It is utterly *ridiculous* that EVERY Sudoku that appears on this channel is world class. Imagine being able to dine out in your favourite restaurant 365 times a year, ordering different meals every evening and _always_ having the best meal of your life. That's how Simon and Mark must feel about these puzzles.
It really is like that eh? When I first found the channel I thought it was just a lot of hyperbole but... honestly there's just a ridiculous quantity of really incredible puzzles once you know where to look. It's wildly impressive.
I've been following for a couple of years now, not only the software is much much better (to the point the older software videos are almost unwatchable), the puzzles also get better and better
Mark and Simon are like billionaires in a world where money can buy happiness...! All these artwork quality puzzles, the full-featured software, and a big audience to enjoy the struggle...! I hope it never ends.
Thanks for featuring my puzzle, Simon! A pleasure as always! You managed to find almost all column 1/row 1 deductions. For the one which had 9 in the middle, r1c1 and the remaining odd in box 3 (or 7) have to add to 9, so the remaining odd in those boxes are 3 or 5. Due to the 8 in r8c8, r1c8 can be neither. That was hard to spot, so I think you did a nice job working it out through the middle zipper.
Thank you for a great puzzle. I used that logic to solve R1 and C1. It was interesting to see Simon use a different path, and I might have shouted to the screen what else can there be except 9 😅
My very similar approach was to subtract out all the known sums (including the pair that add to 9). The 3 corners add to 12. This only happens if R1C1 is 4, and is paired with 5. 5 only goes in one place. Sorted!
Oh, I love Simon's use of the Enligsh language. "That's slightly true... no, that's *jolly* true" I will use that as a gradient for truth going forward
Simon: this is so ridiculously complicated, how does this have only 3 stars? Me: because Simon always picks the most complicated (and beautiful) way to see/prove things? :D
Simon: “If we do X, then y, therefore z, meaning that a, b, and thence c, and so therefore, you cannot place 7 in column 1!! And we now know that X cannot be true.” X: *has five even digits in C1* Simon: “This logic is *so* unusual.”
simpler way of deducing that R1C5 and R5C1 can't be 6 is that it would use up 2,4 and 6 in that row or column and then both square cells in R1 or C1 would both have to be 8
Simon, you constantly find beauty and deductions in all your solves. So humble you are that always giving credit to the setter!! The joy you get in solving for us day after day is something special for us.
So many really clever deductions involved here. It feels like in many of the steps you need to extend the logic by one step further than you'd normally have to in most puzzles. It's not that these two digits see each other so they can't be the same; it's that they each have a counterpart that sees the other's counterpart and if they're the same then so are their counterparts, and that's why they must be different. Lots of that sort of thing going on. Very impressive!
Hello, I rarely comment on youtube videos but I have to say that those sudoku videos are just a chill time i enjoyr almost everyday. Thanks for these moments :)
I just love how sometimes Simon jumps between parts of grid and missing his deductions from before. @16:52 he forget about 9's in row 1/collumn 1 can be placed only at r1c5+r8c1 and r1c8+r5c1, completely removing 9's from center of two zippers.
Just got to 16:26 and I was thinking the same thing, especially as he has just deduced that 9 cannot be in the centre of both row 1/column 1 zippers so r8c8 cannot be a 9
@@Dale-hv4xi I noticed the same thing. I think it's a lot easier for us to spot these issues from the armchair rather than putting together all the rules while your brain is working hard doing the solve.
Also when he tries to put a 6 in r1c5 @20:29. He had already deduced that without a 9 in the zipper the constraint was even digits. So the zipper needs to have 4 odd digits on it and the only possible way to construct that is with 1357.
Mr. Menace thank you very much for this puzzle. I cannot describe in words the joy I felt logically discovering what number goes where on the grid here. I took double the time than Simon but what a pleasure it was this discovering.
Exquisite puzzle, lots of fun deductions. At 38:54 there is another way to deduce how the first column and row go. Simon noticed that whichever digit goes to r1c1, its pair to make 9 is not on the zipper line in box 1. The same holds on the zipper line in row 1 or column 1, whichever has the 9 on the zipper. So in that row or column the pair of 4 or 6 must not go on the zipper. The pair of 4 or 6 is either 5 or 3, so this digit must go to either r1c8 or r8c1 as r1c9 and r9c1 must be even. But r1c8 sees both a 3 and a 5, so column 1 must be the zipper with the 9.
The eclipse was awesome! Truly awe inspiring. I saw it over a lake in a clear blue sky. It was so quiet....until I heard distant clapping and cheering from the forest all around me from others having the same experience.
My last deduction from row and col 1 was this: when you know the zippers are 8 and 9, they always have at least 3 odds on them (8 has 4 odds, 9 has 3). This means the row or col with 9 has to have two more odd digits - which cant be in the corners. Together with the fact that the row or column with the 8 has to have a 9 in the light green square (the 5th odd) - leads to the fact that both light green squares are always odd. This disambiguates where 8 and 9 zippers go, because there arent many odd digits available in r1c8.
