Given: - OD (Outside Diameter) = 24.6 mm - Pitch = 8.5 mm - Number of starts = 4 We need to find: - Lead (L) - Helix angle (α) Calculations: - Lead (L) = Pitch x Number of starts L = 8.5 mm x 4 = 34 mm - Helix angle (α) = arctan (Lead / (π x OD)) α = arctan (34 / (π x 24.6)) α ≈ 23.4 degrees So, the lead is 34 mm, and the helix angle is approximately 23.4 degrees. Let me know if you need any further assistance!
AOA SIR My question is sar Mera sawal hai ki agar mere pass woram ka Daya aur uski pitch ho to main usse module ya DP Kaise nikal sakta hun sar Agar video ke liye time na ho aapke pass short time ho to kindly mujhe aap message mein convey kar de bahut shukriya.
Great explained sir jee
Thanks
❤❤❤❤
Thanks
Assalam.o.allaikum sir worm ki calculation chahye OD 24.6=pitch 8.5 mm= 4 start . Is lead aur angle kitna nikly ga
Given:
- OD (Outside Diameter) = 24.6 mm
- Pitch = 8.5 mm
- Number of starts = 4
We need to find:
- Lead (L)
- Helix angle (α)
Calculations:
- Lead (L) = Pitch x Number of starts
L = 8.5 mm x 4 = 34 mm
- Helix angle (α) = arctan (Lead / (π x OD))
α = arctan (34 / (π x 24.6))
α ≈ 23.4 degrees
So, the lead is 34 mm, and the helix angle is approximately 23.4 degrees.
Let me know if you need any further assistance!
@@shahidnisartechnicalinstru4854 thanks allot sir
AOA SIR
My question is sar Mera sawal hai ki agar mere pass woram ka Daya aur uski pitch ho to main usse module ya DP Kaise nikal sakta hun sar Agar video ke liye time na ho aapke pass short time ho to kindly mujhe aap message mein convey kar de bahut shukriya.
Agar pitch hain tw ,module=pitch/3.1416
Jab module malom ho jay tw ,DP=25.4/module