Hey bro in this play list please make on the video on design of flywheel springs brakes with the psg college of technology data book Make it completely like DME 2 book U r doing very good Well done
The books which have mentioned 102 instead of 1020 aren't misprinted. In those Pt is in kgf instead of Newton. That's why ... Difference of 9.8(10 aprx)
@@viswanadhamlokesh3964 Haha thanks for the reply. Because of ur reply I got to know about this comment of mine. Time flies! I was I engineering that time and was struggling hell lot with chain design...haha ... . 😄😄
For a question on chain drive, if the center distance is not given, I have a formula to calculate it on page 7.74. The formula states that the optimum distance is to be taken as a=(30 to 50)p. Pitch as we know can be selected from the same page or can be assumed, whichever is suited. This center distance can be an approximate value because at the very last, we calculate the final center distance once again corrected to even number of pitches from the formula on page 7.75!
Sir, you have said that we have to consider or prefer the transmission ratio if we won't given both N1 and N2. But while calculating the Pt we need N2 then from where we should take the speed. Plz revert
Hello According to the data book page 7.78, w is weight/m in kgf (relating to centrifugal tension) while going back to the big table the value for weight/m is 1.78 in kgf so how did you conclude m=1.78kgf? While m being w/g, the units don't come up as kgf.. or I'm confused.. Kindly explain.. Thank you..
In step 6, I have put in 1.78 kgf but that is actually 1.78 kgf/m which when multiplied by the square of velocity which is (m/s)^2 automatically gives the value in Newtons. Hope this cleared the doubt. Feel free to reply back if it isn't clarified still.
ROBOMECHTRIX Oh sir I got but it still couldn't digest it.. like if it is (wv^2/g) the unit comes up as [kgf (m/s)^2 (m/s^2)^-1] since in the data book 7.72 it is said to consider weight per metre to be "kgf" and not "kgf/m" there is still an "m" left in multiplication with "kgf".. but okay.. if it was kgf/m then it would cancel out the "m" but still sir was it worthy of you to show only "w/g" to be in kgf.. the "v" part has also helped in bringing the value to "kgf m m^-1" Thank you for you reply sir it was very kind of you..
In step 6, I have put in 1.78 kgf but that is actually 1.78 kgf/m which when multiplied by the square of velocity which is (m/s)^2 automatically gives the value in Newtons.
hello sir, in this entire solution the data that is power to be transmitted P=11 kW is no where used. Is it that the power to be transmitted does not affect the selection of the chain drive?
For a question on chain drive, if the center distance is not given, I have a formula to calculate it on page 7.74. The formula states that the optimum distance is to be taken as a=(30 to 50)p. Pitch as we know can be selected from the same page or can be assumed, whichever is suited. This center distance can be an approximate value because at the very last, we calculate the final center distance once again corrected to even number of pitches from the formula on page 7.75!
Sir I asked my college professor regarding this. I suggested him the same method you have described I.e assumption of pitch. But he said instead of assuming pitch ,assume the velocity. But the problem here is if we assume the velocity and find the breaking load,ultimately in order to calculate the exact center distance we need an assumed value. Sir can we assume the centre distance to 1500mm.? This was suggested by my college professor while taking this topic.
Assumption is one of the thing that can be anything, your professor might be correct too! But eventually if the actual center distance is eventually less, we will have to lower down the value anyways. Both the approaches can be used, but it is preferable that you follow what your professor has asked you to.
The link of the book from which the formulas are taken is Amazon - www.amazon.in/Design-Data-Engineers-College-Kalaikathir-Coimbatore/dp/8192735508/ref=sr_1_4?ie=UTF8&qid=1508657797&sr=8-4&keywords=design+data+handbook
Thank you very much it helped me a lot
Do you have a simple equation for power in a two sprocket chain drive system.
I like how the design is based on breaking strength of the chain. But the computation of Ft, Fs and Fc are iffy.
Are there any standard sizes of sprocket dia and chain length?
Hey, first of all...Great video sir ! At 4:52,the total on what is calculated ? front sprocket ? Also, shoudnt that be added vectorially ?
Hey bro in this play list please make on the video on design of flywheel springs brakes with the psg college of technology data book
Make it completely like DME 2 book
U r doing very good
Well done
Thank you so much sir..!!!!
SO DIFFERENT FROM VB BHANDARI BOOK CHAIN DRIVE, WHICH ONE SHOULD BE FOLLOWED?
please mention that book name with name of author which you are referring in your videos
The books which have mentioned 102 instead of 1020 aren't misprinted. In those Pt is in kgf instead of Newton. That's why ... Difference of 9.8(10 aprx)
yep that's truee....
