Bro you know what.. Sabse accha best friend app aur apki team hi hai mera.. You all guys put efforts to make understand and clear all my concepts.. Thanx my friends 😊
Mast bhai ek bar me samajh me aa gya.... And safe state is New available 3,14,12,12... And after grant the request of p1(0,4,2,0).. New safe state is same as previous which is And new available is 14, 24 ,12,12
Bhaiya jaise teen part de rakhe hai usme se second part meh safe sequence nikalna hai aur third meh immediately wala part diya hai toh second wale sequence ka update karke sequence nikalenge ya pehle second ka sequence nikalke fhir update karke third ka sequence nikalenge
My Results are = b) safe sequence < p0, p2, p3, p4, p1 > , Available will be = 2,21,17,12 c) safe sequence < p0, p2, p3, p4, p1 > , Available will be = 3,14,12,12 have you got the same answers @Mayank Meena ?
sir u r great really u have ability to faill most of the reputed and experience teacher of u tube .....phir se comment kr diya kya kru ur vidieo really force me to do that even in exam time i got that much of time for ur vidieo..........u r superb
You are THE BEST. I mean, the channel is good, but Sumer, you are the reason why people come here. Why don't you make your own channel. Don't get me wrong, all others are great too, but you know he's got that potential, encourage him to start his own channel. Keep up with the great work and keep growing exponentially.
Just a basic question: If P1 requests for then we solve and find the safe sequence but if the question has another part saying P3 requests for something then do we need start with the previous data or updated data?
Bro you know what.. Sabse accha best friend app aur apki team hi hai mera.. You all guys put efforts to make understand and clear all my concepts.. Thanx my friends 😊
So how is life?
bhai problem to solve ho gaya
....par tune dil jit liya yar....kash sabhi lecturer tere jaise hote
True
Sir,the way you teaching it's been an great asset for me .You were totally outstanding throughout the lectures.I m really enjoying your channel.
Bhai tera bol ne ka flow muje bahut accha laga... And what a explanation thanks a lot bhai.....
Your welcome
You are best online tutor that I have . Thank you so much bro. ☺️
bhaiya, mereko pehchana
Great bro itni asani se smjadiya yarr schme mst content hain ...
Love your voice bro when you say
"Smja na tumko " 😂
Thanks
Bahuttt badiyaa mere bhai 👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻 Accha samjh me aa raha hai aapka😍
The safe state is
New Allocation=1420
New Available=1100
Need=0330
BY the way Love ur video man
gr8 work
u cleared my entire concept
Flash Cell Series P1 will execute at last
which available matrix we shoud take for solve whole question....question wali ya phr p1 wali?
@@PreetiSingh-ko7dm In available matrix only the value of p1 changes. Rest of the values remains the same with only the changed p1 value
@@alexmercer9276 yes Correct answer I also Got the same values
resource request nahi aati thi tune smjha diya bhai ...aaur jaise tu smjhata h usme badi maja aa rhi hai ...btw thnx
sir kamal karte ho kya energy se padhate ho
thank you sir
you are the best
god bless sir
Mast bhai ek bar me samajh me aa gya....
And safe state is
New available 3,14,12,12...
And after grant the request of p1(0,4,2,0)..
New safe state is same as previous which is
And new available is 14, 24 ,12,12
Amazing bro. Hope this question is present in the set question paper tomorrow.
Thanks alot
Same Question in Exam
Great !! Thanks alot
Bhaiya jaise teen part de rakhe hai usme se second part meh safe sequence nikalna hai aur third meh immediately wala part diya hai toh second wale sequence ka update karke sequence nikalenge ya pehle second ka sequence nikalke fhir update karke third ka sequence nikalenge
Bhai tu sachme chava hai yaar 😎😎😎🙌🙌
Literally watching this 1 hr before vtu exam..tqsm
Thnku vai..aapp to easy lar diye...mere exm ki paper..
bhai maza aagya !! kasam se mast sikhaya ekdum baap
Bhout achaa smjhate ho ap...
Your way of talking is very friendly.
Nice and quick explanation thank you keep making this type of videos tomorrow is my os exam and this video help me
You're a genius bro. Itna sikhi kaise Bhai mujhe v bta na meko v sikhna.
Max of p2 should be 902 not 900...please correct me if i am wrong?
I like the lecture. I was impressed in first session.
bhai bhot hard aisehi video bna yehi lang. me smjme aate jaldi
Bhai tu zher h 😍😍😍😍😍
Top class explanation bro👍🏻🙏
a)
need matrix
A B C D
p0 0 0 0 0
p1 0 7 5 0
p2 1 0 0 2
p3 0 0 2 0
p4 0 6 4 2
b)
safe sequence> p0>p2>p3>p4>p1
is it correct?
safe sequece p0>p1>p2>p3>p4
same qstn maine av banaya safe sequence: p0,p1,p2,p3,p4 Available welll be : 3,14,12,12
My Results are =
b) safe sequence < p0, p2, p3, p4, p1 > , Available will be = 2,21,17,12
c) safe sequence < p0, p2, p3, p4, p1 > , Available will be = 3,14,12,12
have you got the same answers @Mayank Meena ?
bro check it again the sequence will be and ur available is correct
ya bro safe sequence is correct just write available values i.e 3,14,12,12
Kya baat hai!
