the output of the opamp. When you insert an extra resistor between the load and the non-inverting input (like you did) that is the "improved" Howland.
    2. You didn't explain the restriction associated with the improved Howland. The resistors have to conform to certain ratios in order to keep it balanced. This is important for explaining why a second opamp overcomes those restrictions.
    3. You didn't explain the biggest advantage of a Howland: it's output is bipolar (two-quadrant operation).

  • @pocoapoco2
    @pocoapoco2 6 ปีที่แล้ว +1

    I found I was able to further simplify the circuit by replacing the resistor between the voltage source and the non-inverting input and the resistor immediately following the op amp output and replacing them both with wires. An then moving the constant current output from the op amp output to the non-inverting input. changing the value of the resisrtor between the ouput and non-inverting input then determines the current.

  • @1973jdmc
    @1973jdmc 5 ปีที่แล้ว

    Thank you sooo much for this video. I have an exam next week and couldn’t see the woods from the trees- THANK YOU

  • @electronicsNmore
    @electronicsNmore 6 ปีที่แล้ว +6

    He did a great job making this video.

  • @uwezimmermann5427
    @uwezimmermann5427 6 ปีที่แล้ว +11

    good work there! Just a small little comment from teacher to teacher - you should perhaps start with an introduction or a goal, like saying more clearly that this circuit _is_ a constant current source for the current through the lower of the two resistors at the output.

    • @andruloni
      @andruloni 6 ปีที่แล้ว +1

      +1
      It's easier to see the effect if we know what it is

    • @ricardonunes6724
      @ricardonunes6724 6 ปีที่แล้ว +1

      I agree. I also think that you should explain the advantages and disadvantages of the circuit compared to similar ones. I can think of many other constant current circuits.

  • @pinolec
    @pinolec 6 ปีที่แล้ว +16

    Well done Dave. I like it.

  • @6alecapristrudel
    @6alecapristrudel 6 ปีที่แล้ว +18

    This is probably the best explanation of this circuit I've seen so far!
    Can you do more analog stuff like this? Maybe OTAs or impedance converters?

    • @Audio_Simon
      @Audio_Simon 6 ปีที่แล้ว

      More analog please!!

  • @siddacious
    @siddacious 6 ปีที่แล้ว

    Great video for someone like me who is still learning the fundimentals. More like this!

  • @groveh1
    @groveh1 6 ปีที่แล้ว

    Nice! Thanks for introducing me to the Howland current pump!

  • @lezbriddon
    @lezbriddon 6 ปีที่แล้ว

    great vid, i have seen something like this in cheap ebike brushless motor controllers to get a stable 12v for the gate drives, because (apparently) normal voltage regulators dont respond quick enough to input voltage drops, which leads to the 12v dropping, not fully turning on the mosfets, and then them exploding due to internal heating....

  • @jd_flick
    @jd_flick 6 ปีที่แล้ว

    really interesting explanation

  • @joinedupjon
    @joinedupjon 6 ปีที่แล้ว +42

    cheers. Liked the format but I think you should look at ways of zooming up on the circuit you're talking about.

  • @VoidHalo
    @VoidHalo 6 ปีที่แล้ว

    I love CircuitMod. Playing around with it is a HUGE reason why I got into electronics.Of course there are other things that played a fundamental role in me getting into electronics. EEVBlog being another big one. Only just found this series and I love it. I was a bit weary with watching a video not hosted by Dave, but you did a great job. Cheers.

  • @JamesPotts
    @JamesPotts 6 ปีที่แล้ว

    a) I did learn something, and b) that end picture alone is worth a thumbs-up.

  • @Mustakari
    @Mustakari 6 ปีที่แล้ว

    Excellent! I like this style. Clearly explained and the tempo is just right.

  • @deanolium
    @deanolium 6 ปีที่แล้ว +3

    Good video, and quite a clever system. Showing how it's derived is really useful, and a good way to learn.

  • @gregfeneis609
    @gregfeneis609 6 ปีที่แล้ว

    BTW, David, I went to the website for falstad, and just tried rolling the mouse scroll wheel while the mouse cursor is in the black circuit space. It appears that you can easily zoom the circuit this way. I did this on my Win 7-64 laptop with Opera and Chrome browsers. YMMV.

