Data Handling One Shot | Math Chapter 3 | Class 7 | CBSE
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Answer of the homework question is
A) Mean is sum of the total number of observations /
total number of observations
= 429/11
Mean is equal to=39
B) mode is 15
C) median is 6th observation which is 15
Thank you ma'am🌸
1.mean =39
Mode= 15
Median= 50
2. Mean= 13.17
Mode=14
Median= 14
3. 450 (c)
Homework:
1. Mean = Sum of all observation/Total number of all observation = 158/11 = 14.36
Median = 2, 10, 12, 14, 14, 14, 14, 14, 14, 16, 18 = 12/2 = 6
Mode = 14 occurs the most, so 14
2. Sum of cars sold in January and March = 375+75 = 450
3. (Extra question which was said during the class)
Mean = 39
Median = 15
Mode = 15
Name :Aasakti🦋
Answer: 1.mean=39
Meadian=15
Mode=15
2. mean=13.16
Meadian=14
Mode = 14
3. C option 450
To find the mean, median, and mode for the given data set \( 2, 14, 16, 12, 14, 14, 16, 14, 10, 14, 18, 14 \), let's proceed step by step.
### Mean
The mean (average) is calculated by summing all the values and dividing by the number of values.
First, sum the values:
\[ 2 + 14 + 16 + 12 + 14 + 14 + 16 + 14 + 10 + 14 + 18 + 14 = 162 \]
There are 12 data points in total. Now, calculate the mean:
\[ \text{Mean} = \frac{162}{12} = 13.5 \]
### Median
To find the median, we first need to sort the data in ascending order:
\[ 2, 10, 12, 14, 14, 14, 14, 14, 16, 16, 18 \]
There are 12 numbers, so the median is the average of the 6th and 7th numbers:
\[ \text{Median} = \frac{14 + 14}{2} = 14 \]
### Mode
The mode is the number that appears most frequently in the data set.
In this case, the number 14 appears most frequently (5 times), which makes it the mode.
### Comparison of Mean, Median, and Mode
- **Mean:** 13.5
- **Median:** 14
- **Mode:** 14
**Observations:**
- The mean (13.5) is slightly lower than the median (14). This indicates that the distribution is slightly skewed to the left.
- The mode (14) indicates the most frequently occurring value, which in this case matches the median.
In summary, the mean, median, and mode provide different perspectives on the central tendency of the data:
- Mean gives an average value influenced by all data points.
- Median gives the middle value, unaffected by extreme values.
- Mode gives the most frequent value(s) in the data set.
For this particular data set, while the mean and median are close, the mode (14) stands out as the most frequently occurring value.
Please move to the other platform
NAME: ASHI
HOMEWORK
1. MEAN= 13.17
MEDIAN = 14
MODE = 14
2. C - 450
3. SUM OF CARS SOLD IN THE MONTHS - JANUARY AND MARCH = 375 +75 = 450
(SOLVED)➕➖➗🟰♾️........
Q.1 Mean -13.17
Median - 14
Mode - 14
The mean is slightly lower than the median and mode, which are equal. This slight difference is due to the presence of the outlier value 2, which pulls the mean down slightly. The median and mode, being measures of central tendency less affected by outliers, remain equal and reflect the most frequently occurring value in the dataset.
Q.2 c- 450
Question 1:: - Mean = 39
- Median = 15
- Mode = 50
Question 2:: - Mean= 13.17
- Median = 14
- Mode = 14
Question 3:: - { - Option - C - 450 - }
╚═.✾. ═.✾. ═.✾. ═╝
H. W
1. Mean - 39
Mode - 15
Median - 15
2. Mean- 13.1666667
Mode - 14
Median - 14
3. The sum of jan and march
i. e 375+75 - 450
Homework:
1.Mean 13.17
Median 14
Mode 14
2. C-450
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homework 1 . mean 13.15 median 14 mode 14 homework 2 c) 450 and extra question : mean 39 median 15 mode 15
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1.Mean = 39
Mode= 15
median =15.
2.Mean: 12.83
Median: 14
Mode: 14
3. 375➕75 = 450
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