Actually, my videos are for more advanced topics but "The Organic Chemistry Tutor" (he teaches a bunch of subjects - not just chemistry) has a very easy to understand and beginner-friendly playlist th-cam.com/play/PL0o_zxa4K1BVCB8iCVCGOES9pEF6byTMT.html
For a = 1, then that would be equal to (50!)^2 / (101)!, by use of the Beta Function. But for a general a, I don't think there would be a nice answer 💀
@exp_ert_math i had this in an exam, tried differentiating with respect to a 50 times 💀 i got the right answer but i think it was the wrong approach...
I think you can use the initial condition of a=0 for each time you integrate back to find the coefficients - you'll probably spot the pattern and get a general formula for the coefficients of the polynomial so you can write it as a sum. This is all in my head so I don't know whether it will actually work 💀
really enjoyable
Thanks dude🎉
wow rlly cool
They did teach it
Do you have an explaining video for trigonometry for 9th graders?
Actually, my videos are for more advanced topics but "The Organic Chemistry Tutor" (he teaches a bunch of subjects - not just chemistry) has a very easy to understand and beginner-friendly playlist th-cam.com/play/PL0o_zxa4K1BVCB8iCVCGOES9pEF6byTMT.html
I need some help with this integral int^1_0 x^50(a-x)^50 dx where a \in R
For a = 1, then that would be equal to (50!)^2 / (101)!, by use of the Beta Function. But for a general a, I don't think there would be a nice answer 💀
@exp_ert_math i had this in an exam, tried differentiating with respect to a 50 times 💀 i got the right answer but i think it was the wrong approach...
It seems to be some 50 degree polynomial in a, but are you sure you can find the coefficients of the polynomial?
@exp_ert_math oh damn i forgot the constants of integration
I think you can use the initial condition of a=0 for each time you integrate back to find the coefficients - you'll probably spot the pattern and get a general formula for the coefficients of the polynomial so you can write it as a sum. This is all in my head so I don't know whether it will actually work 💀