Hi! Glad you asked! No, you don't need statistics foundations, we'll provide you with those within our courses. If you have any other course information related queries, please do not hesitate to contact us at support@aihr.com. Have a nice day!
Thank you for this very good video. The explanation of the concept was easy to understand, and the 3 examples cited were relevant and simple to comprehend.
Hi @Sudakshina! Thank you for your kind request, we are very happy to see PhD-level interest in the field of HR! Here's a link to our online repository where you can find academic sources that shall help you further pursue your interest in the field: www.analyticsinhr.com/people-analytics-resources-repository/ Hope to have helped you sufficiently and wishing you a great day, Nastasia from AIHR
Hi @Carlos! So, here it goes: Without making calculations, the sequences are identical except for order for the first five rolls. Consequently, these sequences have the same probability up to and including the first five rolls. The second and third sequences must now be less probable than the first, as an extra roll, with probability less than one, is involved. Hence the first sequence is the most probable. The calculation requires the notion of independence. Two methods. Firstly, work out the probabilities for the sequences: The probability of a red on an individual roll is 2/6 = 1/3 and the probability of green is 4/6 = 2/3. Hence, since successive rolls are independent, the probability of the first sequence is 1/3 * 2/3 * 1/3 * 1/3 * 1/3 = 2/243 = 0.0082 Similarly, the probabilities of the other two sequences are 1/3 * 2/3 * 1/3 * 1/3 * 1/3 * 2/3 = 4/729 = 0.0055, while the probability for the third sequence is: 2/3 * 1/3 * 1/3 * 1/3 * 1/3 * 1/3 = 2/729 = 0.0027. Out of these three, the first sequence is the one with the highest probability, and there you go, that's why number 1) is the correct answer! Hope that answers your question :-) Have a productive week and a relaxing weekend! Nastasia from AIHR
It's a shorter sequence and a superset of #2. The example is a little misleading in that it covers conditional probability and not probability of equal events (6 roll events). It's a numerical equivalent of the the Conjunction Fallacy, as I see it. en.m.wikipedia.org/wiki/Conjunction_fallacy
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fluently explained.very helpful
...
What are the technical courses u suggest for HR analytics sir??
Exaplanation is simple and understandable..tq
Hi Shabreen! We offer several courses about HR analytics, which you can find here: www.aihr.com/courses/hr-analytics/
Thank You,... this was helpful..
HR Analytics is the application of analyzing the past data in present for achieving future organization goals.
Great explanation! Dankjewel ;)
Very nicely explained the points
Do you need to have statistics foundation before taking these courses?
Hi! Glad you asked! No, you don't need statistics foundations, we'll provide you with those within our courses. If you have any other course information related queries, please do not hesitate to contact us at support@aihr.com. Have a nice day!
Thank you for this very good video. The explanation of the concept was easy to understand, and the 3 examples cited were relevant and simple to comprehend.
Hi Siao Ping Luo, and thank you! We are thrilled to hear that you found the video valuable!
Really helpful! Thank you for creating these contents and for having AIHR! Big thanks! So insightful and just amazing! 😊
Great to hear you find our videos helpful, John! Happy learning!
Best,
Betty from AIHR
VERY HELPFUL AND INFORMATIVE
Very very insightful. Thank you very much.
Great Sir, please do make some research related videos on hr analytics at the Phd level so that we can benefit, AND once again thanks a lot
Hi @Sudakshina! Thank you for your kind request, we are very happy to see PhD-level interest in the field of HR! Here's a link to our online repository where you can find academic sources that shall help you further pursue your interest in the field: www.analyticsinhr.com/people-analytics-resources-repository/
Hope to have helped you sufficiently and wishing you a great day,
Nastasia from AIHR
Could you explain mathematically why answer 1 is the right one? The sum of each probability, the answer two is bigger!
Hi @Carlos! So, here it goes:
Without making calculations, the sequences are identical except for order for the first five rolls. Consequently, these sequences have the same probability up to and including the first five rolls. The second
and third sequences must now be less probable than the first, as an extra roll, with probability less
than one, is involved. Hence the first sequence is the most probable.
The calculation requires the notion of independence. Two methods. Firstly, work out the probabilities for
the sequences: The probability of a red on an individual roll is 2/6 = 1/3 and the probability of green
is 4/6 = 2/3. Hence, since successive rolls are independent, the probability of the first sequence is
1/3 * 2/3 * 1/3 * 1/3 * 1/3 = 2/243 = 0.0082
Similarly, the probabilities of the other two sequences are 1/3 * 2/3 * 1/3 * 1/3 * 1/3 * 2/3 = 4/729 = 0.0055,
while the probability for the third sequence is: 2/3 * 1/3 * 1/3 * 1/3 * 1/3 * 1/3 = 2/729 = 0.0027.
Out of these three, the first sequence is the one with the highest probability, and there you go, that's why number 1) is the correct answer!
Hope that answers your question :-)
Have a productive week and a relaxing weekend!
Nastasia from AIHR
It's a shorter sequence and a superset of #2. The example is a little misleading in that it covers conditional probability and not probability of equal events (6 roll events). It's a numerical equivalent of the the Conjunction Fallacy, as I see it. en.m.wikipedia.org/wiki/Conjunction_fallacy
Should have added ... for example RRR is also more common than RGRRR.
Thanks a lot 😘🥰😊☺😚
Does one have to be an HR professional to do any of the analytic courses?