I did this one all by myself, took me only 10 mns more than Simon!! And I filled the 8 and 9 rows without using the middle purple line! I'm a bit baffled actually. I even used all the right logic instead of hammering away at all pencilmarks I can think of. This will be a very good day surely! Thank you mr Menace for this journey in a puzzle, I even giggled at things like "well, both the cells are a one" in row and column one
10:34 "If both of these were 9s..." There's another way besides (and perhaps simpler than) the parity logic Simon gets to shortly to prove this cannot be the case - whichever of the marked 7 positions in box 1 is NOT 7 must sum to 9 with r1c1, since if it didn't its partner would be lonely on the zipper line. As such if the associated row/column 1 zipper line were a 9-sum the digit in r1c1 would repeat in the orange cell
Simon casually understanding that whichever zipper we put the 9 on the other can not have more than 1 even digit on it, and then goes on an entire tyrade about where 7 goes if 6 is in the middle even tho 6 would need 2-4 which he already proved is impossible :D also love it when I make the same progress in 5 minutes as he does in 20, but get stuck for a whole hour after that :D
At 10.47 minutes you could already have concluded that R6C6 or R4C4 was a nine, because the 9 cannot be on the zipper. (''Where does 9 go in box 6?'' would have been the right question, I learned from you) At 47.11 min you would then automatically be sure that the 9 was in R6C6, or at 51.27 min, when the 9 was placed in R2C4. As it was, it became the penultimate number that you filled in, at 53.29! It's funny how you sometimes miss the obvious, but I would have missed out on the beautiful deductions that you came up with now. I assume it would have considerably shortened the video. But again....I'm not complaining! Beautiful puzzle, beautiful solve!
I got 58 minutes. Calculating the different values for the zipper lines in my head was a little bit challenging. but it was really fun to do so. This was a great puzzle!
0:53 I always needs to go listen to "Losing my Religion" to cleanse the palette after hearing the "3 in the corner" song. Mark gives it a valiant effort, but is not a singer, and Simon just giggles his way through it each time.
fascinating how long it took Simon to notice the middle square couldn't be 7. I think his brain works in such complicated mathematical ways these days, he has forgotten to scan.
How can it be that Simon almost instantly jumps to the question "where is the nine in column 1?" and then "where is the nine in row 1?" and next embarks on a far-fetched quest on symmetry without ever going up with the question of the nine in box 1.
41:21 finish. I had a bit of a snafu in the middle, when I didn't think about what a few of my pencil marks meant. That caused an erroneous chain of events which lasted for a good 5-10 minutes. Fortunately it was an easy fix after rewind, and all of the logic I had done was still sound, just with different numbers. Brilliant!
Yay managed to solve this one! Took me 1:04:45. Don't usually solve sudokus much but I thought it was a worth a try without watching Simon :) I think this is the first zipper line sudoku I've ever solved but I've done a few odd/even parity ones too. I did get stuck a lot but I pulled through without turning to the video for hints.
An easy way to determine which way row 1 and column 1 go was to look at the 8th digit in each. They have to be 9 and 5. Then the 5s in box 9 give you which way round that row 1 and column 1 go.
I thought it would be a fun challenge to try to make that zipperline rule more concise. Here goes: The center of a purple line is the sum of pairs of cells equidistant from it.
There are a lot of elegant deductions to be made in this puzzle, and I mean a lot. No way is this a 3 star puzzle! That said, I probably did miss something. Very nice though, thanks.
Some very interesting breakin logic to fill in those middle zipper digits i think 3-4 stars out of 5 is about right. took my just under 40 minutes to complete so certainly not the hardest of puzzles but not easy either
Closes box showing the real time it took to solve puzzle, only to check the recording time while asking how long it took to solve the puzzle - everytime!
43m20s. Not a whole lot to say about this one except that the deductions were delightful as always, and i like zipper lines. Edit: No there is something to say! After having slept on it my mind came back to finding the 89 pair on the zipper centers on R1 and C1 and how that forced the R5C5 zipper center to be 5 or 6 and the feeling of... dread is not the right word, but that "oh gosh, what consequences is THAT going to have?" is a reaction I don't often feel and I cherish it
22:00 An easier way of seeing why that couldn't be 6 is because you would have too many even digits in c1 and r1. The corners are even, so that takes up 2 of the 4 even digits allowed. if the middle square is 6, than you would only be allowed 1 more even digit so the sums need to be dual-odds. the only odd numbers that add up to 6 are 1-5 and 3-3, but that last one is illegal.
I think the simplest path to seeing that the edge zippers take an 8,9 middle is that the nine and all but one even number are used up in the row/column, so the zipper is 1357 and a mystery even-so once you deduce that the even is in the middle, 1+3+5+7 = 2X.
Just wanted to say how much I love the shout outs and happy birthdays at the start of every video. You would think it's something you might skip through but I just love how genuinely appreciative you are of your followers and how lovely you are! Much love
when I made 89 center pairs for the two lines I completely forgot they could either be in either of the sides as a pair, so I took an extra 30 minutes to beat it, the double 3 for the 6 give away the order of 89 pair and the rest was just sudoku, really interesting.
I cracked this one by realising that r1c8 & r8c1 both had to be either 5 or 9 by running through the 8/9 zipper options. Then placed the 9 in r1c8 because of the positions for 5 in box 9.
So I'm a middle level player with Soduko and I love watching the channel. But for the first time (probably ever) I saw something before Simon. When he was talking about the 9's and was pointing out the middle row 1 or the middle column 1 I saw that affected 8R8C. Whoot whoot !!! I guess I'm getting better (nowhere near the master but still pretty good haha).
