Thankuu u soo much such ...i have very difficulty in this concept but now by the help of your video by doubts are crystal clear ...i have search last 2 hrs continuously this concept but i have find nothing helpful but this help me a lot 😊
There's no point and no fun in studying like this sir taught, watch full explanations, how each and every thing happened and where to came from. If you just learn some "tricks" or "formulas" you won't be able to get into iit or top in neet. Shortcuts in study dosent work!!
Correct English- I just want to say to you that you are an amazing teacher and you know nice tricks. just wanted to help you, friend do not feel embarrassed.
Hey,I need to calculate how much the quantity of Conc H2SO4 Will be required for a 100 mL solution to reduce the pH from 6.5 to 4.5. How do I calculate it ?? Thank you so much in advance .
Sir it's very simple instead of writing 3ph we can simply write 3-log(1) just for sake that where there is no multiplied factor there is something to show its exists.
Guys I am 9th grader and we have Olympiad syllabus so here they teach you the syallbus of 11th and 12th with the CBSE part. Pehli dafa zindagi me I will be able to do a chemistry problem without any hinderence☺️
sir you really saved me...i have my chem exam tomorrow and I had a lot of difficulty in this part...thank youuuu :)
Same
And brother yeh mere sath hone wala 3 din me 🥺🥺🥺🥺😭😭😭😭😭😭
Thankyou aur acche se padhai Karo
According to sir🙏
i am watching before an hour
No bro I am watching this on my exam day
I have my exam in 6 Hours, it 3 am, and this video really helped a lot, thanku Sir
Bhai hmare school ka h kya 😂
my exam at 10 am
now it 1 am + sonna bhi hai + school may mobile kaise le jau
@sugarkanearmy kaisa gaya bhai??
4 am and 6 hours for me
Saal bahr mein makkhiyan mare kya??
Legends are watching one day before exam 🙂🙂😅😅🤣🤣🤣
Yes bro 😅🤣🤣
No bro legends are watching on the day of exam like me 🥲😂
2 hrs left for exam 😢
Fr bhai🥲😂😂😎
Day tomorrow public exam 😢
Thank you! You explained it better in 4 minutes than what my teacher did in 1.5 hrs!
9.3 is the pH of last part
nice explanation sir 👌
Very nice nd simple dear sr👏🙏
Thanks
Thank you so much sir.. Apner jonno puro ta bujlam
Thanku sir ! Tomorrow is my Exam And this 4 min Video helped me A lot👏👏👏👏👏
Hats off to the teacher!...This vedio had helped me when I was in grade 9 and it again helped me today when I'm in grade 11...
U learnt nothing in 2 yrs😂
Bhut gjb sir,aapki tarif k liye mere paas koi word nahi h sir
Tareef rehny do
Dua kr do Allah se
@@chemistryacademy786 god bless you. Sir 🙏🙏
Salute u sir...🎉
No doubts sir crystal clear 👍🏻
Thanku sir
today is my exam and it's 4:30am your explanation helped me a lot
Jazakallah Sir Allah apko ajar de🤲🙏❤
Ameen
Allah ap ki dua qabool kry
@@chemistryacademy786 shurkiya Sir, Ameen🙏💖💖
GREAT SIR G VERY EASY METHOD
sir love from INDIA i am watchin this just before my exam as i get to know that it comes every year
Thank you so much sir
Bohott he asan aur achi tarh sy samjaya
This is very helpful sir.Thankuuuu so much...........🙏🙏🙏
Yes
Very nice and simple sir .It help me alot
Thankuu u soo much such ...i have very difficulty in this concept but now by the help of your video by doubts are crystal clear ...i have search last 2 hrs continuously this concept but i have find nothing helpful but this help me a lot 😊
Kia baat hai sir proud itna acha hamary sir nai samjh atay
❤️❤️❤️ from Pakistan 🇵🇰
Thanks for this video sir this video is very helpful for mi🙏🙏
your video very helpful for me thks
Nice explaination sir 👍👍👍
Thanks 😊 sir
My concept is crystal clear✨!!...answer is 9.3
Sir you are the best you have explained very well
So so beautiful sir 😍❤💖🙏
Crystal clear sir !!! Awesome!!
Thank you so much sir for this video.
The answer of the last question is 9.3
This helped a lot.. thank u.. ❤️❤️
Thank u sir i was struggling with this concept thank u for help 😊😊
wow sir your explanation is great
I don't have any word for your praise, you are outstanding sir...
