Try to solve the question with lecture or after understanding lecture..you will come to know resistance is in kohm because 110 total current is in miliampere.
@@vaibhavjain3854 sir I have checked but still not able to understand like mili amp = 10^-3 4.8/110×10^-3 = approx 43.5 and exact 43.63 please explain
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amazing teacher
Best electronic channel and teacher
Best explanation...sir ji
Thankyou so much.....
sir why have you taken maximum load current for minimum zener diode current?
See the lecture again and understand the concept and relation between load, zener and supply current.
@@vaibhavjain3854 sorry sir but unable to understand this thing
@@sanyamtyagi5578 koi baat nai sbhi topic samjhne k liye nai hote...trick dekh lo kynki question aata h iska in paper.
good presentation
Shukriya
Sir app kon se collage mai padhate hai
ABESIT
Sir,
U have done a very good work for us
I am from ABESEC🎉
@@gagansharma5011 kha hai college
@@saurabhmaurya2805 GHAZIABAD
Awesome explanation sir...... Just make one video more on this to cover more question
Very nice sir ji
At 20:45 Sir the value of R should be in ohms not in kilo ohms
20:47 resistance is 43.5 ohm so why changed to K-ohm
Try to solve the question with lecture or after understanding lecture..you will come to know resistance is in kohm because 110 total current is in miliampere.
@@vaibhavjain3854 I saw it was 4.8V/110mA so it becomes 43.5 ohm
@@divyanshgoel09 what is the power for mA? This shows that you have not studied previous lectures carefully.
@@vaibhavjain3854 sir I have checked but still not able to understand like
mili amp = 10^-3
4.8/110×10^-3 = approx 43.5
and exact 43.63
please explain
@@divyanshgoel09 you are right R is 43.5 ohm only
Sir microprocessor and microcontroller ka video se kar digya sir gi
Nice
sir jab VL >VZ ie ( second conditions in 1 st question ) toh aapne zener diode ke direction ko change Kyo kar diya
Because zener works in reverse bias condition.