Around 15 minutes in, you're looking at box 9, completely oblivious to what you've just proved when considering box 1. That is, one of the straight lines is a 9, which prevents the other being 9, so one of R1C8, or R8C1 is 9, therefore the zipper in box 9 must be an 8. @ 20:42 - "If it is 6..." - Seconds earlier you explained that the only even digit you can put on the line must be in the centre. Now you're trying to put 2 and 4 on the line as well! Those centre digits are an 89 pair, making the R5C5 either 5 or 6 (despite your best efforts, it could never be 7) Your ability to forget what you've just worked out amazes me. @ 22:04 - "It's so ridiculously complicated" - Only because you make it so. As explained above it's trivially simple. Your "beautiful trick" to disambiguate the 5/6 line wasn't necessary. Sudoku would have given you that. @ 45:18 - "I've run out of colours" - Why have you got any colours? The ones you've used are totally useless. If you can't remember that the digits on the edge form pairs, you really do have a problem. Your utterly chaotic approach to sudoku baffles me. There's just no method to it at all, you just make one deduction, then look somewhere completely different. For instance, you got the 7 in R3C1, and instead of going down the column, where the next cell was a 78, and the one after that was an 89, you jumped to R1C3 and then filled in R1, eventually returning to C1. Even when you've placed a digit, let's say it was 2 at the bottom of the grid, and this resolves a 23 pair at the top, you'll point at the cell which sees the 2, but then click on the other of the pair, making it 2, before returning (sometimes) to click on the cell you originally pointed at to make it 3. You'll then completely forget to look at the second 2 you placed to see what difference it made. Instead, you look at the 3 and are surprised when it gives you nothing. If you first put the 3 in the cell which can't be 2, you can then click in the other cell which cannot now be 3, and then you can see what impact that has, which is quite likely to give you another 2 in a third column, or at least eliminate 2 from other cells in the same column. This is one of the main reasons you end up missing so much, because you jump forward, then step back, breaking the flow. It's not that you miss stuff which bothers me, it's a live solve and you're bound to miss stuff. It's that you miss stuff because of how you work which bothers me. If you were logical and disciplined when filling in the grid, you would miss half of what you do. As you're a fan of logic, I don't understand why you eschew logic when filling in the grid. Sorry for the rant, but this was a very shouty video.
R1C1 could be determined early because of that careful placement of the given 3, which eventually rules out R1C8 and R8C1. Therefore ask how you can put 3 on both the zipper lines?
Thanks Simon! I enjoyed the video as always. 24:25 Once you deduced that there was an even on the opposite zipper from the 9 zipper, I think you could’ve left the deduction of the 89 pair to the fact that the even digit had to go on the center along with 4 odd digits comprised of 1,3,5,7 = 16 / 2 = 8. Or did I miss something?
Only 18:02 for me. Was able to quickly spot a few of the 9 positions. And then in box 1 with an odd total, there had to be 2 more evens on the equal distance lines. From there on the solve wasn't too difficult anymore.
23:30 The easier argument against the other center being 6 is that the row/column now has too many even digits. 6 requires 24, and the boxes require two more. 29:50 I bifurcated on 8 vs. 9 using cornermarks and centermarks for the two possibilities. The 5s in block 9 settled the choice.
@@glum_hippo Written in the stars? I felt it? I might have superpowers I guess, because I haven't seen any threes in corners anywhere ever since. I even checked under the curtains. Not even any football player with nr 3. on his/her back have been taking corners that I know of.
12:40 Sorry Simon, R5C1 and R1C5 can't both be nines - or both odd digits for that matter - since your argument proves that both R1C2 and R2C1 will then be odd and that's simply impossible because of the zipper line.
Classic Simon using crazy (but sound) logic to work out the middle of C1 or R1 can't be a 6. When in the sentence immediately prior to that logic he says, "If it's a 6, the other cells have to be 1-5 and 2-4." Which soaks up too many even digits. Always entertaining 😊
R1 and C1 are a lot simpler than Simon makes out, which is easier to see with case testing and just filling numbers in to see what happens. The middle of the zipper that isn't 9 can't be 6 because we've already worked out that the zipper can only have odd digits so it must be 1-3-5-7 with an 8 in the middle. Very clever puzzle but not too difficult if you just bash some numbers in rather than trying to fold too much in your head, finished in 25 minutes 👍🏻
"but what if it's 6? Then where does 7 go?" Or, you know, 6 doesn't work because you'd need a 2 4 pair on the zipper and just said the last even goes in the center of that zipper.
"This is so complicated" "Only three stars for difficulty" implies "Ah, I must be doing it wrong".... And how can you use a word like "Lacuna" without trying to make a pun with "Coil"...
Sigh. I fought with it for over an hour, then realized I was getting the line sums in B1 wrong, treating them like arrows rather than zippers. Unfortunately I don't have more time or energy to spend on this one. Oh well.
Nice puzzle! One curious thing is that I got the puzzle completed pop-up despite having one cell still pencil-marked (R7C5). I also got the screen after filling it in correctly and deleting the entry. The preemptive popup went away when I closed the tab and reopened. Not that it affected anything, just thought it was interesting
For some reason, the input solution doesn't appear to care what you put into the four cells r7c2, r7c5, r8c2, r8c4. Leave all four of those blank, and it still says it's a correct solution. Very strange.
if 6 was in either of the two green centre fields and 4, 2 was one of the sums adding to 6, plus two even numbers in the corners, that's 5 even numbers between 1 and 9.
This was the hardest puzzle i ever solved, took me about 100 mins. And i solved a few 4 star puzzles before. No way this is 3 stars. Amazing puzzle though.
