Why do I keep getting electricity questions wrong?

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ความคิดเห็น • 26

  • @venukahansana5709
    @venukahansana5709 ปีที่แล้ว +5

    its about 4AM rn and these sirens sure keep me awake, Thanks for the video!!!!

  • @saferehman8234
    @saferehman8234 3 ปีที่แล้ว +27

    Wow youre trying to break my ears with that siren 😂😂 nice video though thanks

  • @victorotene
    @victorotene 5 ปีที่แล้ว +23

    Please remove that siren or reduce the volume in future videos. However, excellent video, thanks.

    • @inthebackwiththerabbish
      @inthebackwiththerabbish 5 ปีที่แล้ว +11

      Nah that siren gives me life

    • @queenm.a707
      @queenm.a707 ปีที่แล้ว +1

      Makes me just want to leave the video, but I have an exam tomorrow 🥲

  • @abdulmonam1490
    @abdulmonam1490 2 ปีที่แล้ว +4

    this video was a nightmare for people in hiroshima

  • @an5i910
    @an5i910 ปีที่แล้ว +1

    7:09 if we put 0.66 on the top, wouldn't that give v.drop of the combined resistance I.e 0.666 and not the v drop of the 1 ohm resistor. However, question wants v.drop across 1 ohm resistor

    • @burrowsphysics
      @burrowsphysics  ปีที่แล้ว

      Those two things are the same. Remember they are in parallel so the potential difference across each / both is the same so the P.D across the 1 ohm is the same as the p.d across the 2 ohm is the same as the p.d across the combination.

    • @an5i910
      @an5i910 ปีที่แล้ว

      So 0.87 is p.d across 1 ohm and 2 ohm resistor as they are in parallel, thank you for helping

  • @nawfaljafri
    @nawfaljafri 2 ปีที่แล้ว +2

    questionn,
    @14:40 why are you subtracting the voltage across them by 100V (the emf im guessing), doesnt that give the voltage that is left? becaus withouht subtracting form hundred, we already got the voltage across the resistor we chose, isnt that how the formula works?

    • @burrowsphysics
      @burrowsphysics  2 ปีที่แล้ว +2

      So I'm not trying to calculate the potential difference across a resistor, I'm trying to work out the voltage at A and at B to then find the difference between them. By calculating the potential difference across the 120 ohm resistor and subtracting it from the EMF, you calculate the voltage (energy each coulomb has at a specific point) in this case A.

    • @nawfaljafri
      @nawfaljafri 2 ปีที่แล้ว +2

      @@burrowsphysics ahhh i see!! thankyou so mcuh for all the replies uve given recently to me even though i asked quesiotns under videos here adn there multiple times in the span of like 3 days, adn that too so quickly, really helping me out for my finals prep

  • @VK-il9kv
    @VK-il9kv 4 ปีที่แล้ว +4

    please do more of these hard questions thanks

  • @pwei1577
    @pwei1577 5 ปีที่แล้ว +5

    Yes Mr burrows ur such a legend

  • @phobiatheory3791
    @phobiatheory3791 5 ปีที่แล้ว +3

    Honestly helped me so much, thank you

  • @saraahmed632
    @saraahmed632 4 ปีที่แล้ว +1

    Such a helpful video, Thanks!

  • @h0197
    @h0197 5 ปีที่แล้ว +4

    Damn only if this was made 2 weeks ago but kudos thanks

  • @inthebackwiththerabbish
    @inthebackwiththerabbish 5 ปีที่แล้ว +2

    Hi sir thanks for all the help :)

  • @Eric-dw2vd
    @Eric-dw2vd 3 ปีที่แล้ว

    Does anyone know what to do when finding combined resistance of a 0 ohm resistor in parallel as you can't divide by zero? Do you just ignore all the other resistors in that parallel configuration and just take the combined resistance to be zero?

    • @burrowsphysics
      @burrowsphysics  3 ปีที่แล้ว +5

      That is called a short circuit. The circuit acts as if that resistor isn't there so yes you treat their combined resistance as zero

  • @ochachako
    @ochachako 3 ปีที่แล้ว +1

    is this really GCSE level? bc i'm struggling sm with this

    • @burrowsphysics
      @burrowsphysics  2 ปีที่แล้ว +1

      I would say very top end of GCSE / A level sort of level

    • @ochachako
      @ochachako 2 ปีที่แล้ว

      @@burrowsphysics okay thanks!

  • @simrannahar8262
    @simrannahar8262 2 ปีที่แล้ว +1

    such a helpful intuitive insight, thank you so much!