How to Solve Radical Equations that have Three Radicals: Step-by-Step Explanation
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- เผยแพร่เมื่อ 10 ก.พ. 2025
- Learn how to solve radical equations that have 3 radicals and check your answer for extraneous solutions. Step-by-Step explanation by PreMath.com
Sir! you explained in an easy way, have cleared many things, hope you will keep it up. We "AL FAHAD EVENING ACADEMY" team thanks you by the deep of heart.
This was too easy for you. I like it better when you solve the challenging geometry problems. But I like your videos in general. Thanks!
Sqrt(A)=sqrt(B)+sqrt(C)
Conditions :
B>=0 , C>=0 , A>= B+C ==> D: validity
Solve (A-B-C)^2= 4BC in D
this video is very helpul!thankyou
Thank you PreMath soo much
excellent ! I like this makes things simple five stars !
Thank you so much
Thks.
Thanks🤗
So nice of you Ivan dear! You are awesome 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and stay blessed😃
Solution by insight
5=3+2
x=3
I think there exists a mistake moving to step 3 we must not cancel the √ with the exponent bcz the number under the redicle can be of a positive or a negative value but the answer of the (√3)² can't be negative so we have 2 cases of x at this step .. Idk this is what I've learnt 🙁😐
х=3 попадает в одз, зачем проверка?
Thank youu
You are very welcome Crissel! I'm sure you are an awesome student 👍 I'm glad you liked it! Please keep sharing premath channel with your family and friends. Take care dear and all the best😃 Have a very happy and blessed New Year!
If i get two x ... Is that true?? Bcs i get kuadratic equation at the end🙏
This is for my math question
good video
Thanks for the visit! Thanks for the feedback Vishwanathan! Take care dear and all the best😃
00:00 Why don't you start with calculating the Domain?
1) √(9x-2) ⇒ 9x-2 ≥ 0 ⇒ 9x ≥ 2 ⇒ x ≥ (2/9) ⇒ x ∈ [ (2/9) ; +∞] ⇒ x ∈ [ (8/36) ; +∞)
AND
2) √(4x-3) ⇒ 4x-3 ≥ 0 ⇒ 4x ≥ 3 ⇒ x ≥ (3/4) ⇒ x ∈ [ (3/4) ; +∞] ⇒ x ∈ [ (27/36) ; +∞)
AND
3) √( x+1) ⇒ x+1 ≥ 0 ⇒ x ≥ (-1) ⇒ x ∈ [ (-1) ; +∞)
which causes that the Domain is:
D: x ∈ [ (3/4) ; +∞)
07:04 So our solution "3" ∈ D
Your idea is the best .
But :
1) instead 9x-2 >=0 write:
9x-2 >= (4x-3) + (x+1)
Example :
Sqrt(x-3) = sqrt(x+5) + sqrt(2x+8)
If you write 1) x-3>=0 ===> x>=3 D would be D= [3, +inf ).
But (-2x-16)^2 = 4(x+5)(2x+8) gives :
x= -6 or x=4
4 is well in D but isn't a solution.!!!
Correction:
1) x-3>= (x+5) +(2x+8) ==> x=0 ==> x>=-5
3) 2x+8>=0 ==> x>= -4
Therfore D= { } ===> no solution.
Thank you
sum of squares :)
x variable
Powerful
x=3
DISLIKE Not accessible to blind viewers.
x = 3