My break-in was completely different and MUCH easier. And I do mean incredibly easy. We already know that if the center digit is an 8 along the first row or column, the 8th digit is a 9. This gets us the info in box 9 (ie. center cell of box 9 is an 8, etc.) similar to what was done in the video. Now let's consider the case where the center digit is a 9 along the top row (we'll start with the top row for now). We are told there are two pairs that add up to 9 based on the zipper. That means the remaining 4 digits on the row must also pair up to add to 9 as two pairs. So what cell does the first cell (that can be a 4 or 6) pair up with? It's even. So it doesn't pair up with the 9th digit. And it cannot pair up with the second cell because that's on a zipper line that already adds to 9 with a different cell. So the only cell left is the 8th cell. The 8th cell MUST be 5 or 3 to pair up with the 6 or 4 in the first cell. But if we tried 3 or 5 in the 8th column, there are already 3 (given) and a 5 (in box 9) in use. So the 9 has to instead go in the middle of the first column. Along the top row in the middle is an 8. Easy. Just look at the pairs that add up to 9, not just the pairs on the zipper but for the whole row. That's it.
20:34. Or you can just say one way to make 6 is with 2 and 4, leaving only 8 to fill both corners. Simon does like to make things more complicated than they need to be, doesn't he?
@45:36 - he makes the claim ".. can't include 2's and 4's" ... but why not? If the grey squares are 2 for example, they're compliments are 4. and r7c3 can be 4 and it's compliment r3c6 can be 2 (while it's neighbors on the upper part are 4's ??) this assuming r8c3 is a 1 and r2c6 is a 5 regardless. But I'm not seeing how he can jump to r7c3 is a 3 so quickly? it could easily be the other 2 or 4 ?
![งมหอย จับปลา มือเปล่า หาอยู่หากินแบบวีถีอีสานกับแก๊งเซียนหรั่ง ม่วนคัก! [ขอนแก่น] @Sianstudio](http://i.ytimg.com/vi/JEJZg6N-AbU/mqdefault.jpg)
It is utterly *ridiculous* that EVERY Sudoku that appears on this channel is world class. Imagine being able to dine out in your favourite restaurant 365 times a year, ordering different meals every evening and _always_ having the best meal of your life. That's how Simon and Mark must feel about these puzzles.
That’s how I feel watching.
Very well said!!
It really is like that eh? When I first found the channel I thought it was just a lot of hyperbole but... honestly there's just a ridiculous quantity of really incredible puzzles once you know where to look. It's wildly impressive.
I've been following for a couple of years now, not only the software is much much better (to the point the older software videos are almost unwatchable), the puzzles also get better and better
Mark and Simon are like billionaires in a world where money can buy happiness...! All these artwork quality puzzles, the full-featured software, and a big audience to enjoy the struggle...! I hope it never ends.
Thanks for featuring my puzzle, Simon! A pleasure as always!
You managed to find almost all column 1/row 1 deductions. For the one which had 9 in the middle, r1c1 and the remaining odd in box 3 (or 7) have to add to 9, so the remaining odd in those boxes are 3 or 5. Due to the 8 in r8c8, r1c8 can be neither. That was hard to spot, so I think you did a nice job working it out through the middle zipper.
Thank you for a great puzzle. I used that logic to solve R1 and C1. It was interesting to see Simon use a different path, and I might have shouted to the screen what else can there be except 9 😅
It was massively satisfying to solve this one. Very good puzzle with some great logic!
Loved this setting from you!! Fabulous how the zippers all interacted together. Thank you for the insight into your mind!!
My very similar approach was to subtract out all the known sums (including the pair that add to 9). The 3 corners add to 12. This only happens if R1C1 is 4, and is paired with 5. 5 only goes in one place. Sorted!
Fabulous puzzle, Mr Menace! 👏👏
Oh, I love Simon's use of the Enligsh language.
"That's slightly true... no, that's *jolly* true"
I will use that as a gradient for truth going forward
52:11 "please dont be difficult now, I really really just want to fill you in" naughty simon
😂 "naughty simon" ...
It feels like a Whose Line "Scenes from a hat" style 'things you can say to your partner and puzzle book'.
Simon: this is so ridiculously complicated, how does this have only 3 stars?
Me: because Simon always picks the most complicated (and beautiful) way to see/prove things? :D
Simon: “If we do X, then y, therefore z, meaning that a, b, and thence c, and so therefore, you cannot place 7 in column 1!! And we now know that X cannot be true.”
X: *has five even digits in C1*
Simon: “This logic is *so* unusual.”
We can clearly not choose the wine in front of Simon.
@@nochsta What's that over there!
simpler way of deducing that R1C5 and R5C1 can't be 6 is that it would use up 2,4 and 6 in that row or column and then both square cells in R1 or C1 would both have to be 8
Simon, you constantly find beauty and deductions in all your solves. So humble you are that always giving credit to the setter!! The joy you get in solving for us day after day is something special for us.
No snakes, no loops, no doubling or halving, no need to design the boxes. Just Sudoku. What a fantastic SUdoku puzzle !!!!
-Simon what is your kryptonite?
-Playing sudoku on a sudoku puzzle
So many really clever deductions involved here. It feels like in many of the steps you need to extend the logic by one step further than you'd normally have to in most puzzles. It's not that these two digits see each other so they can't be the same; it's that they each have a counterpart that sees the other's counterpart and if they're the same then so are their counterparts, and that's why they must be different. Lots of that sort of thing going on. Very impressive!
If it were 6 on the left, you won’t have enough even digits for the corner.
Finally a video where i see something before him!
@@jaytrox4599 Just look at box logic first XD
I was yelling at his logic to get rid of the 6 chance in the middle of both zippers..2 and 4 and 6 on a zipper makes corner evens impossible,
Yes was saying the same 😂
Hello, I rarely comment on youtube videos but I have to say that those sudoku videos are just a chill time i enjoyr almost everyday. Thanks for these moments :)
Rules: 04:13
Let's Get Cracking: 05:07
Simon's time: 48m35s
Puzzle Solved: 53:42
What about this video's Top Tier Simarkisms?!