Supreme sir thank you very much
Thankyou sir helped a lot love from karnataka 💝💝
thank you sir 🙏🙏 love from nepal🇳🇵🇳🇵🇳🇵
Please subscribe my channel
bro very helpful ha thanks love you bro
Thank you so much sir ♥️♥️♥️
❤️❤️❤️❤️
dhaniya vaada meri professor itni ghatiya hai ye sab samjhane mein ye video badi acchi hai
hahahahhaha😂😂😂😂😂
Subhan allah sirjee allah ap ko kameyab kara
Ameen
Legends are watching after attempting wrong in a Pre-board exam
Bhai allah apko bohot bohot sari jaza de mera kal chem ka paper ha or ma bohot parshan tha lakin apki video ne tension katam kardi jazakallah
Ameen
Allah Pak ap ko paper me Kamyab kry
Tomorrow is my exam 😊this vdo really help me
Oh thank you ji❤😊
There's no point and no fun in studying like this sir taught, watch full explanations, how each and every thing happened and where to came from. If you just learn some "tricks" or "formulas" you won't be able to get into iit or top in neet. Shortcuts in study dosent work!!
Oh my god what a wonderful idea thankful to you for making this video leacture
Thanks sir !! It really helped 🌟
Thank you sir best explaination
Sir best teacher
Best vdo sir
Thanks
how does log 2 equals to 0.3...
sir pls make vdo on this topic..
Love from India sir ji
Thanks
@@chemistryacademy786 teachers like u are boon for students 😊
Sir love from up ❤️
Love from Pakistan 🇵🇰
Ur literally god sir
Thank u sir 🥰🥰
Thank you very much sir
Very nice sir...too easy...I m already an subscriber...😀👍👍
Thanks
You r great sir !!
Tysm for such an amazing trick & yes I've subscribed your channel
Thanks
Actually I want say to you , you be a good teacher and you have a good tricks 🥰
Correct English-
I just want to say to you that you are an amazing teacher and you know nice tricks.
just wanted to help you, friend
do not feel embarrassed.
@@yourstrulytk12worldaffairs bhut badhiya
It's simple n awesome
Thanks
Thanks l am happy for my question is solved
Thanku sir kaffi easily samjh gya☺️
Vey vry helpful
Nice And very easy
Thank u so much sir it's help me alot
thanks brother 😍🤑🤑🤑
Sir agar power positive ho to neechay negative hojay gi??
Sir mast padhate ho
राम राम सर
मस्त शिकवले तुम्ही 🙏🏻🚩
जय श्री राम भाई 🚩🕉🙏
Superb explanation! Sir 🙏👍
hmm
smjhh ma ayaa kya
Aa gya samajh m kya
4 hour left for my xm an i am here thank u bhaiya
Guru Ji pyae chui 🙏
Thank you soo much sir 👍🏻👍🏻👍🏻 sir by the way are these 10 th class questions? Are these asked in boards
Yes
@@chemistryacademy786 ok sir thank you 👍🏻
Its in class 11
@@nihalbhamrah4726 hey!! Isn't these type of que asked in 10 th board??? Our teacher hasn't done it yet!
@@simritdhanoa1207 no it's not there in 10th
Thnks it really helps...but one thing can u explain in English...
Thanks sir this is so helpful for me
Hey,I need to calculate how much the quantity of Conc H2SO4 Will be required for a 100 mL solution to reduce the pH from 6.5 to 4.5. How do I calculate it ?? Thank you so much in advance .
Sir u explained it in vry amazing way👌🥰
Very nice sir
Sir it's very simple instead of writing 3ph we can simply write 3-log(1) just for sake that where there is no multiplied factor there is something to show its exists.
Sir plz upload a video on.... If we have given ph then find h+ ion
Okay
Wonderful vedio
Thank you sir cam we use it in board exam
Really thank you sir.
Ur voice is like unusual hacker
😁😅😅
Guys I am 9th grader and we have Olympiad syllabus so here they teach you the syallbus of 11th and 12th with the CBSE part.
Pehli dafa zindagi me I will be able to do a chemistry problem without any hinderence☺️
Very helpful 👌
SIR PLEASE REPLY , kya hum iss tareeqe se class 11th board exam mai kar sakte hai?
Pakistan 🇵🇰 and India have different Board exam
Very good
Thanks for your concept sir
'Normal' me diya ho to bhi 'Molar' ki tarha hi karna hoga kya????
sir you saved me too thank you!
Thank you sir
Amazing ❤️👍👍
HCL ki H+ constration is 10 ki power -9 ki ph kya hogi
9
@@sachinjaiswal3957 to matlab jitna jyada dilute karoge utana basic hoga to ye to strong base NaOH se strong ho jaega
Really helped sir ❤️❤️
1/2 hr before exam 😅
Best help video
Superb 👍👍👍
Thanks sir🥳🥳
That really brilliant... 😊😊