Second shifting theorem of Laplace transforms

[@sachinc_rajagopal4418]

Brilliant mathematics, Doctor . You have uncluttered many minds .

[@inthebackwiththerabbish]

Decluttered*

[@DannyBoi56]

Thank you so much. I was so lost when I first attempted these, and you made my cryptic textbook crystal clear. Thank you!

[@QuinnMorgendorffer]

Thank you. I'd like to second what Veraila has said. My exam is tomorrow and I am always a notoriously late studier. I watched this once and I understood it and have been able to go away and do every Second Shifting Theorem question on the past exams. Now I'm off to go see if you have any Convolution Theorem videos!
Thanks again Chris.

[@DrChrisTisdell]

@Veraila It's because the function (t-1)^2 is zero when t=1, so there is no jump in the case. Hope this helps.

[@gurtaj]

wow understood the whole thing, thanks a lot sir. Keep up the good work .

[@eesaarashid1954]

thanks you doctor. I understood everything clearly. lifesaver u r

[@Veraila]

omg, thank you! thank you! A hundred times thank you! :-) I finally understand it! My exam is in two days and this has saved my life! btw do you have the answers to last 2 questions; I couldn't find your website :(

[@shahed1368]

Thank you Dr. Tisdell. your video helped a lot.

[@chalams]

Thanks sir, this helped me in understanding in a better way

[@yuehernkang]

this is very helpful sir. thanks so much ! Helped alot for my tesT!

[@zuhairalsaffar7001]

l like your way of teaching thank you so much for your help and support 🙏 ❤ 💙

[@DrChrisTisdell]

My pleasure.

[@TheAdlcn]

I think large video and small video at the right bottom corner are totally different :)

[@DrChrisTisdell]

Adil Can Balçık You're right! That's my error, as the files got mixed up.

[@chcknmld]

Does this method apply strictly to this example only? Because it get the wrong answer to anything else I apply it to.

[@lindawillis2391]

this just cleared my doubts thanks

[@PixieLavender]

Hello, I cannot find the answers on UnderstandMath.tv to the last part where you gave us questions to answer.

[@DrChrisTisdell]

Hi - you can find them in the free ebook tinyurl.com/EngMathYT.

[@noelacquer]

This helped a lot, thank you!

[@yusafmagsi]

QUESTION! after solving the problem at the end in final part of example b) while writing the solution would you write u(t-4)g(t-4)^2 or just u(t-4)(t-4)^2 without the g.. ?

[@Veraila]

Just a quick question, when you drew the graph of t-shifting for part a), why wasn't there any 'jump' at t=1(point c); why did it just connect to the graph for (t-1)^2 immediately? It's just a bit ocnfusing :S

[@henryunderhill5417]

Because when you switch the graph on , it's value is determined by the t value at that point, which was zero in this case

[@VarunBharathiJBEC]

thanks u so much for the class!! : )

[@thetruereality2]

Can we use second shifting property while solving heaviside problems ??

[@aliabdullahnajm7000]

I'll be very grateful if you could tell me how to recognize first shifting theo of second shifting theo. because that make me confused .(I have an exam next week hope you to ans. as soon as possible )

[@deepshikharb]

thanks for the video, Sir.. It helped :)

[@DrChrisTisdell]

Wow - thanks!

[@DrChrisTisdell]

@philg24 Download the PDF to get the answers from UnderstandMath.tv Best wishes.

[@Sawsan8822]

Why did you replace (t-1)^2 with t^2 ??

[@DrChrisTisdell]

Hi - could you please let me know the time within the video that your question refers to?

[@Sawsan8822]

Dr Chris Tisdell 4:07 and thanks a lot for responding, professor Chris :D

[@hippomantube]

He didnt replace it, he was simply labeling each part of g(t-c), he then wrote t^2 because that is what he needed to use the formula. he wrote g(t-c) then g(t), the latter would be used in L{g(t)} mutiplied by e^-cs, which would give him the final answer.

[@pradheepkrishna6964]

Thanks a lot sir...

[@jonizo89]

Thanks! :)

[@bashirchoham5364]

horrible waste of time