Ive taken calc 1,2,3, linear algebra, intro to differential equations, and am now in complex vector analysis and somehow avoided learning about hyperbolic functions. This was great explanation and just what I needed for this class. Thank you :)
Bruh I'm a fucking engineering 1st year student and this is the first time I'm hearing about hyperbolic functions. I dont recommended walking on any bridges i make in the future
Professor Dave, you continue to deliver on the kicks in the discovery. Learning that Hyperbolic geometry is literally geometry with Hyperbolas has warmed my soul
Great video Dave. Enjoy all your uploaded material. You truly have mastered the art of distilling a topic to it bare essence. Your fan following is very lucky to have you. Just missed one small point though in this particular video. You forgot to explicitly describe the relationship between these trigonometric hyperbolic functions to an actual graphical hyperbola. That I think would have made the video just a tiny bit more complete.
It was the best . I liked your video very much. I was so confused about these h functions but your amazing video helped me a lot. Thank you very much sir.
I Had a calculus class this morning about this exact hyperbolic functions, and it took 90minuts, and professor dave finished it in 7 minutes. Thank you professor dave
The graph of the system y = (1/2)e^x y = -(1/2)e^x is clearly not a hyperbola. On a hyperbola with no vertical asymptotes, the limit of dy/dx as x approaches plus or minus infinity should be finite (it should approach a line). For y = (1/2)e^x , dy/dx = (1/2)e^x which increases without bound as x approaches infinity (the graph does not approach a line).
Agreed! i'm not taking anything away from Professor Daye, but the grapth of Ae^x is the graph of the exponential function, not the graph of the hyperbola. The easy equation of a hyperbola is y=1/x. the area under that curve is ln. the inverse function of ln is e. so there's ur connection b/n e and hyperbolas. A rotated hyperbola has the equation y^2-y^2=R^2
The hyperbolic functions do come from a hyperbola, Dave's explanation is not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy." Dave is generally very good, but he's wrong about this.
I'm disappointed in this vid. Professor Dave is my favorite for math videos to assign to my students, because the vids are professionally made, clear, understandable, and have good graphics. Some math vids are just unwatchably bad. I need a good vid on hyperbolic functions, but this one has a glaring error. Dave says that 1/2 e^x and -1/2 e^(-x) form a hyperbola. They do not. Hyperbolas have linear asymptotes. Exponentials do not. The hyperbolic functions do come from a hyperbola, but that's not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy" I want a vid with the production values of Professor Dave Explains, but with a correct explanation of how the hyperbolic functions relate to the unit hyperbola, and there isn't one. I'm bummed.
He's not saying that it makes a hyperbola. It makes a function called a hyperbolic sine. It is related to hyperbolas in a similar way that sine and cosine are related to the circle, but it isn't a hyperbola itself. It also has a lot of properties in common with sine and cosine, but it isn't either of those functions either.
@@carultch I know what the hyperbolic sine function is. That is not the point. Listen to the vid from 1:20 to 1:35, where he says: "Now what does this mean graphically? Well, let’s take this expression and break it up into two terms: one-half e to the x, minus one-half e to the negative x. If we sketch these two curves, we get a hyperbola." That is incorrect. Sketching those two curves does not create a hyperbola.
Curse you Texas Instruments users. Casio is standard for us Aussies :) I just bought an FX-82AU plus II for $12 (Co-op Bookshop on campus had a 70% off clearout on everything), but I kinda have strong feelings for my decade old FX-100AU. Can't have enough calculators.
This is a very uncharacteristically dry presentation, and you haven't really shown how the hyperbolic functions are related to the hyperbola _in the way the the regular trig functions are related to the unit circle._
nope. the signs are different. that change in sign made all that huge difference. example: d[tanh^-1 x] = 1/(1-x2) d[tan^-1 x] = 1/(1+x2) and no you cant multiply the other by negative to get the other. they are completely different.
does someone know what is the equation of the hyperbola at 1:32 in terms of x and y ? I suppose it has to have an xy term that makes it rotate like 45 degrees ?
I would say that yes, that is an apparent error. That said, the point of this section is to demonstrate that the sinh function is the sum of these two exponential curves.
Ive taken calc 1,2,3, linear algebra, intro to differential equations, and am now in complex vector analysis and somehow avoided learning about hyperbolic functions. This was great explanation and just what I needed for this class. Thank you :)
Same....
bruh im taking hyperbolic functions in calc 2
Bruh I'm a fucking engineering 1st year student and this is the first time I'm hearing about hyperbolic functions. I dont recommended walking on any bridges i make in the future
@@mayankjain04 lmao same
I'm a second-year math major and I'm just learning about them now on my own. Why do they skip these?
