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Vikrant Batch - Enrollment Link 👉 bit.ly/CDS_Vikrant📲PW App Link - bit.ly/YTAI_Defence🌐PW Website - www.pw.live
Homework answers:1. -6.5 J2. 33thankyou ma'am❤
Wonderful teaching ❤ ma'am....
Yaha ke teachers bhi bahut caring hai
Question 1 :- work = -10 j and ∆u(energy change)= 3.5 Q = (-10) + 3.5Q = (- 6.5)
Unit lagao uniti.e. Joule😂
Physicswallah platform is the greatest platform
Loving teacher
1) -6.5 joule is the Amount of heat loss 2) 33%Jai hind mam ✨🙏
Ma'am thanks for the last revision that you gave that really helps us a lot.You are really a nice teacher.
Very informative,love you mam🤗🤗❤️
Thank u mam😊 best teacher ever.
44:18 -->33 answer
30:57 ans is -6.5
Thank you mam ☺️
-6.5 joule is the amount of heat loss.33% efficiency. Jai Hind ma'am
13.5j
Tq mam
First answer = -6.5 Joule
Efficiency of a Carnot engine is A. 33
O bhai , 1 - 250/373 ko Kaisey solve kiya ?? Help kardo
A . -6.5jB. 33 please mam, you solve the question again
Yea ek esa chapter hai.... jo ki mera na he 10th mein hua ... +2 mein aur na he AB 🥲🥲
efficiency 33
1] -6.5J amount of heat loss 2] 33%
Madam please explain again about Third Law Of Thermodynamics in next Class
As soon as possible.
Lecture was informative mam but connection b/w 1st law and 2 nd law was left i think
Thnxxx mam
-6.533%
Amount of Heat🔥 Loss /Gain is 13.5 Joule
Galat bhai galat.....-6.5J is the correct answer
@@simran_the_spideyya you are right
Mam please tell me ,Kya NDA ki classes TH-cam par nahi start hogi 🙏🙏🙏🙏Please reply me mam
Sir agniveer batch launch kijiye
Sir NDA online class kab se suru karenge
9th- 10th Ncert m to nhi h mam ye
Cds ki playlist kha ha puri
Mam apaka name kya hai
❤❤❤❤❤❤❤❤❤❤ mam apaka name kya hai
This chapter is not a part of 9th or 10th NCERT, then how is this importent for CDS 1 2023
Pyq. M aya h
bhai UPSC hai ek question Ganesha mega from higher classes, inhone chapter hi nana Diya @@anjneykumarsingh4461
Vikrant Batch - Enrollment Link 👉 bit.ly/CDS_Vikrant
📲PW App Link - bit.ly/YTAI_Defence
🌐PW Website - www.pw.live
Homework answers:
1. -6.5 J
2. 33
thankyou ma'am❤
Wonderful teaching ❤ ma'am....
Yaha ke teachers bhi bahut caring hai
Question 1 :- work = -10 j and ∆u(energy change)= 3.5
Q = (-10) + 3.5
Q = (- 6.5)
Unit lagao unit
i.e. Joule😂
Physicswallah platform is the greatest platform
Loving teacher
1) -6.5 joule is the Amount of heat loss
2) 33%
Jai hind mam ✨🙏
Ma'am thanks for the last revision that you gave that really helps us a lot.
You are really a nice teacher.
Very informative,love you mam🤗🤗❤️
Thank u mam😊 best teacher ever.
44:18 -->33 answer
30:57 ans is -6.5
Thank you mam ☺️
-6.5 joule is the amount of heat loss.
33% efficiency.
Jai Hind ma'am
13.5j
Tq mam
First answer = -6.5 Joule
Efficiency of a Carnot engine is A. 33
O bhai , 1 - 250/373 ko Kaisey solve kiya ?? Help kardo
A . -6.5j
B. 33
please mam, you solve the question again
Yea ek esa chapter hai.... jo ki mera na he 10th mein hua ... +2 mein aur na he AB 🥲🥲
efficiency 33
1] -6.5J amount of heat loss
2] 33%
Madam please explain again about Third Law Of Thermodynamics in next Class
As soon as possible.
Lecture was informative mam but connection b/w 1st law and 2 nd law was left i think
Thnxxx mam
-6.5
33%
Amount of Heat🔥 Loss /Gain is 13.5 Joule
Galat bhai galat.....
-6.5J is the correct answer
@@simran_the_spideyya you are right
Mam please tell me ,
Kya NDA ki classes TH-cam par nahi start hogi 🙏🙏🙏🙏
Please reply me mam
Sir agniveer batch launch kijiye
Sir NDA online class kab se suru karenge
9th- 10th Ncert m to nhi h mam ye
Cds ki playlist kha ha puri
Mam apaka name kya hai
❤❤❤❤❤❤❤❤❤❤ mam apaka name kya hai
This chapter is not a part of 9th or 10th NCERT, then how is this importent for CDS 1 2023
Pyq. M aya h
bhai UPSC hai ek question Ganesha mega from higher classes, inhone chapter hi nana Diya @@anjneykumarsingh4461
Physicswallah platform is the greatest platform
Loving teacher