  • @miketel01
    @miketel01 6 ปีที่แล้ว +1

    Awesome VID. Yay David2 is back

  • @teslakovalaborator
    @teslakovalaborator 6 ปีที่แล้ว

    If I get it it we can made something like integrator if we charge cap with current proportional to the V difference and measure the time constant

    • @davidledger5941
      @davidledger5941 6 ปีที่แล้ว

      Yes! you can. It is one way to calculate the value of a capacitor.

  • @athousandprojects
    @athousandprojects 6 ปีที่แล้ว

    Great video - thanks

  • @jmannUSMC
    @jmannUSMC 6 ปีที่แล้ว

    Really like how you teach!

  • @NetworkXIII
    @NetworkXIII 6 ปีที่แล้ว +2

    Good video David, enjoyed it a lot. Op-amps are amazing devices.

  • @irawarnaca8133
    @irawarnaca8133 6 ปีที่แล้ว

    Thanks David, great building block. It would be helpful to see how to leverage this in a circuit. Show us an example please. Thanks again, I really do appreciate your videos, I would like to see more of them.

  • @joopterwijn
    @joopterwijn 6 ปีที่แล้ว +2

    It would be Nice to show it on a board next to the theorie! For instance load a super cap for a flash?

  • @NorbertHarrer
    @NorbertHarrer 6 ปีที่แล้ว

    Good job. Explained very well. Looking forward to more stuff from you, David.

  • @Edson_Staack
    @Edson_Staack 6 ปีที่แล้ว +2

    I laughed with the photo in the end! Unbelievable! :)

  • @final182
    @final182 6 ปีที่แล้ว

    I like this format, I would love to see more of these videos where circuit building blocks are explained

  • @tomwimmenhove4652
    @tomwimmenhove4652 6 ปีที่แล้ว

    Very well explained. Good work.

  • @yced101
    @yced101 6 ปีที่แล้ว

    More of these vids pls :) Just gr8

  • @toniturnwald9890
    @toniturnwald9890 6 ปีที่แล้ว +1

    Thank you, for uploading, from your films I can learn pretty good the electronic stuff. Cheers and bye bye Toni

  • @henrywilloughby6965
    @henrywilloughby6965 6 ปีที่แล้ว

    Love it! I’ve been hoping David would start getting screen time!

  • @philiprogers5772
    @philiprogers5772 6 ปีที่แล้ว +46

    What software are you using?

    • @davidledger5941
      @davidledger5941 6 ปีที่แล้ว +66

      Falstad its an online tool
      www.falstad.com/circuit/circuitjs.html

    • @WacKEDmaN
      @WacKEDmaN 6 ปีที่แล้ว +7

      Thanks David..good little simple tool...that said, ive seen some people make some strange circuits with it, that wouldnt really work in the real world ("free energy")

    • @h0lx
      @h0lx 6 ปีที่แล้ว +8

      I self taught electronics to myself with it. Took a piece of a working schematic and figured how it worked by replicating it there

    • @philiprogers5772
      @philiprogers5772 6 ปีที่แล้ว +7

      What a great bit of software. If only I had this when I was at school, how much further on in electronics would I be by now?

    • @amirs5512
      @amirs5512 6 ปีที่แล้ว +10

      DaveCad 3.0

  • @ПетяТабуреткин-в7т
    @ПетяТабуреткин-в7т 6 ปีที่แล้ว

    Thumbs up for the Falstad simulator.

  • @dentakuweb
    @dentakuweb 6 ปีที่แล้ว

    It would have been nice to know what the final outcome of the circuit is before even starting.
    SO... I did an experiment and connected two LEDs to the output of this circuit (using 5V instead of 1V) AND a separate circuit with just a voltage source, 1k resistor and two LEDs. The one with the simple resistor is dimmer and if I go from 1 to 2 LEDs the current reading goes down and 3 LEDs obviously doesn't even light.
    With the Howland Current Pump I can string a bunch of LEDs together and a COSTANT 5mA keeps flowing through it even with 5 LEDs in series. It starts going down if I add a sixth LED.
    You see, it would have been nice to connect this circuit and see it actually do something useful like lighting LEDs.