@@viswanadhamlokesh3964
Haha thanks for the reply. Because of ur reply I got to know about this comment of mine. Time flies! I was I engineering that time and was struggling hell lot with chain design...haha ... . 😄😄
Thank you sir
U DONT NEED TO HOPE THAT I UNDERSTOOD SIR
FOR REAL I UNDERSTAND EVERYTHING]
Pl give reason if motor and gearbox connect with single chain spoket if we use double spoket motor load increase or not.
Please upload the design also in pdf format...that will be helpful...
Sir, if center distance was not given, then how will you find step 4 i.e p(max)....?
Thank u
you told that we should take((w/g)=m) but in the table weight is given and not mass
How to do sums when centre's distance not given,.?
For a question on chain drive, if the center distance is not given, I have a formula to calculate it on page 7.74.
The formula states that the optimum distance is to be taken as a=(30 to 50)p. Pitch as we know can be selected from the same page or can be assumed, whichever is suited. This center distance can be an approximate value because at the very last, we calculate the final center distance once again corrected to even number of pitches from the formula on page 7.75!
Sir, how to determine output power when designing from scratch?
sir I have the same issue, I am inquiring if you have solve this issue?
@@kentlouieeyana7189 not yet
i have a calculation to be done on Chain drive mechanism. Can anyone help me out with that ? Thanks in advance...
Sir, you have said that we have to consider or prefer the transmission ratio if we won't given both N1 and N2. But while calculating the Pt we need N2 then from where we should take the speed. Plz revert
Sure we will get back to you.
Hello
According to the data book page 7.78, w is weight/m in kgf (relating to centrifugal tension) while going back to the big table the value for weight/m is 1.78 in kgf so how did you conclude m=1.78kgf?
While m being w/g, the units don't come up as kgf.. or I'm confused..
Kindly explain..
Thank you..
In step 6, I have put in 1.78 kgf but that is actually 1.78 kgf/m which when multiplied by the square of velocity which is (m/s)^2 automatically gives the value in Newtons.
Hope this cleared the doubt. Feel free to reply back if it isn't clarified still.
ROBOMECHTRIX
Oh sir I got but it still couldn't digest it.. like if it is (wv^2/g) the unit comes up as [kgf (m/s)^2 (m/s^2)^-1] since in the data book 7.72 it is said to consider weight per metre to be "kgf" and not "kgf/m" there is still an "m" left in multiplication with "kgf".. but okay.. if it was kgf/m then it would cancel out the "m" but still sir was it worthy of you to show only "w/g" to be in kgf.. the "v" part has also helped in bringing the value to "kgf m m^-1"
Thank you for you reply sir it was very kind of you..
dude in step 6 why didnt you convert kgf to newtons
In step 6, I have put in 1.78 kgf but that is actually 1.78 kgf/m which when multiplied by the square of velocity which is (m/s)^2 automatically gives the value in Newtons.
Reference book?
hello sir, in this entire solution the data that is power to be transmitted P=11 kW is no where used. Is it that the power to be transmitted does not affect the selection of the chain drive?
kiya tho hai step 6
Yes, it has been used in step number 6.
Sir if the center distance is not given in the question,how do we proceed?
For a question on chain drive, if the center distance is not given, I have a formula to calculate it on page 7.74.
The formula states that the optimum distance is to be taken as a=(30 to 50)p. Pitch as we know can be selected from the same page or can be assumed, whichever is suited. This center distance can be an approximate value because at the very last, we calculate the final center distance once again corrected to even number of pitches from the formula on page 7.75!
Sir I asked my college professor regarding this. I suggested him the same method you have described I.e assumption of pitch. But he said instead of assuming pitch ,assume the velocity. But the problem here is if we assume the velocity and find the breaking load,ultimately in order to calculate the exact center distance we need an assumed value.
Sir can we assume the centre distance to 1500mm.? This was suggested by my college professor while taking this topic.
Assumption is one of the thing that can be anything, your professor might be correct too! But eventually if the actual center distance is eventually less, we will have to lower down the value anyways.
Both the approaches can be used, but it is preferable that you follow what your professor has asked you to.
ROBOMECHTRIX thank you sir.
I am testing ...
where i can find design data book please help
Telegram channel
Can you please upload the data book or give us a link to download it
The link of the book from which the formulas are taken is
Amazon - www.amazon.in/Design-Data-Engineers-College-Kalaikathir-Coimbatore/dp/8192735508/ref=sr_1_4?ie=UTF8&qid=1508657797&sr=8-4&keywords=design+data+handbook
no pdf version at all?
I am not sure. You will have to check it out online.
thanks a lot
bro do you got it's pdf?
units ki pure waat laga di hai sir ne
73.74 TEETH? How?
At last step dr formula not in pg 7.72