The Secret: 3x (02:29, 02:44, 05:11)
Bobbins: 1x (17:48)
Knowledge Bomb: 1x (05:43)
Three In the Corner: 1x (00:45)
And how about this video's Simarkisms?!
Ah: 13x (14:26, 15:17, 15:17, 15:17, 16:00, 33:03, 33:03, 33:07, 35:47, 38:02, 40:35, 47:55, 49:30, 50:28, 50:28)
Pencil Mark/mark: 11x (09:52, 14:50, 24:54, 28:26, 34:21, 35:13, 35:28, 37:31, 40:14, 44:28, 48:49)
Symmetry: 11x (06:19, 06:50, 06:52, 07:05, 07:20, 07:30, 07:34, 09:40, 36:51, 39:39, 42:09)
Sorry: 6x (03:09, 08:07, 08:07, 15:22, 28:06, 30:21)
Beautiful: 6x (09:12, 21:28, 33:10, 42:20, 53:55, 55:16)
Hang On: 6x (13:37, 30:15, 45:51, 46:15)
Cake!: 6x (02:25, 02:37, 02:49, 02:53, 03:18, 03:20)
Goodness: 4x (08:04, 08:29, 40:35, 47:24)
The Answer is: 3x (05:57, 41:02, 50:00)
Brilliant: 3x (01:06, 44:38, 45:20)
In Fact: 3x (06:28, 22:59, 27:19)
Obviously: 3x (06:43, 12:02, 21:02)
Good Grief: 2x (21:28, 38:02)
Naked Single: 2x (51:35, 52:58)
Shouting: 2x (02:36, 03:45)
We Can Do Better Than That: 2x (19:56, 42:38)
Wow: 2x (53:46, 53:46)
Nonsense: 1x (28:41)
Clever: 1x (53:37)
Fascinating: 1x (14:18)
By Sudoku: 1x (36:46)
Surely: 1x (42:09)
Puzzling: 1x (04:00)
Almost Interesting: 1x (29:43)
What Does This Mean?: 1x (41:36)
Nature: 1x (38:33)
Most popular number(>9), digit and colour this video:
Thirty Five (7 mentions)
Nine (93 mentions)
Green (3 mentions)
Antithesis Battles:
Low (2) - High (0)
Even (34) - Odd (26)
Higher (2) - Lower (0)
Column (22) - Row (12)
FAQ:
Q1: You missed something!
A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn!
Q2: Can you do this for another channel?
A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!
I just love how sometimes Simon jumps between parts of grid and missing his deductions from before.
@16:52 he forget about 9's in row 1/collumn 1 can be placed only at r1c5+r8c1 and r1c8+r5c1, completely removing 9's from center of two zippers.
Just got to 16:26 and I was thinking the same thing, especially as he has just deduced that 9 cannot be in the centre of both row 1/column 1 zippers so r8c8 cannot be a 9
@@Dale-hv4xi I noticed the same thing. I think it's a lot easier for us to spot these issues from the armchair rather than putting together all the rules while your brain is working hard doing the solve.
Also when he tries to put a 6 in r1c5 @20:29. He had already deduced that without a 9 in the zipper the constraint was even digits. So the zipper needs to have 4 odd digits on it and the only possible way to construct that is with 1357.
@@joelv4495 yeap, for 1 thing, that we saw and Simon missed, there are 9, that he saw and we missed
Your disentangling the zippers around the edge was fascinating, Simon. Thank you for this great video!
I love seeing your facial expressions whenever you find a logic deduction. Its like watching a child unpack a christmas present
Mr. Menace thank you very much for this puzzle. I cannot describe in words the joy I felt logically discovering what number goes where on the grid here. I took double the time than Simon but what a pleasure it was this discovering.
Exquisite puzzle, lots of fun deductions. At 38:54 there is another way to deduce how the first column and row go. Simon noticed that whichever digit goes to r1c1, its pair to make 9 is not on the zipper line in box 1. The same holds on the zipper line in row 1 or column 1, whichever has the 9 on the zipper. So in that row or column the pair of 4 or 6 must not go on the zipper. The pair of 4 or 6 is either 5 or 3, so this digit must go to either r1c8 or r8c1 as r1c9 and r9c1 must be even. But r1c8 sees both a 3 and a 5, so column 1 must be the zipper with the 9.
The eclipse was awesome! Truly awe inspiring. I saw it over a lake in a clear blue sky. It was so quiet....until I heard distant clapping and cheering from the forest all around me from others having the same experience.
My last deduction from row and col 1 was this: when you know the zippers are 8 and 9, they always have at least 3 odds on them (8 has 4 odds, 9 has 3). This means the row or col with 9 has to have two more odd digits - which cant be in the corners. Together with the fact that the row or column with the 8 has to have a 9 in the light green square (the 5th odd) - leads to the fact that both light green squares are always odd. This disambiguates where 8 and 9 zippers go, because there arent many odd digits available in r1c8.
I did this one all by myself, took me only 10 mns more than Simon!! And I filled the 8 and 9 rows without using the middle purple line! I'm a bit baffled actually. I even used all the right logic instead of hammering away at all pencilmarks I can think of. This will be a very good day surely! Thank you mr Menace for this journey in a puzzle, I even giggled at things like "well, both the cells are a one" in row and column one
It's lovely to see Simon guiding himself through the puzzle and noticing things he "missed" ^^
10:34 "If both of these were 9s..."
