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Anyone catch Einstein fingers?
😮 Nice
Just did it now, an alternative method Is: X^32 = 2^x(X^32)^1/32 = (2^x)^1/32X = 2^(x/32). If a = x/3232a = 2^a(2^5)a = 2^aa = 2^(a-5)And it isn’t difficult to see that a=8. So,X/32 = 8X= 32x8X=256
Anyone catch Einstein fingers?
😮 Nice
Just did it now, an alternative method Is:
X^32 = 2^x
(X^32)^1/32 = (2^x)^1/32
X = 2^(x/32). If a = x/32
32a = 2^a
(2^5)a = 2^a
a = 2^(a-5)
And it isn’t difficult to see that a=8. So,
X/32 = 8
X= 32x8
X=256