In the last one I did (3^5) is equal to =243 and (3^3) =27. Therefore, (3^3)^x where x makes it so that it equals 3^5. Therefore x is 5/3. Then we add a negative symbol because we are looking for the reciprocal and then plug x into the equation to get 3^-2 or 1/9.
Hello there GRE Ninja Tutorin - at the beginning, you mention an exponent basics video linked below, but many of us dont see the link - we'd appreciate it if you can post it!
Because you multiply in an X form. Multiply 2^n with the number above 500 (numerator), and then 500 with the number above 2^n (numerator). So it it 2^n * 1 = 1 * 500 but the signs are opposite
Hi sir In question 2....for quantity A we can write 12/3^1/2 as (2 * 3^1/2)/(3^1/2) if we simplify that the result is 2 and for quant B i can write 8/2^1/2 as (2 * 2^1/2)/(2^1/2) and if we simplify that then i can get same 2 as result. So both quant A and B are equal right?
to compare x*racine(y) and a*racine(b) without using calculator, you should try to simplify so that there number in the racine or outside in the two expressions are the same, same for having + or - in * place, same for expononet in place of racine
IF YOU CANT WRITE EXPONENTS EXPRESSIONS WITH SOMETIHGNG IN COMMON? and want to compare two numbers, youcan trry small numbers and big enough big numbers, if it changes with different numbers then D
You lost me on " X is an integer greater than 2. He found that the smaller the number the answer was A but as it got larger it switched to B. Finding this he chose answer D? D wasnt an option, at least not in the question we were given?
@@shanedepoe4798 These are GRE's Quantitative Comparison questions. The following excerpt is taken from the ETS web page linked at the bottom of this message: "These questions ask you to compare two quantities - Quantity A and Quantity B - and then determine which of the following statements describes the comparison. (A) Quantity A is greater. (B) Quantity B is greater. (C) The two quantities are equal. (D) The relationship cannot be determined from the information given." In the two questions you asked about, Alex showed that there are scenarios consistent with the information provided in which quantity A is larger than quantity B, and there are other scenarios consistent with the information provided in which quantity B is larger than quantity A. Since we cannot determine which quantity is greater, the relationship cannot be determined and the answer to these questions is (D). For more on how quantitative comparison questions work, check out this webpage: www.ets.org/gre/test-takers/general-test/prepare/content/quantitative-reasoning.html#accordion-eb7b696bc8-item-a0c181a566 I hope that helps!
in the second question, can you raise the denominators to half and then separate the half (eg 3^(1/2)= 3^1 / 3^2), then transfer the denominator of the denominator to the numerator? complicated but quick?
Sadly, you can't do this. Let's use another example to demonstrate why: if we were trying to find the square root of 16, we could set this up as 16^(1/2) which equals 4. However, if we were to do what you suggest, we would say that 16^(1/2) = 16^1 / 16^2 = 16 / 256 = 1/16 which definitely does not equal 4. It's a nice thought, and it would be lovely if it worked out, but your suggestion breaks a few rules of algebra. I hope that helps!
The solution to the last question does not sit with me well. I solved for X and arrived at -5/3 which I then substituted in the other part to get 9 or was that a wrong approach? Please I need clarity
You've got the correct solution for X. There must be a problem after that stage, and I suspect this issues is that you've lost a negative sign somewhere. Once you substitute X = -5/3 into 3^(3X + 3) you should get 3^(3(-5/3)+3) = 3^(-5 + 3) = 3^(-2) = 1/9. I hope that helps!
In terms of the content itself, yes: you can think of this as a complete, free GRE video course that covers everything you really need. The hitch, of course, is that you'll still need to put everything we teach into practice. So you'll need to do plenty of practice questions and exams, ideally from official GRE materials. You'll need to figure out how to execute with consistency -- for example, careless errors or bad time management can demolish your score, even if you "know everything" already. But yeah: we'll teach you everything you really need on this channel. It's just that it's up to you to use all of the information effectively on test day. :) I hope that helps a bit, and have fun studying!
This is a great question, and it all comes down to the notation you use. For the purposes of the GRE, when you go from x^2 = 4 to finding x, you'll get two answers: +2 and -2. However, when you're presented with sqrt(4), in the same format as in Q2, then it's implied that you're looking for the positive root. So, you can think of sqrt(4) as +sqrt(4), and it's only when you want to go from x^2 = 4 to x = ±2 that you need to find both roots. I hope that helps! For more information, check out this page: en.wikipedia.org/wiki/Square_root
Question 5 is explained in the video starting at about 28:40. Check it out and please let us know if you have any further questions. I hope that helps!
@@teresac7356 Keep in mind that the question is asking about the "smallest value of n." While it's true that 1/2^10 is smaller than 1/2^9, that's not exactly what the question is asking. Since we want to know the smallest value of n itself (and 9 is smaller than 10), the correct answer is C. Let me know if that helps clarify things!
In the last one I did (3^5) is equal to =243 and (3^3) =27. Therefore, (3^3)^x where x makes it so that it equals 3^5. Therefore x is 5/3. Then we add a negative symbol because we are looking for the reciprocal and then plug x into the equation to get 3^-2 or 1/9.
Best video over. Your steps are out of this world
At the beginning, you mention an exponent basics video linked below, but I do not see one. Could you please post that link? Thanks!
It has been 4 months. Did you give your gre till now? If yes then what was your score?
th-cam.com/video/MuGMKG2BrPY/w-d-xo.html
I recommend this video by the tested tutor on TH-cam :)
@@prem_patel7 Still studying -- I will let you know!
For me it’s the opposite
I found the last one of the easiest.