  • @GadgetUK164
    @GadgetUK164 6 ปีที่แล้ว

    Great job Dave2 =D

  • @PilotPlater
    @PilotPlater 6 ปีที่แล้ว

    I wonder with the 100k resistors if it's susceptible to noise/interference? I've boj'd together timer circuits with BJTs and capacitors/resistors and to get long enough timer delays you need very high resistances, the BJTs were very sensitive to noise.
    In my case I stacked a couple stages of BJTs because I wanted a binary on/off, so that's probably where the over-sensitivity to noise came from.

  • @ryebis
    @ryebis 6 ปีที่แล้ว +7

    Haha that end shot

  • @MedSou
    @MedSou 6 ปีที่แล้ว +2

    thank you 👍👍👍👍👍

  • @PeregrineBF
    @PeregrineBF 6 ปีที่แล้ว

    Upvoted just for the use of Falstad's circuit sim. Rodrigo Hausen made some improvements (github /hausen/circuit-simulator) which can be handy.

  • @amciaapple1654
    @amciaapple1654 6 ปีที่แล้ว

    @David: Fine video but it begs the comparison with other current sources, such as based on a single JFET and even BJT. Also, application examples would be nice...

  • @EDGARDOUX1701
    @EDGARDOUX1701 6 ปีที่แล้ว

    A very good explanation David! Thanks for sharing and hope to see more on OpAmps. I would loke to see opamps with strain gages, I do have an issue with those. Thanks again

  • @topherteardowns4679
    @topherteardowns4679 6 ปีที่แล้ว

    Awesome video. Even awesomer outtro pic

  • @simonscherz2869
    @simonscherz2869 6 ปีที่แล้ว

    So what's the advantage of the Howland Current Pump to a current regulator with Zener diode and transistor?

  • @p_mouse8676
    @p_mouse8676 6 ปีที่แล้ว +2

    Nice little circuit, although it would be interesting to compare this to some othere options in sense of price, stability and noise. In this case the resistors need to match very well. You can make a decent current source with tge TL431, which are cheap as chips

    • @davidledger5941
      @davidledger5941 6 ปีที่แล้ว +1

      Yeah it does end up being quite comparable, resistors being so low cost, I prefer this topology when you need the current source voltage controlled, from a DAC or such.

    • @p_mouse8676
      @p_mouse8676 6 ปีที่แล้ว

      Why wouldn't that be possible with a TL431 or similar?

    • @davidledger5941
      @davidledger5941 6 ปีที่แล้ว

      Well with this circuit you don't need any extra parts, wouldn't you need some extra's for a TL431 current source? You might not need much if you did a TL431 current sink.
      How would you do it?

    • @p_mouse8676
      @p_mouse8676 6 ปีที่แล้ว

      Maybe, don't know just right out of the top of my head.
      But in general, just a basic voltage controlled current source only needs an opamp, some kind of MOSFET or transistor and just 1 sense resistor (maybe two passives to get better stability)
      Like I said, this is a cute little circuit, but not very precise because of the resistor mismatching.

  • @gilbertjuly
    @gilbertjuly 4 ปีที่แล้ว

    nice video, wonder what is the circuit simulator you are using? looks awesome!

  • @shomiahmed5144
    @shomiahmed5144 4 ปีที่แล้ว

    Hi there, at the last you talk about some sources of error in terms of a very small current passing through the positive feedback. What if we retained the previous circuit i.e. with a buffer instead of using high impedance? Will that eliminate the small current issue through the positive feedback?

  • @janzkrs8006
    @janzkrs8006 6 ปีที่แล้ว

    I like the short, simple format :)Question though. Isn't this more of a constant voltage source, I mean as said, if the ressistor is not constant the current wont be eather!?

  • @fabiStgt
    @fabiStgt 6 ปีที่แล้ว +1

    Great explanation and also very nice software setup you're using to visualize the circuit!

  • @gregfeneis609
    @gregfeneis609 6 ปีที่แล้ว

    Good work, Sir. As I understand it, a HCP can be used to emulate inductors to other circuits. Would you care to make a video about that?

  • @6alecapristrudel
    @6alecapristrudel 6 ปีที่แล้ว +6

    Another nasty source of error is mismatch in the diff-amp's resistors. This causes the amp to have some common mode gain as well so it's not only amplifying the difference between the inputs.
    If the inputs are shorted together and then we connect them to some input voltage the output will still change with the input even though the difference between the inputs is zero. Even worse is that this common mode gain can be inverting or non-inverting depending on the exact ratio of the resistors in the two input sides.

