If D is integral domain then polynomial Ring is also integral domain

แชร์
ฝัง
  • เผยแพร่เมื่อ 24 ต.ค. 2024

ความคิดเห็น • 14

  • @india6596
    @india6596 5 ปีที่แล้ว +1

    sir ring theory chapter ki aur theorem k proof ki video bhi upload krdo please .i will be very thankfull to you

  • @Mathemastery
    @Mathemastery 3 ปีที่แล้ว +2

    Very good lectures 👍🏻 keep doing

  • @sabazahid426
    @sabazahid426 ปีที่แล้ว

    We have to show polynomial ring an integral domain. Whereas polynomial ring contains finite polynomials...so how can we prove it using infinite polynomials f(x) and g(x)... Aren't we supposed to differentiate it from formal power series ring??

  • @Explainer103
    @Explainer103 5 ปีที่แล้ว +1

    Zero divisor= if a.b=0,then neither a=0,nor b=0,without zero divisor means if a.b=0 then a=0 or b=0

    • @PathFindersAcademy
      @PathFindersAcademy  5 ปีที่แล้ว

      ya ur argument is correct. On the other way to Prove that in a Ring there is no zero divisors that is we have to show that product of any two non zero elements say a and b which is not equal to zero ( a.b is not equal to zero for all a and b belongs to Ring)

  • @sakshi8808
    @sakshi8808 4 ปีที่แล้ว +1

    Sir plzz solve converse part of this therom

  • @chandrashekharsingh8387
    @chandrashekharsingh8387 5 ปีที่แล้ว +2

    Thanks sir

  • @Explainer103
    @Explainer103 5 ปีที่แล้ว +1

    Commutative ring with unity?

    • @PathFindersAcademy
      @PathFindersAcademy  5 ปีที่แล้ว +3

      It is very simple to show that D[x] is Commutative because D is integral domain
      Otherwise Take any 2 polynomials denote is as F(x) and g(x) take it's general form find F(x).g(x) by multiplication of polynomial u get expansion as D is integral domain u can interchange elements in products now u get g(x).f(x) this proves that D[x] is Commutative Ring

    • @Explainer103
      @Explainer103 5 ปีที่แล้ว +1

      Thannks

    • @chandumudiraj2582
      @chandumudiraj2582 3 ปีที่แล้ว

      Thanku bro👌👌