Margins 4 - using the bode diagram and MATLAB

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  • เผยแพร่เมื่อ 2 ก.พ. 2025

ความคิดเห็น • 11

  • @samehum
    @samehum 11 ปีที่แล้ว

    Fantastic video, thanks John.

  • @fahrenheit451able
    @fahrenheit451able 4 ปีที่แล้ว

    How do you switch from plot to plot at 14:00

  • @mihirzachariah4462
    @mihirzachariah4462 4 ปีที่แล้ว

    Thanks very much! Just what I needed

  • @tanyingjian7562
    @tanyingjian7562 8 ปีที่แล้ว

    what if I get multiple gain margin after lag-lead compensator, one is positive whereas the other is negative, however, the closed loop system is still stable, what does it means?

    • @johnrossiter2323
      @johnrossiter2323  8 ปีที่แล้ว

      You will need to look at the Nyquist diagram to get further insight via the encirclements.
      Anthony

  • @aryanjebelli705
    @aryanjebelli705 9 ปีที่แล้ว

    what happens if the gain plot doesnt intercept 0 dB, im assuming phase will just be infite?

    • @johnrossiter2323
      @johnrossiter2323  9 ปีที่แล้ว +1

      Aryan Jebelli If the gain is always less than one then you cannot determine a phase margin. Also, you cannot intersect the minus point with s=jw which tells you the poles cannot cross from RHP to LHP or vice-versa!
      Anthony

  • @cerohierro4405
    @cerohierro4405 10 ปีที่แล้ว

    what if the phase plot doesnt intercept -180º?

    • @johnrossiter2323
      @johnrossiter2323  10 ปีที่แล้ว +2

      Cero Hierro This means you cannot solve GK=-1 with s=jw, so you cannot find a gain such that a closed-loop pole is on the imaginary axis. Usually this would also mean that the gain margin is infinite so the system is closed-loop stable for positive K.Anthony

  • @gabrielj.4758
    @gabrielj.4758 4 ปีที่แล้ว

    gracias!

  • @Hamalaw-lg9th
    @Hamalaw-lg9th 9 ปีที่แล้ว

    thank you :)