There's another way besides (and perhaps simpler than) the parity logic Simon gets to shortly to prove this cannot be the case - whichever of the marked 7 positions in box 1 is NOT 7 must sum to 9 with r1c1, since if it didn't its partner would be lonely on the zipper line. As such if the associated row/column 1 zipper line were a 9-sum the digit in r1c1 would repeat in the orange cell
lol I read that as paltry logic at first
😅I could not have worked this out on my own, but it was easy to follow Simon with his logic, and I enjoyed every one of his moments of insight.
Simon casually understanding that whichever zipper we put the 9 on the other can not have more than 1 even digit on it, and then goes on an entire tyrade about where 7 goes if 6 is in the middle even tho 6 would need 2-4 which he already proved is impossible :D
also love it when I make the same progress in 5 minutes as he does in 20, but get stuck for a whole hour after that :D
22:58
Clever opening that just cascaded into a full grid once the c1 and r1 zippers disambiguate. Beautiful and a pleasure to solve
25:32 For me, I was so mesmerised by the first row and column it took me 5 minutes before I placed 9 in box 1
I have been banging my head from the time he stated that 2 nines were in 2 of 4 spots that 1 of 2 spots looked at one spot for the 89 spot.
At 10.47 minutes you could already have concluded that R6C6 or R4C4 was a nine, because the 9 cannot be on the zipper. (''Where does 9 go in box 6?'' would have been the right question, I learned from you) At 47.11 min you would then automatically be sure that the 9 was in R6C6, or at 51.27 min, when the 9 was placed in R2C4. As it was, it became the penultimate number that you filled in, at 53.29! It's funny how you sometimes miss the obvious, but I would have missed out on the beautiful deductions that you came up with now. I assume it would have considerably shortened the video. But again....I'm not complaining! Beautiful puzzle, beautiful solve!
I got 58 minutes. Calculating the different values for the zipper lines in my head was a little bit challenging. but it was really fun to do so. This was a great puzzle!
0:53 I always needs to go listen to "Losing my Religion" to cleanse the palette after hearing the "3 in the corner" song. Mark gives it a valiant effort, but is not a singer, and Simon just giggles his way through it each time.
fascinating how long it took Simon to notice the middle square couldn't be 7. I think his brain works in such complicated mathematical ways these days, he has forgotten to scan.
He's just not used to the gift of Given Digits, he doesn't even see them.
How can it be that Simon almost instantly jumps to the question "where is the nine in column 1?" and then "where is the nine in row 1?" and next embarks on a far-fetched quest on symmetry without ever going up with the question of the nine in box 1.
16:05 for me. What an interesting puzzle, really enjoyed it!!
41:21 finish. I had a bit of a snafu in the middle, when I didn't think about what a few of my pencil marks meant. That caused an erroneous chain of events which lasted for a good 5-10 minutes. Fortunately it was an easy fix after rewind, and all of the logic I had done was still sound, just with different numbers. Brilliant!
Yay managed to solve this one! Took me 1:04:45. Don't usually solve sudokus much but I thought it was a worth a try without watching Simon :) I think this is the first zipper line sudoku I've ever solved but I've done a few odd/even parity ones too. I did get stuck a lot but I pulled through without turning to the video for hints.
23:49! Solve number 85. Great puzzle!
Twice as quick as Simon!. Ye ha! For once well and truly beaten. Once!. Just once!
Though I enjoy every puzzle on this channel, this one was simply spectacular. ❤❤❤❤ this puzzle.
18:00 you worked out the green cells can't both be 9 so since the only other place in row/column 1 for 9 would see the 89 in box 9 it has to be 8
Finished in 130:32, but I had to do a lot of mild bifurcation to see what worked and what didn't. Looking forward to watching to see what I missed.
An easy way to determine which way row 1 and column 1 go was to look at the 8th digit in each. They have to be 9 and 5. Then the 5s in box 9 give you which way round that row 1 and column 1 go.
The thinner zipper lines look great.
I thought it would be a fun challenge to try to make that zipperline rule more concise. Here goes:
The center of a purple line is the sum of pairs of cells equidistant from it.
It was a fun try, but hard for me. Needed some tips from the watch. Thank you for the solve! 😊
18:06 for me :)
After realizing there always has to be a 1 on the two straight zippers it was easy sailing🎉
There are a lot of elegant deductions to be made in this puzzle, and I mean a lot. No way is this a 3 star puzzle! That said, I probably did miss something. Very nice though, thanks.
To think it could be done this way. It completely feels a different puzzle. The end doesn't do just to the path.
To mute your buzzing phone, click on either of the volume buttons while it is buzzing. It will stop the rettet and the noise!
Some very interesting breakin logic to fill in those middle zipper digits i think 3-4 stars out of 5 is about right. took my just under 40 minutes to complete so certainly not the hardest of puzzles but not easy either
Closes box showing the real time it took to solve puzzle, only to check the recording time while asking how long it took to solve the puzzle - everytime!
43m20s. Not a whole lot to say about this one except that the deductions were delightful as always, and i like zipper lines.
Edit: No there is something to say! After having slept on it my mind came back to finding the 89 pair on the zipper centers on R1 and C1 and how that forced the R5C5 zipper center to be 5 or 6 and the feeling of... dread is not the right word, but that "oh gosh, what consequences is THAT going to have?" is a reaction I don't often feel and I cherish it
22:00 An easier way of seeing why that couldn't be 6 is because you would have too many even digits in c1 and r1. The corners are even, so that takes up 2 of the 4 even digits allowed. if the middle square is 6, than you would only be allowed 1 more even digit so the sums need to be dual-odds. the only odd numbers that add up to 6 are 1-5 and 3-3, but that last one is illegal.