Thank you, Jesus.
Fu ck you don't mocking
@@hunterz3163 aww is hunter mad abt some dead dude
@@hunterz3163 cope
@@sfl928 bruh you get 0 women
@@carmen_13 bro has 💅 in his bio 💀
Professor Dave, you continue to deliver on the kicks in the discovery.
Learning that Hyperbolic geometry is literally geometry with Hyperbolas has warmed my soul
Great video Dave. Enjoy all your uploaded material. You truly have mastered the art of distilling a topic to it bare essence. Your fan following is very lucky to have you. Just missed one small point though in this particular video. You forgot to explicitly describe the relationship between these trigonometric hyperbolic functions to an actual graphical hyperbola. That I think would have made the video just a tiny bit more complete.
what is that relationship?
Caranya.seorang.seni.bangunan.
It was the best . I liked your video very much. I was so confused about these h functions but your amazing video helped me a lot. Thank you very much sir.
Might have mentioned that y=cosh x makes a catenary.
Brilliant. Truly short and poignant, thank you for making this and uploading it.
What has my life come to
No*x^3
Yes*x^2
No*x
Yes
@@chemicallystimulated476 No*x^-1
I have been roaming for so long
But finally i have found him 🙏
His name is Professor Dave
I never learned hyperbolic functions in Calc 2, this is a great help in calc 3
I Had a calculus class this morning about this exact hyperbolic functions, and it took 90minuts, and professor dave finished it in 7 minutes.
Thank you professor dave
The graph of the system
y = (1/2)e^x
y = -(1/2)e^x
is clearly not a hyperbola. On a hyperbola with no vertical asymptotes, the limit of dy/dx as x approaches plus or minus infinity should be finite (it should approach a line). For y = (1/2)e^x , dy/dx = (1/2)e^x which increases without bound as x approaches infinity (the graph does not approach a line).
Agreed! i'm not taking anything away from Professor Daye, but the grapth of Ae^x is the graph of the exponential function, not the graph of the hyperbola. The easy equation of a hyperbola is y=1/x. the area under that curve is ln. the inverse function of ln is e. so there's ur connection b/n e and hyperbolas. A rotated hyperbola has the equation y^2-y^2=R^2
@@MrWill2714 But those are really hyperbola.
The hyperbolic functions do come from a hyperbola, Dave's explanation is not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy."
Dave is generally very good, but he's wrong about this.
Wish you were my face to face teacher!!
Wish you were my face
@@nyksiex 🤣🤣🤣
The video I was searching for..,is Finally found👍. Very well explained
I am from india but
I understand thes explain easily
So I want to tell you
Thank you very much
Very good and conceptually clear explanations.
If I pass Calc it’ll be because of you 💕
blessings to professor dave
Awesome and lucid explanation
Just amazing, way better than our teacher in Universities.
thanks professor jesus, helps a lot
Amazing video and epic intro !!!
Hi buddy
Thank you Professor Dave, this came in handy in Engineering Math
well explained sir dave.
You're so good at teaching, sir!
It's amazing how similar they are to normal trignometric functions!
Umm... Thank you. Will help me alot for my exam.
Thankyou sir , your lecture helped me from a horrible maths class .
Wait..I don't get it!
Why (e pwer y) Times (e bower -y) is equal to 1???
I need to understand.
Amazing explanation sir! Keep doing.. great work!
Thanx for explaining
I'm disappointed in this vid. Professor Dave is my favorite for math videos to assign to my students, because the vids are professionally made, clear, understandable, and have good graphics. Some math vids are just unwatchably bad.
I need a good vid on hyperbolic functions, but this one has a glaring error. Dave says that 1/2 e^x and -1/2 e^(-x) form a hyperbola. They do not. Hyperbolas have linear asymptotes. Exponentials do not.
The hyperbolic functions do come from a hyperbola, but that's not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy"
I want a vid with the production values of Professor Dave Explains, but with a correct explanation of how the hyperbolic functions relate to the unit hyperbola, and there isn't one. I'm bummed.
