The attractive forces between rock and star are Newton third law pairs! So they are equal magnitude, opposite direction: Fstar = - Frock From Newton's 2nd law, we can relate force with momentum cuz F = Δp/Δt. Since time of interaction between rock and star is same, so: Fstar = - Frock ΔP_star = -ΔP_rock So both objects would have the same change in momentum!
I fail to understand how the momentum of S is changing exactly? ISN'T IT STATIONARY?
The question never mentioned that S is stationary
the dopest explanation
mereko to kuch smjh nahi ayi
@@tahabashir9405 sad
At 6:56 how do we explain that the momentum of R is equal to momentum of S?
Force on R is equal to force on S (by Newton's 3rd Law / Law of Gravitation), hence CHANGE in momentums are of equal magnitude also!
may i know how r the forces from S & R RELATED to the momentum??
The attractive forces between rock and star are Newton third law pairs! So they are equal magnitude, opposite direction:
Fstar = - Frock
From Newton's 2nd law, we can relate force with momentum cuz F = Δp/Δt. Since time of interaction between rock and star is same, so:
Fstar = - Frock
ΔP_star = -ΔP_rock
So both objects would have the same change in momentum!
@@ETphysics but they are not interact. so there are no force between them, is that right?
@@prsstnc exactly
@@neko2000gh Thanks!
@@prsstnc no cuz there is gravitational force between them
Why is the momentum of the star negative?
Thankyou so much, great explaination, liked and subscribed
if this comes in my exam i will switch off
i was thinking the same thing
like who thinks so far to actually be able to come up with a solution like that
Very interesting.
Wtf