I think the simplest path to seeing that the edge zippers take an 8,9 middle is that the nine and all but one even number are used up in the row/column, so the zipper is 1357 and a mystery even-so once you deduce that the even is in the middle, 1+3+5+7 = 2X.
Boy I’m gonna feel silly if it’s not 8.
Just wanted to say how much I love the shout outs and happy birthdays at the start of every video. You would think it's something you might skip through but I just love how genuinely appreciative you are of your followers and how lovely you are! Much love
when I made 89 center pairs for the two lines I completely forgot they could either be in either of the sides as a pair, so I took an extra 30 minutes to beat it, the double 3 for the 6 give away the order of 89 pair and the rest was just sudoku, really interesting.
I cracked this one by realising that r1c8 & r8c1 both had to be either 5 or 9 by running through the 8/9 zipper options. Then placed the 9 in r1c8 because of the positions for 5 in box 9.
Finished in 20:30 by following along with the video.
Finished in 71:41. I'm bad at zipper lines :(.
Fun puzzle!
38:54 A rare treat for me to be quicker than Simon.
So I'm a middle level player with Soduko and I love watching the channel. But for the first time (probably ever) I saw something before Simon. When he was talking about the 9's and was pointing out the middle row 1 or the middle column 1 I saw that affected 8R8C. Whoot whoot !!! I guess I'm getting better (nowhere near the master but still pretty good haha).
Around 15 minutes in, you're looking at box 9, completely oblivious to what you've just proved when considering box 1. That is, one of the straight lines is a 9, which prevents the other being 9, so one of R1C8, or R8C1 is 9, therefore the zipper in box 9 must be an 8.
@ 20:42 - "If it is 6..." - Seconds earlier you explained that the only even digit you can put on the line must be in the centre. Now you're trying to put 2 and 4 on the line as well! Those centre digits are an 89 pair, making the R5C5 either 5 or 6 (despite your best efforts, it could never be 7)
Your ability to forget what you've just worked out amazes me.
@ 22:04 - "It's so ridiculously complicated" - Only because you make it so. As explained above it's trivially simple.
Your "beautiful trick" to disambiguate the 5/6 line wasn't necessary. Sudoku would have given you that.
@ 45:18 - "I've run out of colours" - Why have you got any colours? The ones you've used are totally useless. If you can't remember that the digits on the edge form pairs, you really do have a problem.
Your utterly chaotic approach to sudoku baffles me. There's just no method to it at all, you just make one deduction, then look somewhere completely different. For instance, you got the 7 in R3C1, and instead of going down the column, where the next cell was a 78, and the one after that was an 89, you jumped to R1C3 and then filled in R1, eventually returning to C1. Even when you've placed a digit, let's say it was 2 at the bottom of the grid, and this resolves a 23 pair at the top, you'll point at the cell which sees the 2, but then click on the other of the pair, making it 2, before returning (sometimes) to click on the cell you originally pointed at to make it 3. You'll then completely forget to look at the second 2 you placed to see what difference it made. Instead, you look at the 3 and are surprised when it gives you nothing. If you first put the 3 in the cell which can't be 2, you can then click in the other cell which cannot now be 3, and then you can see what impact that has, which is quite likely to give you another 2 in a third column, or at least eliminate 2 from other cells in the same column. This is one of the main reasons you end up missing so much, because you jump forward, then step back, breaking the flow.
It's not that you miss stuff which bothers me, it's a live solve and you're bound to miss stuff. It's that you miss stuff because of how you work which bothers me. If you were logical and disciplined when filling in the grid, you would miss half of what you do. As you're a fan of logic, I don't understand why you eschew logic when filling in the grid.
Sorry for the rant, but this was a very shouty video.
R1C1 could be determined early because of that careful placement of the given 3, which eventually rules out R1C8 and R8C1. Therefore ask how you can put 3 on both the zipper lines?
Thanks Simon! I enjoyed the video as always.
24:25 Once you deduced that there was an even on the opposite zipper from the 9 zipper, I think you could’ve left the deduction of the 89 pair to the fact that the even digit had to go on the center along with 4 odd digits comprised of 1,3,5,7 = 16 / 2 = 8. Or did I miss something?
27:06 for me, nice and simple one today but lovely logic
Only 18:02 for me. Was able to quickly spot a few of the 9 positions. And then in box 1 with an odd total, there had to be 2 more evens on the equal distance lines. From there on the solve wasn't too difficult anymore.
Simmon you already said that one of r1c8 or c1r8 needs to be 9 so this gives you that box 9 center is 8.
23:30 The easier argument against the other center being 6 is that the row/column now has too many even digits. 6 requires 24, and the boxes require two more.
29:50 I bifurcated on 8 vs. 9 using cornermarks and centermarks for the two possibilities. The 5s in block 9 settled the choice.
Aaaaah, no threes in corners, but let's watch anyways ;).
how can you be sure so quickly?! ;-)
@@glum_hippoIsn't it obvious? Because Simon didn't sing!
@@glum_hippo Written in the stars? I felt it? I might have superpowers I guess, because I haven't seen any threes in corners anywhere ever since. I even checked under the curtains. Not even any football player with nr 3. on his/her back have been taking corners that I know of.
12:40 Sorry Simon, R5C1 and R1C5 can't both be nines - or both odd digits for that matter - since your argument proves that both R1C2 and R2C1 will then be odd and that's simply impossible because of the zipper line.
