Thank you so much sir, I could not express my gratitude towards you. I got a call for interview from IIM Kozhikode and Cap interview. I self studied with your logics, thank you for making available such a great content free of cost. Hats off to you sir!🙏🙏
Sir please help me in solving the question i am unable to find it on google also and this category is not covered in your videos, A And B Can Do A Work In 16 Days A Alone Works FOR 8 DAYS AND B COMPLETES REMAINING WORK IN 20 DAYS BY WORKING ALONE. IN HOW MANY DAYS B CAN DO THE WHOLE WORK ALONE
SIr, can you help with the LCM method for this question: Q: John can constantly dig a hole at 15 inches per minute and LInda can dig at 45 inches per minute. A certain hole can be dug by John alone in 12 hours. If the hole is dug by john for half the time and then both together, how many minutes does it take to dig the hole? A. 288 mins I took the LCM of 15 and 45. John does 3 units of work and Linda does 1 unit of work. Total work is 12*60= 720 minutes. First half, john works alone = (360/3) = 120 minutes. And then both together 4 units of work = (360/4) = 90 mintues. Total time = 120 + 90 = 210. But ans is 288 minutes. Can you tell me where i went wrong?
Hi Rahul Understand the concept, we take LCM of number of days not the efficiency and that LCM is our total work Here Efficiency is already given and information to calculate total work is also given ( Total work done if John works = 12inch/min *60min *12hrs = 10800 inches) Now let they finish the work in 2Tmins ( I have not take T because by taking 2T calculation will be easy) John Work for half time and they both work for another half time Work done by John in T mins = 15T Work done by both in another T mins = (15+45)T= 60T Total work done by both = 15T + 60T= 75 T 75T = 10800 T= 144 So total time (2T) = 288mins To avoid calculations 15*60*12 can be equated to 75T
thank you very much sir!!
I dont think anyone can simplify this topic in more detail! Sir, your explaination is really awesome :)
Wow Sir!!
LCM Method is very Easy and Effective....
I always used to get confused via Formula.....
THANK YOU SO MUCH....👍👍✔
The shortcuts shown here are so amazing 😍
Thanks for easy and fast methods sir : )
Superb Explaination😍. Everything I was understanding at a one go...🤩
Glad to hear that :)
wow, you are really a very good teacher.
Thanks Ritika
Thank you so much sir, I could not express my gratitude towards you.
I got a call for interview from IIM Kozhikode and Cap interview.
I self studied with your logics, thank you for making available such a great content free of cost. Hats off to you sir!🙏🙏
Please share statistics videos for gre as soon as possible.... Sir your all tricks is very easy and helpful
Sir please help me in solving the question i am unable to find it on google also and this category is not covered in your videos, A And B Can Do A Work In 16 Days A Alone Works FOR 8 DAYS AND B COMPLETES REMAINING WORK IN 20 DAYS BY WORKING ALONE. IN HOW MANY DAYS B CAN DO THE WHOLE WORK ALONE
40 days
Sir you have literally opened my way of thinking! Agar main ladki hota toh aapse shaadi karleta
😂😂Hahahah 😄🙏
SIr, can you help with the LCM method for this question:
Q: John can constantly dig a hole at 15 inches per minute and LInda can dig at 45 inches per minute. A certain hole can be dug by John alone in 12 hours. If the hole is dug by john for half the time and then both together, how many minutes does it take to dig the hole?
A. 288 mins
I took the LCM of 15 and 45. John does 3 units of work and Linda does 1 unit of work. Total work is 12*60= 720 minutes. First half, john works alone = (360/3) = 120 minutes. And then both together 4 units of work = (360/4) = 90 mintues. Total time = 120 + 90 = 210. But ans is 288 minutes. Can you tell me where i went wrong?
Hi Rahul
Understand the concept, we take LCM of number of days not the efficiency and that LCM is our total work
Here Efficiency is already given and information to calculate total work is also given ( Total work done if John works = 12inch/min *60min *12hrs = 10800 inches)
Now let they finish the work in 2Tmins ( I have not take T because by taking 2T calculation will be easy)
John Work for half time and they both work for another half time
Work done by John in T mins = 15T
Work done by both in another T mins = (15+45)T= 60T
Total work done by both = 15T + 60T= 75 T
75T = 10800
T= 144
So total time (2T) = 288mins
To avoid calculations
15*60*12 can be equated to 75T
@@aptifyy Thank you so much for the reply sir :) Got the concept.