Kya samjhaya hai!
Thanks a lot
I really need the answer of the last question that's why I'm on TH-cam rn
if this is the question, will i have to write the previous part answer along with this or just this is sufficient?
Bole toh majja aa gaya bhai aise padh k.....thanks bhaiii
Nice way of teaching. easy to understand.Thanks
Nice explanation
Resource allocation Graph bhi explain kr dejiye
(iii) yes,
available=1100
alloc.=1420
need=0330
i like your teaching style.....good job
👌👌 tqsm sir .. ur teaching technique.and way of speaking is really good.
Brother what if request is not smaller than available in second step, should we proceed to next step or stop the process?
Sir question ko karna ka tharika chize bhi hota m
Meri to
P0=1057
P1=743
P2=1047
P3=543
P4=745
Ha sir
सही है कि
Bhra Dil ton respect aa👌
sir u r great really u have ability to faill most of the reputed and experience teacher of u tube .....phir se comment kr diya kya kru ur vidieo really force me to do that even in exam time i got that much of time for ur vidieo..........u r superb
Thanks alot we are happy to help you
thanx bhai nice explanation.pr exam mai 2no solution solved karneka?
Thank u ....so much ..
Many many thanks for a excellent video
#i am very impresed#
Very nice explanation ... And I solved d practice example.
I got d correct answer
Thanks for the video 👍👍
whats the sequence?
You are THE BEST. I mean, the channel is good, but Sumer, you are the reason why people come here. Why don't you make your own channel. Don't get me wrong, all others are great too, but you know he's got that potential, encourage him to start his own channel. Keep up with the great work and keep growing exponentially.
This was very helpful bro.
Thanks a lot.
Will definitely share your channel to everyone I know.
👍🏻💜
It's really a last moment tution ..👍👍👍😜🤩
Nice explanation
Real time scheduling topic bhi explain krdo
Safe sequence is
Correct 💯
Very nice explaination thanks for the video
Thank you bro🙂🙂
Awesome helpful video thanks 👍💯💯
Dhanyawad
Tquuu sirr😊😊
bhaiya aapne 2nd wali table k max me P2 me 902 ki jagha 900 kyu likha hai...???
Sir plzz part 3 bataya na
Best...keep helping.😊
thank you verh much ....
i like your explanation☺
great video please make a video on round robin
tu pyse dey ga kiya abhi k abhi..nice
Thankyou so so much for uploading these videos. I'm grateful.
Thnku Sm bro 😅😘😘
Thank you so much for that video. If you can make video on theory of computation that will be very helpfull for me and my friends.
SMIT me bhi thumara hi lecture padhate h bhai
bhai you are doing great job.....
thanks bhai !
Your welcome
super Easy to understand
Just a basic question:
If P1 requests for
then we solve and find the safe sequence but if the question has another part saying P3 requests for something then do we need start with the previous data or updated data?
Updated data
Bro what if allocation is greater than max....
Then how to take remaining need....?
Great video n helpful one... Hatts off Sir 👏👏
mast reee
Can u please update a video of Dekker's algorithm & Peterson's Algorithm...??
Bhai deadlock k bare m kuch bta skte ho detail m??
Awesome video !
Superb sir...
if request >=need then what will we do
Next process Ko check karenge request< need ane talak
what i do if "Two Process" arrive request be granted immediately.
P0 arrives for (3,3,2) and P2 arrives for (0,1,0)
Safe state algorithm using kar raha ho jo aap wo koi book sa refer kiya hai aapna ya aapka own made hai
biriyani pak rahata keya? 🤣 ap great ho vai!
How did you conclude that p1 is granted immediately?
Thank you bro.
The system is not in a safe sequence
But request will be granted
Is it true?
Thanks bhai
You are so freaking awesome bro........... 😍😍
provide us the answer of the practice problem.
this was needed!!!
mastre!!!!!!!!!!!!!!
Very nice👌👌
Thanks a lot
What to do if request is greater tn need
Bro do a series on ages and remaining aptitude topics please...!
Ooh ok all the best for that.
Hope we get that soon...!
good one bro
Bro baad bali table me Max kam kr diya P2 ka
We don't have to compare request with new available??? We have to compare request with the available which is given(i.e given in question) isn't it?
and 2nd Query is :-> RESOURCE REQUEST ALGORITHM in that if "Request is greater than Need" then going and after what happen..?
thanks 😊
What i do if available is not given and total has given ?? Plz tell me
What if available is not given in the question?
dua lagegi bhai dua
Keep it up!!👌🏼👍👍👍
Bhai ye avilable resources nhi diya h question me? To avilable resourse kaise find krenge..