Calculus BC - 10.9 Determining Absolute or Conditional Convergence

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  • เผยแพร่เมื่อ 16 พ.ย. 2024

ความคิดเห็น • 8

  • @darcash1738
    @darcash1738 ปีที่แล้ว +4

    useful tip for speed on some mcqs: approaching infinity, n^c < c^n < n! (c is a constant not in [-1, 1] bc otherwise it'd be getting smaller approaching infinity).

  • @lwcky8929
    @lwcky8929 8 หลายเดือนก่อน +2

    I was sick during the day we covered this and could not figure out for the life of me how to do problems like 4 & 5. finally decided to look into it before the test and finally understand it better.

  • @mozazoom2751
    @mozazoom2751 2 ปีที่แล้ว +3

    Thank you for this helpful video, I'm wondering when you will upload the next lesseon video?

  • @ethanwho_
    @ethanwho_ 8 หลายเดือนก่อน +1

    how come in problem 2 you negated the (-1)^n+1 for alternating series test when taking the limit but in problem 3 you added the (-1)^n when u took the limit? i thought you said you suppose to leave out the alternating part. maybe in problem 3 u arent using alternating test and im just mistaking it but then what test are u using if ur taking the limit of that entire alternating series?

  • @m.al7arbi465
    @m.al7arbi465 2 ปีที่แล้ว

    In the last question which is 5 , isn’t it supposed to be ( conditionally converges ) at x=2 since the series diverges there ? Why did you choose x=0 although it converges there .

    • @JorgeHernandez-fi2lc
      @JorgeHernandez-fi2lc 2 ปีที่แล้ว +5

      The series is absolutely convergent from (0,2) but that does not include the endpoints 0 and 2 because the limit in the ratio test converges when its less than 1 (not less than or equal to). The endpoints would technically be divergent. That's why when he plugs in 0 it is conditionally convergent and when he plugs in 2 it is fully divergent.
      Hope that made sense

  • @CoreFlax
    @CoreFlax 2 ปีที่แล้ว +2

    Algebros