They don't provide a link, however I used this video to and it was an efficient refresher th-cam.com/video/LkhPRz7Hocg/w-d-xo.html
Hello there GRE Ninja Tutorin - at the beginning, you mention an exponent basics video linked below, but many of us dont see the link - we'd appreciate it if you can post it!
Thanks for sharing this video🎉
Some basics about Question 5 - Do we always flip the inequality sign when you take the reciprocal of a fraction?
Because you multiply in an X form. Multiply 2^n with the number above 500 (numerator), and then 500 with the number above 2^n (numerator). So it it 2^n * 1 = 1 * 500 but the signs are opposite
The question around' 39:40 is a deadly one , for every possible mistake there is an answer
Hi sir
In question 2....for quantity A we can write 12/3^1/2 as (2 * 3^1/2)/(3^1/2) if we simplify that the result is 2 and for quant B i can write 8/2^1/2 as (2 * 2^1/2)/(2^1/2) and if we simplify that then i can get same 2 as result. So both quant A and B are equal right?
where's the link below the video he mentioned at the beginning?
to compare x*racine(y) and a*racine(b) without using calculator, you should try to simplify so that there number in the racine or outside in the two expressions are the same, same for having + or - in * place, same for expononet in place of racine
0.2=1/5 and 0.002=1/500
IF YOU CANT WRITE EXPONENTS EXPRESSIONS WITH SOMETIHGNG IN COMMON? and want to compare two numbers, youcan trry small numbers and big enough big numbers, if it changes with different numbers then D
You lost me on " X is an integer greater than 2. He found that the smaller the number the answer was A but as it got larger it switched to B. Finding this he chose answer D? D wasnt an option, at least not in the question we were given?
the following question is the same situation where the answer turns out to be neither A or B so he just pick a non existent answer D. What is D?
@@shanedepoe4798 These are GRE's Quantitative Comparison questions. The following excerpt is taken from the ETS web page linked at the bottom of this message:
"These questions ask you to compare two quantities - Quantity A and Quantity B - and then determine which of the following statements describes the comparison.
(A) Quantity A is greater.
(B) Quantity B is greater.
(C) The two quantities are equal.
(D) The relationship cannot be determined from the information given."
In the two questions you asked about, Alex showed that there are scenarios consistent with the information provided in which quantity A is larger than quantity B, and there are other scenarios consistent with the information provided in which quantity B is larger than quantity A. Since we cannot determine which quantity is greater, the relationship cannot be determined and the answer to these questions is (D).
For more on how quantitative comparison questions work, check out this webpage:
www.ets.org/gre/test-takers/general-test/prepare/content/quantitative-reasoning.html#accordion-eb7b696bc8-item-a0c181a566
I hope that helps!
in the second question, can you raise the denominators to half and then separate the half (eg 3^(1/2)= 3^1 / 3^2), then transfer the denominator of the denominator to the numerator? complicated but quick?
Sadly, you can't do this. Let's use another example to demonstrate why: if we were trying to find the square root of 16, we could set this up as 16^(1/2) which equals 4. However, if we were to do what you suggest, we would say that 16^(1/2) = 16^1 / 16^2 = 16 / 256 = 1/16 which definitely does not equal 4.
It's a nice thought, and it would be lovely if it worked out, but your suggestion breaks a few rules of algebra.
I hope that helps!
The solution to the last question does not sit with me well. I solved for X and arrived at -5/3 which I then substituted in the other part to get 9 or was that a wrong approach? Please I need clarity
You've got the correct solution for X. There must be a problem after that stage, and I suspect this issues is that you've lost a negative sign somewhere.
Once you substitute X = -5/3 into 3^(3X + 3) you should get 3^(3(-5/3)+3) = 3^(-5 + 3) = 3^(-2) = 1/9.
I hope that helps!
Is this Playlist enough to give the gre exam to get a good score
In terms of the content itself, yes: you can think of this as a complete, free GRE video course that covers everything you really need.
The hitch, of course, is that you'll still need to put everything we teach into practice. So you'll need to do plenty of practice questions and exams, ideally from official GRE materials. You'll need to figure out how to execute with consistency -- for example, careless errors or bad time management can demolish your score, even if you "know everything" already.
But yeah: we'll teach you everything you really need on this channel. It's just that it's up to you to use all of the information effectively on test day. :)
I hope that helps a bit, and have fun studying!
In the second question, doesn’t square root of 4 = + or - 2?
This is a great question, and it all comes down to the notation you use.
For the purposes of the GRE, when you go from x^2 = 4 to finding x, you'll get two answers: +2 and -2. However, when you're presented with sqrt(4), in the same format as in Q2, then it's implied that you're looking for the positive root. So, you can think of sqrt(4) as +sqrt(4), and it's only when you want to go from x^2 = 4 to x = ±2 that you need to find both roots.
I hope that helps!
For more information, check out this page:
en.wikipedia.org/wiki/Square_root
@@GRENinjaTutoring Thanks
in question 5, how answer is c) 9?
please reply
Question 5 is explained in the video starting at about 28:40. Check it out and please let us know if you have any further questions.
I hope that helps!
@@GRENinjaTutoring Hi, why wouldn't it be D) 10? Isn' that an even smaller integer than 9?
@@teresac7356 Keep in mind that the question is asking about the "smallest value of n." While it's true that 1/2^10 is smaller than 1/2^9, that's not exactly what the question is asking. Since we want to know the smallest value of n itself (and 9 is smaller than 10), the correct answer is C.
Let me know if that helps clarify things!
It’s about the smallest Integer n and not the whole fraction.
Except last question i solved everything it made feel like i can make 325+
That last one is indeed pretty hard. :)
Have fun studying, and please keep us posted on your progress!