    • @davidledger5941
      @davidledger5941 6 ปีที่แล้ว +2

      OH YEAH, thats a pretty good point which I completely forgot about mentioning.

    • @Sixta16
      @Sixta16 6 ปีที่แล้ว +1

      Pretty much fail, as due to the mismatch the Howland current pump is one of the circuits that mostly works only on paper and in reality gives poor performance.

  • @Audio_Simon
    @Audio_Simon 6 ปีที่แล้ว

    P.s. Thanks for the easier topic this time around!

  • @newsogn5148
    @newsogn5148 3 ปีที่แล้ว

    Thank you for this!!! I wanted to know more about the homeland current source for a 4-20 ma output in industrial controllers, what software is that???

  • @urugulu1656
    @urugulu1656 6 ปีที่แล้ว +1

    well explained although i remember the howland source a bit different in topology...

    • @davidledger5941
      @davidledger5941 6 ปีที่แล้ว

      This is the improved howland current pump, very slightly different.

  • @RiyadhElalami
    @RiyadhElalami 6 ปีที่แล้ว +6

    Good job David, that was a good reminder for a very helpful circuit.
    You should do more!

  • @k1ngjulien_
    @k1ngjulien_ 6 ปีที่แล้ว

    What is the Advantage of this over a normal V to I CC OPAmp circuit?

  • @Sixta16
    @Sixta16 6 ปีที่แล้ว

    Well, what I completely miss here is the analysis of what effect the accuracy of the resistors and the input offset voltage has on the behavior. Because in most cases, the Howland current pump is a useless circuit that does not give enough accurate current output in many applications. Also the completely floating input reference voltage is not how you would implement the circuit in reality.
    Sorry, if I have missed something.

  • @ACTlVISION
    @ACTlVISION 6 ปีที่แล้ว

    That was interesting but can someone ELI5 what applications is this used for? When would this be used for an LED over just a current limiting resistor?

  • @andreschneider3147
    @andreschneider3147 6 ปีที่แล้ว

    Hi, Dave and Dave! Can you give us some update about EEVdumpsterHack channel?

  • @thiagoennes
    @thiagoennes 6 ปีที่แล้ว

    the picture of dave2 at the end.... always cracks me up. I really like this format. How about some power audio amplifiers?

  • @EdwinNoorlander
    @EdwinNoorlander 6 ปีที่แล้ว +9

    Why is everything so small. Why don’t use the whole screen?

  • @bm830810
    @bm830810 6 ปีที่แล้ว

    excellent explanation, please increase the size though

  • @Apocalypse033
    @Apocalypse033 6 ปีที่แล้ว

    wow,it's a amazing software online

  • @vant4888
    @vant4888 6 ปีที่แล้ว

    What is a practical usage of such current ?

  • @DeRaafMedia
    @DeRaafMedia 6 ปีที่แล้ว

    Needs more breadboards!!

  • @gorillaau
    @gorillaau 6 ปีที่แล้ว

    Nice Video, David.

  • @Biela2008
    @Biela2008 6 ปีที่แล้ว

    More of this please! :D

  • @dshshajskj6143
    @dshshajskj6143 2 ปีที่แล้ว

    Can i use RC parallel as load and will it effect the current in Howland Current Converter

  • @abcvideoyoutuization
    @abcvideoyoutuization 6 ปีที่แล้ว

    Could you show a working pump?

  • @fabimre
    @fabimre 6 ปีที่แล้ว

    Interesting.
    Btw, which software did you use?

  • @stonail665
    @stonail665 6 ปีที่แล้ว

    Big fan of Falstad ,also there are 2 mobile apps called icircuit and Everycircuit which is the same software.
    nice tuto great explanation.

  • @RobertShaverOfAustin
    @RobertShaverOfAustin 6 ปีที่แล้ว

    What simulation/circuit tool are you using for this tutorial. I love how it looks and how easily you made changes.
    *CIRCUIT QUESTION:* in the latter part of this tutorial you show a "load" resistor on the right side of the diagram connected to ground symbol. What I don't understand is where the current returns to the source. How is that circuit completed? The ground symbol is just a shorthand way to show a connection. Can you replace this symbol with a wire to show the return path?
    *TUTORIAL QUESTION:* What is the objective of this tutorial? You explained many things but I did not always follow why they were important to know. One example is the _virtual ground_. I think you expected me to understand why this was important and why it would be useful.

