Your are giving bcd representation. Excess 3 code means we add 3 to bcd code. So, when we change the decimal digit 8 to excess 3 code, first we need to change 8 to BCD code(1000) and next we add 3 to it. So, 1000+0011=1011.This is the representation in Excess 3 code. Understand, thanks
Ya, sandi XS-3 salah satu sandi-2 tdk berbobot, yang pd bilangan dasan 3 jadi 0 pd XS-3 atw 0011 dst, sampai bilangan dasan 12 atw 1100 (biner) jadi 9 pd XS-3...., jd utk tahu XS-3 menjadi dasan, hrs terlebih dahulu dikurangi dg 0011 pd setiap XS-3 dlm kelompok-2 aksara yg terdiri dari 4 bit, menjadi sandi BCD dan lanjut ke basis 10....!!
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way of communicating is awesome and easily understood mam.... thank you
xd
@@janekborgiel8023 what's wrong kid?
You make it very easy to understand in simple language, thnx mam
Awesome teaching 👏👏 ma'am
Nice explanation madam we can easily understood mam .... Thanks madam
we have to take binary numbers or bcd numbers ?
Very good explanation mam❤
I follow your video from Bihar no any language problem .For Nimcet entrance.
Learned a new idea from you
Before adding the 3 to carry the why not the carry consider as 1 so the answer is there no need to add 3 to carry. answer my doubt?
I have clear my doubt from it vedio .. thank u
ThanK you so much mem your good teacher
you are awsome,thank you😊
Super explanation madam. I have a dought that is what we do when carry is the last group
In bcd we treat 11 as 1 and 1 as separate na then 0001 and 0001 is not correct?
Very nice explanation mam tq
can i have parallel subtractor
help on this 811+777 use excess 3 and give answer,the challenge if adding 0011,there is another carry,what do i do?
Adding 8 in excess 3 we will get 11 and excess 3 should be 0001 0001 .why it is not there?
Same doubt..Can someone please help with this?
Your are giving bcd representation.
Excess 3 code means we add 3 to bcd code.
So, when we change the decimal digit 8 to excess 3 code, first we need to change
8 to BCD code(1000) and next we add 3 to it.
So, 1000+0011=1011.This is the representation in Excess 3 code.
Understand, thanks
thank you mam i have a clearidea about xs3
ur awesome mam...no more doubts
Very helpful
13+15 limitations of excess 3
mam please do excess -3adder on 8+9
Ya, sandi XS-3 salah satu sandi-2 tdk berbobot, yang pd bilangan dasan 3 jadi 0 pd XS-3 atw 0011 dst, sampai bilangan dasan 12 atw 1100 (biner) jadi 9 pd XS-3...., jd utk tahu XS-3 menjadi dasan, hrs terlebih dahulu dikurangi dg 0011 pd setiap XS-3 dlm kelompok-2 aksara yg terdiri dari 4 bit, menjadi sandi BCD dan lanjut ke basis 10....!!
Mam can use please share it for 6+6. Excess 3 addition
Thank you
Akhri Ball pe six mara mam apne to ye to bohot easy hai
why is 1+1=0 and will carry 1
Nyc 1mam
Nyc
Nice
Please low ur voice mam
Yes mam
8 and 9 of excess 3 code for addition
11 + 15 = 26 नही 59😀
Ma'am please improve your English, sometimes it is difficult to understand you!
Ab bdsk madam english sudhare ki tujhe🤣