Intersection of Two Planes in a Line Vector

Intersection of Two Plane in Three Dimension
Foot of Perpendicular: • Foot of the Perpendicu...
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[@dishateotia9611]

The way you explains everything very calmly is what I'm so thankful for sir . why the heck my teacher teaches at the speed of rajdhani express !

[@lawliet2263]

Rip inglisss 🤢

[@dharmrajprajapat9287]

Hii

[@karencovey7123]

Thank you Anil. You explain things so clearly. I am teaching myself Linear Algebra and had struggled with two different books and different examples. Then your video sorted it all out! You are a good teacher. Karen

[@shane3391]

Been suffering through these type of problems, your video just made things click for some reason! Thanks!

[@HeckMotelMusical]

You are a life saver Mr. Kumar!!!

[@sumitgarg1129]

By this method, we need not to find cross product of normal of planes and it is very easy.
Excellent sirji☺

[@rishavkumar3907]

You teach in a simple way.
Keep up and upload more videos please.

[@_sf_editz1870]

Everybody likes TH-cam teachers than Institute teachers because they teach for ranks they teach for passion

[@great9640]

you are the best one that explains this concept!!!!! the other youtubers make it complicated for nothing but you !! even explain the small details thanks so much!!!!!!!!!!!!!!!!!!!!!

[@Ppooh002]

Can i say x= 32/9 - 2/3t
Y=t
Z= 4/3 + 2/3t
Is this right?
I made x the subject and substitute in the other equation then made a variable a subject in which another variable was made t. Is this approach fine?

[@حسينالعالمي-ت7ز]

I am watching from iraq and thank you very match for you 🌹🌹🌹

[@siddharthsabharishankar7714]

awesome video...

[@ritankardas9925]

Sir we can also find the direction vector simply by finding the cross product of the normal vectors of the planes
Is it true?? ,sir

[@athena4838]

Thanks for the help!!

[@hentai6582]

Indians have always helped me when no one else would.

[@bonelesspizza6311]

why are you able to consider z to be a parametric variable? can you always choose/assume one of the variables to be a parametric variable? why are you allowed to substitute z for t?

[@undercover4874]

You can assume any variable for paramater

[@divyeonline3206]

Actually there is no need of introducing New parameter we can say z=z and find all variable in terms of z

[@lcchen3095]

Z equals z,ain’t gonna make any sense mate

[@dayghost379]

@@lcchen3095 he just mean why there is t? If there is nothing different between z and g except alphabet, mate

[@storytime-d4v]

Okay but if one has to deal with matrices we need that t .

[@thisenvinujitha2668]

good explain

[@t0145]

Thank you very much

[@fariznazmi6512]

AMAZINGGGGGG !!!!

[@present8409]

excellent

[@gatecsirnetmathematics773]

Thanks a lot sir.

[@protyayray2239]

Thanks sir ❤️

[@RiteshSingh-lp9nx]

Sir what will be the equation of intersection in terms of x,y,z??

[@MathematicsTutor]

Answer is given in vector and parametric form. x = -4 - t, y = -2 +3/2 t z = t

[@Tanu26557]

Sir I used the same method to find the eqn. of line of intersection between 2x+3y+2z=6 and 4x-3y+z=11 but the answer is not matching, I got the eqn as (0, -16/9, 17/3) + s(3,1,-9), can u plzz verify sir is my answer wrong or not. Thankz for the effort again😊.

[@MathematicsTutor]

Thanks for the question. Here is my solution. Eq. 2 + Eq. 1
6x + 3z = 17. Let x = t, then z = 17/3 - 2t. Substitute these values in Eq1 to get the answer.
(0, -16/9, 17/3) + t(1, -2/3, -2) or (0, -16/9, 17/3) + t(3, -2, -6)

[@bhaghisharma1134]

Tanushree Banerjee didi ish question mai z ke place pr g Kyu lgaya hai

[@bhaghisharma1134]

Tanushree Banerjee plz sis reply me

[@dharmrajprajapat9287]

Hii

[@haru4556]

Thank you sir. You help me a lot!

[@alipppalippp2948]

Thank u❤❤❤❤

[@atreyeesengupta3163]

Thank sir

[@deepakdiwakar881]

Sir this question plzzzz .The line of intersection of planes x+y-3z-3=0 and x-y+z-5=0 is

[@MathematicsTutor]

Since we have three unknown and two equations, we have to define a parameter to solve.
Let z = t
Add the two equations to get 2x - 2z = 8 or x - z = 4
Since we have taken z = t, x = 4 + t
Substitute these values in the given second equation to find y
y = x + z - 5 = 4 + t +t - 5 = -1 + 2t
L: r = (4, -1, 0) + t(1, 2, 1)
Hope that helps
Thanks

[@helping_hands_7]

Thank u sir

[@natnaellegesse1881]

Keep Sticking with simple problems

[@AkashRaj-vj6br]

Thank you ❤

[@bilalbhatti8750]

Thank you very much sir❤️❤️❤️❤️❤️❤️

[@yugalkishore8991]

Thank you

[@GauravSharma-yx3ki]

Can't we solve this using calculator?

[@shubhampatil7497]

Please add a notes

[@MathematicsTutor]

Thanks for suggestion. What kind of note are you looking forward to. Please suggest.
Thanks for your Feedback. Highly Appreciated.

[@abhaymishra7858]

@@MathematicsTutor only basic formulas and one or two conceptual question.....

[@MathematicsTutor]

@@abhaymishra7858 Here is the Playlist: th-cam.com/play/PLJ-ma5dJyAqoRm1pbdY4odhtS-tVLfOl4.html
Thanks

[@SHRISHYAMSARKAR99]

😂

[@johnfaustin2978]

Thank you so much