8:16 I agree, why didn't I see that straight away.
Classic Simon using crazy (but sound) logic to work out the middle of C1 or R1 can't be a 6. When in the sentence immediately prior to that logic he says, "If it's a 6, the other cells have to be 1-5 and 2-4." Which soaks up too many even digits. Always entertaining 😊
70:34 for me. Nice puzzle!
R1 and C1 are a lot simpler than Simon makes out, which is easier to see with case testing and just filling numbers in to see what happens. The middle of the zipper that isn't 9 can't be 6 because we've already worked out that the zipper can only have odd digits so it must be 1-3-5-7 with an 8 in the middle. Very clever puzzle but not too difficult if you just bash some numbers in rather than trying to fold too much in your head, finished in 25 minutes 👍🏻
For unreasons, I get a correct solution without entering a digit in r7c5, or entering any digit at all in r7c5.
Another shout at the screen episode where Simon starts a piece of logic then fails to see the obvious implications of it.
To be fair, no one expects to do sudoku on a sudoku puzzle
"but what if it's 6? Then where does 7 go?" Or, you know, 6 doesn't work because you'd need a 2 4 pair on the zipper and just said the last even goes in the center of that zipper.
"This is so complicated" "Only three stars for difficulty" implies "Ah, I must be doing it wrong"....
And how can you use a word like "Lacuna" without trying to make a pun with "Coil"...
Sigh. I fought with it for over an hour, then realized I was getting the line sums in B1 wrong, treating them like arrows rather than zippers. Unfortunately I don't have more time or energy to spend on this one. Oh well.
Nice puzzle! One curious thing is that I got the puzzle completed pop-up despite having one cell still pencil-marked (R7C5). I also got the screen after filling it in correctly and deleting the entry. The preemptive popup went away when I closed the tab and reopened. Not that it affected anything, just thought it was interesting
For some reason, the input solution doesn't appear to care what you put into the four cells r7c2, r7c5, r8c2, r8c4. Leave all four of those blank, and it still says it's a correct solution. Very strange.
if 6 was in either of the two green centre fields and 4, 2 was one of the sums adding to 6, plus two even numbers in the corners, that's 5 even numbers between 1 and 9.
For the first time in 3-4 months I manage to solve the puzzle in less time than Simon. Just wanted to flex, I usually take 1.5/2 times of his time
To be clear yes yes make another book :)
23:31 for me. I think I did really well on that one!
i thought i heard 'pizza' when he said peter XD but i do want a slice, so that might be why
This was the hardest puzzle i ever solved, took me about 100 mins. And i solved a few 4 star puzzles before. No way this is 3 stars. Amazing puzzle though.
16:16 solve time. Zippers still are confusing how they're not adjacent sums, but opposite end sums.
Ask yourself where 7 goes in box 5. To help answer that question remember that 7 can’t go on the central zipper. So 7 must be in column. 4 in box 2
Well Simon is seeing things that I didn't get to so early - so business as usual
Except for the 9s in row 1 and column 1 ruling 9 out of R8C8 because they can't both be zipper totals - which is what I focussed on first
This is the only sudoku with no chance of a three in the corner
24:00 for me. with this solve, im up to date again.
21:49 for me. Super easy, but still fun.
My break-in was completely different and MUCH easier. And I do mean incredibly easy.
We already know that if the center digit is an 8 along the first row or column, the 8th digit is a 9. This gets us the info in box 9 (ie. center cell of box 9 is an 8, etc.) similar to what was done in the video.
Now let's consider the case where the center digit is a 9 along the top row (we'll start with the top row for now). We are told there are two pairs that add up to 9 based on the zipper. That means the remaining 4 digits on the row must also pair up to add to 9 as two pairs. So what cell does the first cell (that can be a 4 or 6) pair up with? It's even. So it doesn't pair up with the 9th digit. And it cannot pair up with the second cell because that's on a zipper line that already adds to 9 with a different cell. So the only cell left is the 8th cell. The 8th cell MUST be 5 or 3 to pair up with the 6 or 4 in the first cell. But if we tried 3 or 5 in the 8th column, there are already 3 (given) and a 5 (in box 9) in use. So the 9 has to instead go in the middle of the first column. Along the top row in the middle is an 8.
Easy. Just look at the pairs that add up to 9, not just the pairs on the zipper but for the whole row. That's it.
Also if either is 6 then you run out of even digits for the squares in either row 1 or column 1.
Column 1 must have a 7 on the zipper (even if it's not box 1). So its value is 8 or 9.
the part I couldn't see is that anything other than 8/9 causes a problem in r1.
Simon, if you press the power button on your phone while it is ringing it will send the call directly to voice mail.
Is it even worth doing if I know I'm not going to get a song?
20:34. Or you can just say one way to make 6 is with 2 and 4, leaving only 8 to fill both corners. Simon does like to make things more complicated than they need to be, doesn't he?
now we need a constructor to make a puzzle with only 3s in the corners :)
25:23 solve for me. I feel smart
I think Simon got trolled. My first deduction was it is impossible to have 3 in the corner 🤪
@45:36 - he makes the claim ".. can't include 2's and 4's" ... but why not?
If the grey squares are 2 for example, they're compliments are 4. and r7c3 can be 4 and it's
compliment r3c6 can be 2 (while it's neighbors on the upper part are 4's ??)
this assuming r8c3 is a 1 and r2c6 is a 5 regardless.
But I'm not seeing how he can jump to r7c3 is a 3 so quickly? it could easily be the other 2 or 4 ?