Okay, but i dont understand why the perpendicular force of the friction is sin and not cos. The force of friction is on the end of the ladder, which does not make sense to why you drew it just above. It seems you could draw all the forces on the ladder with sin being the perpendicular. (it seems your just shifting the components around)
Plz make a video on this following problem. A cannon of mass M rests on a horizontal plane having coefficient of friction k. It fires a projectile of mass m with muzzle velocity v in a direction making angle "a" with the horizontal. Determine how far back the cannon will move due to the recoil. Thanks,
You could use conservation of momentum to find the backward horizontal momentum the cannon gets upon firing (using trigonometry). Then, as kinetic energy = P^2/2m, equate this kinetic energy with frictional energy loss to find distance travelled since you know the reaction force that the ground exerts on the cannon.
There is a force on the painter but I’m not interested in the painter. I’m looking at all the forces on the ladder. There are only 2 forces on the painter, the weight of the painter and the normal force from the step on the painter. Both forces are in the y-direction. The force from the ladder is not perpendicular to the ladder. If this was the cases the painter would not be in equilibrium.
what would you do if the full ladder length was given? I've got the same problem except I have to solve for the coefficient of static friction between the ladder and the ground.
my question is which force is responsible for slipping off the rod as there is no force acting left side of the bottom of the rod also there is no component of gravitational force acting. So, which force moves the bottom-most point towards the left for slipping.
why is the normal force not pointing normal to the edge that is at the floor? i thought that in that case, it should be pointing normal to the ladder, instead of the floor
The normal force is produced by the floor and acting on the ladder. The normal force is always perpendicular to the surface that is producing the force.
Hello , Could you please help me and say where I can find these questions or similar questions of physics? Please tell me a website or book or source! Everything that You tink can help me... Thanks!❤️
![ILLSLICK - KILLSHOT REMIX [FULL VERSION]](http://i.ytimg.com/vi/RIK8RrqIAzE/mqdefault.jpg)
Could I just say that your videos are wonderful. Every time I want an explanation for something I learned, physics ninja is around. Thank you :)
Thank you so much!
Okay, but i dont understand why the perpendicular force of the friction is sin and not cos. The force of friction is on the end of the ladder, which does not make sense to why you drew it just above. It seems you could draw all the forces on the ladder with sin being the perpendicular. (it seems your just shifting the components around)
You are a genius sir. Your video is so much cool than any other video I watched before. Make many video with problem.
Thanks a lot sir, helped me alot!❤
Love from India!
Thanks. Helped me a lot with a similar problem.
Glad it helped
Did anyone watch because they were told to watch on remote learning?
Plz make a video on this following problem. A cannon of mass M rests on a horizontal plane having coefficient of friction k. It fires a projectile of mass m with muzzle velocity v in a direction making angle "a" with the horizontal. Determine how far back the cannon will move due to the recoil. Thanks,
nice problem! I"ll try to put something together soon. I'll add it to my queue.
You could use conservation of momentum to find the backward horizontal momentum the cannon gets upon firing (using trigonometry). Then, as kinetic energy = P^2/2m, equate this kinetic energy with frictional energy loss to find distance travelled since you know the reaction force that the ground exerts on the cannon.
THANK YOU FOR THIS VIDEO! SUPER HELPFUL
This statics problem is from classical mechanics book written by David Morin!
Actually, this problem has been around for several hundred years.
Thanks a lot sir, this video was really helpful
really, outstanding..
Hi! Why does the painter not have a reaction force perpendicular to the ladder?
There is a force on the painter but I’m not interested in the painter. I’m looking at all the forces on the ladder. There are only 2 forces on the painter, the weight of the painter and the normal force from the step on the painter. Both forces are in the y-direction. The force from the ladder is not perpendicular to the ladder. If this was the cases the painter would not be in equilibrium.
what would you do if the full ladder length was given? I've got the same problem except I have to solve for the coefficient of static friction between the ladder and the ground.
Tank u so much sir keep it up am from africa
Thank you!
Can this example be extended for motorcycle lean angle?
Yes, similar type of problem
Awesome application 😊
my question is which force is responsible for slipping off the rod as there is no force acting left side of the bottom of the rod also there is no component of gravitational force acting. So, which force moves the bottom-most point towards the left for slipping.
Hi, in your udemy course you found theta max, but maybe you meant theta min... Right? Thanks! 😊
Thank you for the video ! I don't understand why the painter wouldn't have a normal force tho, can someone explain?
There is definitely a force on the painter, but in this problem we are looking at the forces on the ladder, not the painter.
@@PhysicsNinja Got it, thank you so much ! 😀
Why didn't u calculate the torque from the lower end of the ladder that would have been much easier
yes, but the method is the same.
Amazing!
My apologies as was viewing the torque from the bottom of the ladder.
Thanks so much!!
why is the normal force not pointing normal to the edge that is at the floor? i thought that in that case, it should be pointing normal to the ladder, instead of the floor
The normal force is produced by the floor and acting on the ladder. The normal force is always perpendicular to the surface that is producing the force.
Hello ,
Could you please help me and say where I can find these questions or similar questions of physics?
Please tell me a website or book or source!
Everything that You tink can help me...
Thanks!❤️
My physics class uses Texas EDU online for problems. You can also find IB physics practice test pdfs online
N and fs forces must be zero because it is actting on the hang.
how to find the maximum angle?
You have really screwed up my mind with your assignment of the direction of torques as it is counter intuitive
Lol, pretty straightforward. CCW positive, CW negative.
tyvm
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