  • @proluxelectronics7419
    @proluxelectronics7419 6 ปีที่แล้ว +19

    Why so small??

    • @davidledger5941
      @davidledger5941 6 ปีที่แล้ว +7

      The application doesn't zoom well. Wanted the video to be in native resolution, for maximum crispness.

    • @christophertstone
      @christophertstone 6 ปีที่แล้ว +2

      What doesn't zoom well, Falstad? It's vector based... And there's horrific letterboxing. This looks like something my grandma forwarded from the Facebook app on a Nokia 3310. Excellent content, but the production quality is seriously distracting.

    • @steverobbins4872
      @steverobbins4872 6 ปีที่แล้ว +2

      I too could not see the circuit very well at first. Then I changed the TH-cam settings to HD and I could see the circuit very clearly. (David, I would suggest for your next video you start by telling your viewers to switch to HD.)

    • @stephenkemp6870
      @stephenkemp6870 6 ปีที่แล้ว

      Yes, switch to HD. Worked for me. Thanks David.

    • @salerio61
      @salerio61 6 ปีที่แล้ว

      Christopher Stone Everyone's a critic

  • @Audio_Simon
    @Audio_Simon 6 ปีที่แล้ว

    3:30 Looks very similar to the 'Super Balanced' audio input in a book by Doug Self. Designed to load each half of the diff input equally. www.douglas-self.com/ampins/balanced/balfig12.gif

  • @davidliddelow5704
    @davidliddelow5704 6 ปีที่แล้ว

    How accurate do the resistors need to be?

  • @illustriouschin
    @illustriouschin 6 ปีที่แล้ว

    didn't learn what it does and how it is used but pretty good video.

  • @pirateman1966
    @pirateman1966 6 ปีที่แล้ว

    That software looks so much like Circuit Wizard, but free and online!

  • @AttilaAsztalos
    @AttilaAsztalos 6 ปีที่แล้ว

    But but but... what happened to the Old Pump of Howland...?

  • @gianlucalocri
    @gianlucalocri 6 ปีที่แล้ว +1

    Hi Dave!
    What about connect the load directly on the non-inverting terminal of the opamp?
    Like this
    fourier.eng.hmc.edu/e84/lectures/HowlandCurrentSource/node1.html

  • @marianoaldogaston
    @marianoaldogaston 6 ปีที่แล้ว

    Great work, I Think it will be great next time after explanation, do the circuit on breadboard and make some measurements

  • @station240
    @station240 6 ปีที่แล้ว +3

    6:38 Couldn't you replace the unity gain buffer with a simple diode ?
    That would stop the current flowing the wrong way, and as you stated earlier the entire circuit counteracts voltage offsets.

    • @SiloxMedia
      @SiloxMedia 6 ปีที่แล้ว

      Yeah, I think that would work.

    • @domenbull
      @domenbull 6 ปีที่แล้ว +1

      It wouldn't work, since you need to have gnd;
      There must be current (no matter how small of a current), because you need the drop of voltage on the resistors. Useing a diode you would basicly make one resistor useless;
      I hope you understand

    • @domenbull
      @domenbull 6 ปีที่แล้ว +2

      tinyurl.com/y9ubrjzy here is simulation of it

    • @yavuzturan6830
      @yavuzturan6830 6 ปีที่แล้ว

      damn. whole circuit is in the url guess.

    • @domenbull
      @domenbull 6 ปีที่แล้ว

      Resistance of the load should be many times smaller than the resistance of the of the circuit, basicly circuit must have as high of impeadeance as posible (6:40)

  • @emcgon
    @emcgon 6 ปีที่แล้ว +3

    More like this, please: I miss tutorial-style videos on EEVBlog since Fundamentals Friday stopped happening. One suggestion: it would be nice to mix the theory with a practical demonstration of an implementation on a breadboard or something like that. Loved it, though.

  • @justinnamilee
    @justinnamilee 6 ปีที่แล้ว

    Yeah, great content, just zoom up on the subject matter a little more~! Keep it up Dave2.

