SFEE Numerical Example 2

[@TutorialsPoint_]

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[@krn2033]

Please Review T1=T2=373k not 303k.

[@vivekjkumar5797]

True

[@prakashvijay2801]

in last vid you told h1 = h2 when v1 = v2 but here its not the case why?

[@lasansenithmadawala791]

this is real situation and he told at the last video considering ideal conditions

[@Bhava315]

How Can you Use h1=h2...As you said it is the only case when you assume there is no Velocity Change in Upstream & Downstream. Where as the Question is to find out velocities V1 &V2

[@studyaffairs4926]

i have the same question , how?

[@olejrgenarenth8761]

@@studyaffairs4926, Its because h>>1/2v^2. So you can look away from the kinetic energy because the entalpy is much bigger. ->h_1=h_2

[@adityapethkar3725]

@@olejrgenarenth8761 Correctly said. If the difference in velocity is considered in SFEE then (T2-T1) = 0.0016

[@justinchambers3406]

@@adityapethkar3725 0.0016 or 0.6 approx

[@akashjaiswal6478]

how can h1 and h2 become equal??

[@rameshs2539]

Cut to 2:58 - for determining velocity (V) how come u know that volume (v) has to be specific volume?? Plz clear the doubt

[@justinchambers3406]

check the units
ull know

[@subhaka5553]

How r u taking h1=h2?? It can only be equal if the velocities are same. I think this soln is wrong..can you plz upload another soln to this problem??

[@161616ANAND]

For throttling process, enthalpy remains constant. So h1 =h2

[@rahulbhandari2260]

sir. aap jaante ho engineer ko. 10 min se upar koi video nahi. i like this concept. banda pehle hi demotivate ho jata hai 20 min se upar ki video dekh ke hi. dheere dheere 143 videos araam se dekh sakte hain. ye all iz well wala concept hai.

[@tahsinsayednihad6456]

As velocity increases, Kinetic Energy increases. So from where this energy come from if all other energy transformation is Zero?

[@darrenmallare4057]

the pressure difference

[@SeekTheTruthAndTruth]

I think you really need to seek a systematic method of problem solving.

[@VYOMISTRY]

Sir, what is this R ???

[@shubhamkumaragarwal1684]

Gas constant at 100°C

[@vrajparekh6877]

72.25