Then make it lazy teacher
@@ConceptualCalculus You might not struggle so much with your job if you could depend on your teaching instead of other people's videos
Weird flex but ok
He's not saying that it makes a hyperbola. It makes a function called a hyperbolic sine. It is related to hyperbolas in a similar way that sine and cosine are related to the circle, but it isn't a hyperbola itself. It also has a lot of properties in common with sine and cosine, but it isn't either of those functions either.
@@carultch I know what the hyperbolic sine function is. That is not the point. Listen to the vid from 1:20 to 1:35, where he says:
"Now what does this mean graphically? Well, let’s take this expression and break it up into two terms: one-half e to the x, minus one-half e to the negative x. If we sketch these two curves, we get a hyperbola."
That is incorrect. Sketching those two curves does not create a hyperbola.
Super.... It was very easy for understand
Happy Birthday Danae Bertoli from Arkadiko Dramas in Greece. #happy18#zoom#Panagiotis#Efthimis#corona
Happy birthday darling, we still love you, even if you didn't come to the first computer class
Thank you so much, this was very helpful!!
Thank you father
Happy teacher's day sir ❤🎉
Thank you, sir
That's exactly what I needed. Thanks.
Thank you so much. Helping me a lot!
Thanks, Dave! God bless you, brother!
Really helped thank you
Curse you Texas Instruments users. Casio is standard for us Aussies :)
I just bought an FX-82AU plus II for $12 (Co-op Bookshop on campus had a 70% off clearout on everything), but I kinda have strong feelings for my decade old FX-100AU. Can't have enough calculators.
I'm pretty sure 90% of the people on the planet use casio calculators
Thanks for the translation, it was amazing information❤
Very comprehensive thank you sir.
Simple and to the point thanks a lot
Sir..you are simply superb!!!
Please explain Taylor's theorem for differentiability of function..
THANK YOU SIR
GOD BLESS YOU
My perfect tutor you and chatGPT. I hate my actual tutor never explained well
Thanks a lot for the amazing explanation sir
Thankyou😊
Thanks
Thanks prof Dave
This is a very uncharacteristically dry presentation, and you haven't really shown how the hyperbolic functions are related to the hyperbola _in the way the the regular trig functions are related to the unit circle._
Also, we now officially call sech "SHREK".
What math class do you learn this in?
Hi dave
Sir pls explain about Spintronics .....
You didn't give the derivative of inverse of cosech , sech and coth
Superb sir
Am happy fr this
Thanks sir.u are best
is their anti derivative the same as the ones with trigonometric functions too?
nope. the signs are different. that change in sign made all that huge difference.
example:
d[tanh^-1 x] = 1/(1-x2)
d[tan^-1 x] = 1/(1+x2)
and no you cant multiply the other by negative to get the other. they are completely different.
That was helpful
You're the man
well done good explanation , thank you
Tq so much but one suggestion that subtitles in this vedio disturb to see the equations
Turn off caption in your settings
thank you so much
Sir plz solve this problem,
Cosh1/2x=√1/2(1+coshx)
Which country you have live
i loved the intro
تشکر از شما استاد بزرگ👍
Very good
Anyone noticed that cut at 3:20?
Hello , What is the range of sin h when y=0
the range of function has nothing to do with the coordinates, the range still same which is all real numbers
Due to the subtitles can't able to see the lower portion plz do something to solve its an earnest request🙏
just turn off subtitles for those sections
I love this man
Jesus himself is on our rescue.
Amazing
"I don't always drink hyperbolic functions. But when I do, I prefer Dos Hyperbolas - The most interesting function in the world."
So nice sir
Thank u sir
Taking this in high school
Which app you use to edit
Adobe after effects
I watched the intro 10+ times
Omg you are a life saver 😱
Nice
thanks sir .But electricity vedios may i get ur playlist ?
all my playlists are on my home page, try classical physics.
Nice TY
يخي انقذتنا،،شكرا
Sir rice attracting chemicals nema
No understand 🤔😔😔
legend
Genius
!
Thank you math jesus
Jesus. You are genius! 🤯🙏
does someone know what is the equation of the hyperbola at 1:32 in terms of x and y ? I suppose it has to have an xy term that makes it rotate like 45 degrees ?
That's not a hyperbola. Those are exponential functions.
@@FerretWarlord1 so it is wrong what he is saying in that part ?
I would say that yes, that is an apparent error. That said, the point of this section is to demonstrate that the sinh function is the sum of these two exponential curves.
thank you, calculus jesus
Is sech a one one function ?
No.
Great Sirrrr... You are superstar... I understood the whole... B)