  • @abc9999ful
    @abc9999ful 5 ปีที่แล้ว

    Wich spice do you use??

  • @johnpaulsalazar5382
    @johnpaulsalazar5382 6 ปีที่แล้ว

    What op amp did you use?

  • @casperhito
    @casperhito 6 ปีที่แล้ว +1

    Dave 2 working on the goatee. nice

    • @gorillaau
      @gorillaau 6 ปีที่แล้ว

      Casper Myers I reckon he'd be able to pull off wearing a beret.

  • @TheDefpom
    @TheDefpom 6 ปีที่แล้ว

    What software was that Simulator? EDIT never mind you already answered it.

  • @liviupeles8666
    @liviupeles8666 6 ปีที่แล้ว

    What's the name of the simulation software ?

  • @gorillaau
    @gorillaau 6 ปีที่แล้ว +2

    What's the software you are using.

    • @kaizen9451
      @kaizen9451 6 ปีที่แล้ว +5

      www.falstad.com/circuit/circuitjs.html

  • @RLDacademyGATEeceAndAdvanced
    @RLDacademyGATEeceAndAdvanced 2 ปีที่แล้ว

    Good

  • @MajorAbuse
    @MajorAbuse 6 ปีที่แล้ว

    Please redo with a larger schematic.

  • @牛贺龙
    @牛贺龙 6 ปีที่แล้ว

    what is the application?

  • @viktordunaew5119
    @viktordunaew5119 6 ปีที่แล้ว

    How the software is called ?

  • @chrisbalfour466
    @chrisbalfour466 6 ปีที่แล้ว

    Bah, that's what an LM317 wired as a current regulator is for. Discrete opamps are just a pain.

    • @6alecapristrudel
      @6alecapristrudel 6 ปีที่แล้ว +1

      This can be used as an AC current source and can do small currents, it even has a differential input on top of that. The LM317 current source is DC only and has a minimum current requirement of 10mA-ish to work, though granted it can do much higher currents.

    • @chrisbalfour466
      @chrisbalfour466 6 ปีที่แล้ว

      Except a (non-polarized) capacitor in series with a load given an AC source creates a nearly 100% efficient alternating current source (for small-ish loads like a pair of anti-parallel LEDs). The average current is determined by the capacitance.
      Just three components to build an LED light that runs straight off of 120V 50/60Hz ;)

    • @6alecapristrudel
      @6alecapristrudel 6 ปีที่แล้ว

      Good for you. The Howland is pretty much useless for driving LEDs that really need the constant current since they're power LEDs that need much more current than the 20-ish mA an opamp can give you. You can get away with just a resistor for low power ones.
      What you can really use the Howland for though is oscillators, waveform generation and such. Have it drive a cap, feed in a square wave and out pops a triangle wave.

    • @chrisbalfour466
      @chrisbalfour466 6 ปีที่แล้ว

      Sorry, opamps make me cringe. I have an electronics degree, but I'm an unemployed hobbyist and I've only needed an opamp once in the past ten years, for measuring brief voltage spikes too fast for an ADC to handle.
      For a waveform generator I'd actually ad-hoc something with a PWM through a capacitor or an H-Bridge and PWM. Only if either of those wasn't adequate would I consider an opamp. If I needed a 1MHz or higher frequency, I'd might have to break down and give the Howland a shot... But I'd exhaust all other possibilities first.

    • @6alecapristrudel
      @6alecapristrudel 6 ปีที่แล้ว

      Sadly the cheap opamps are kinda shit at MHz frequencies, they can work but accuracy is terrible. Hell some can't even make it to 1MHz at all. The ones that can are expensive, though usually they're also much less hassle, I also do just hobby stuff and I want them all because they're magic.

  • @johnsenchakinternetnetwork2025
    @johnsenchakinternetnetwork2025 6 ปีที่แล้ว +1

    Couldn't you just connect a transistor to have gain and then use it for a current source from emitter to collector ?

    • @davidledger5941
      @davidledger5941 6 ปีที่แล้ว +2

      There are many ways to do it, this is one way. One of its advantages is that its voltage controlled. And the control voltage could be ground referenced.

  • @Biela2008
    @Biela2008 6 ปีที่แล้ว

    8:44 That photoshop job....