Its 2:46AM and I'm super tired studying at a Starbucks at the moment.I have a physics 270 test in 5 days and I really want to crush this one. Physics is a subject I've come to love and I want you to know I really enjoy your content it's only amplified my studying experience. You are always very clear and well paced as you explain. Thanks for the help!
hello sir can you help me in a case which an insulated pipe and fluid inside it and heat transfer with the surrounding air , And I have calculated the heat loss rate already but can't calculate the final temp. !!?
Based on your description, we cannot form a picture of what is happening or what you are asking. Any liquid or gas that flows through a pipe will lose energy through the walls of the pipe. Therefor the temperature of the fluid will drop in reference to the starting point at presumably a specific temperature. The rate of heat loss depends on the difference in temperature between the inside and the outside, and the thickness and type of material the walls are made of. Thus the rate of heat loss deminished with greater distance from the source point.
Please how do we get the final temperature when initial temperature is given ,numberof moles,volume is constant and pressure isnt given but internal energy is given
More specifically use following equation for final temperature you will get : T= f1.n1.T1+ f2.n2.T2/(f1n1 + f2n2) f= Degree of freedom n= no. of mole T= temperature
sir i have a question from the final temperature equation its given that , 1 mol of N2 at temperature To and one mole of He at temp 7/3 To are mixed . what is the final temp of the mixture . i applied the final temp formula but i could not get the answer . the right answer is 3/2 To.
More specifically use following equation for final temperature you will get : T= f1.n1.T1+ f2.n2.T2/(f1n1 + f2n2) f= Degree of freedom n= no. of mole T= temperature As far as your question: T= (5×1×To)+(3×1×7/3To) / [5×1+3×1] T=3/2To
You will find a lot of similarities with equations for different concepts in physics. (I was once able to solve an engineering problem by assuming that the E&M interaction between circuit lines in multi-layered circuit boards followed the same interaction between high voltage power lines, and the equations where an exact match)
@Shashwat Saxena how does that happen? Gases flow from high to low pressure and if theres no pressure gradient they wont mix, unless if you're talkinh practically where the two gasses are linked to each other and they mix there, but thats negligible.
The internal energy depends only on 3 things. 1) The number of degrees of freedom which is represented by Cv 2) The number of mols of the gas represented by n and 3) The temperature of the gas.
I just had this question on a final exam and it was the only one I got wrong. No value was given for the specific volume. Only the initial pressure and temperature of both gases and final temperature of the mixture. The problem was to find the final pressure. The problem also did not state which ideal gas I was working with so there was no way to find the specific volume from a chart. How am I supposed to find the final pressure given that much information? If the specific volume was given, I would have been able to answer it.
You start with the equation: PV = nRT (This applies to any type of gas, monatomic, diatomic, etc.) Then you need to determine which of the 3 state variables remains constant. Based on what you describe, the volume probably remains constant (although not explicitly stated). Then the equation become P/T = rR/V = constant. Thus P1/T1 = P2/T2
@@MichelvanBiezen Sry, I should have specified more: I mean the 137 video long complete playlist. In that one it is missing between Physics-Thermodynamics: States (9 of 10) Work Done By A Gas (Basics) and Physics - Thermodynamics: (1 of 22) What is the First Law of Thermodynamics
That makes the problem somewhat harder. You have to calculate the relative internal energy and find the weighted factor based on the amount of each gas.
@@MichelvanBiezen More specifically use following equation for final temperature you will get : T= f1.n1.T1+ f2.n2.T2/(f1n1 + f2n2) f= Degree of freedom n= no. of mole T= temperature
Its 2:46AM and I'm super tired studying at a Starbucks at the moment.I have a physics 270 test in 5 days and I really want to crush this one. Physics is a subject I've come to love and I want you to know I really enjoy your content it's only amplified my studying experience. You are always very clear and well paced as you explain. Thanks for the help!
Well explained and the no change in internal energy concept was just great!
Glad you liked it!
I know im late but I LOVE YOU DUDE I WAS STUCK FOR LIKE FOR 3 HOURS WITH THIS DERIVATION ANS YOU HELPED ME UNDERSTAND IT! THANK YOU SO MUCH
You're welcome! Glad it helped.
So easily explained... Thank you so much
3:18 by mixing of gases volume of left gas changed from V1 to V1+V2 this work must be done😧?
Work is only done if the volume of the container is increased. In this case the volume of the container remains constant..
So, the initial pressure of both gases is not needed?
It depends on how you want to solve the problem. It can be solved in multiple ways, some of which will require the initial pressure.
hello sir can you help me in a case which an insulated pipe and fluid inside it and heat transfer with the surrounding air , And I have calculated the heat loss rate already but can't calculate the final temp. !!?
Based on your description, we cannot form a picture of what is happening or what you are asking. Any liquid or gas that flows through a pipe will lose energy through the walls of the pipe. Therefor the temperature of the fluid will drop in reference to the starting point at presumably a specific temperature. The rate of heat loss depends on the difference in temperature between the inside and the outside, and the thickness and type of material the walls are made of. Thus the rate of heat loss deminished with greater distance from the source point.
Please how do we get the final temperature when initial temperature is given ,numberof moles,volume is constant and pressure isnt given but internal energy is given
Sir, the formula T=(n1t1+n2t2)/(n1+n2) is valid for mixing mono with mono? what about dia with dia ? and mono with dia?
i think then you would also need to find the Equivalent Cv of the mixture.
More specifically use following equation for final temperature you will get :
T= f1.n1.T1+ f2.n2.T2/(f1n1 + f2n2)
f= Degree of freedom
n= no. of mole
T= temperature
Cv cancelled out and the first equation has no dependency on Cv
Valid for mono+mono , dia+dia, tri+tri etc-- in case of dia+mono, tri+mono etc- go with @Anmol Emprire's formula, it is generalized!
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got job?
Got job?
Got job?
sir i have a question from the final temperature equation
its given that , 1 mol of N2 at temperature To and one mole of He at temp 7/3 To are mixed . what is the final temp of the mixture .
i applied the final temp formula but i could not get the answer . the right answer is 3/2 To.
More specifically use following equation for final temperature you will get :
T= f1.n1.T1+ f2.n2.T2/(f1n1 + f2n2)
f= Degree of freedom
n= no. of mole
T= temperature
As far as your question:
T= (5×1×To)+(3×1×7/3To) / [5×1+3×1]
T=3/2To
@@anmolempire1197 heyy thanks!!
@@anmolempire1197 Absolutely correct, i derived it too, ya'll can be sure it's the right formula!
Correct. If you mix 2 gases with a different specific heat, you also have to account for that.
@@MichelvanBiezen thank you sir :)
The equation for the final temperature has exactly the same form as the coordinate for the resultant force in a moment problem.
You will find a lot of similarities with equations for different concepts in physics. (I was once able to solve an engineering problem by assuming that the E&M interaction between circuit lines in multi-layered circuit boards followed the same interaction between high voltage power lines, and the equations where an exact match)
What about entropy generation?
Can this equation be used for the final temperature of two air masses?
Yes, but they do need to give you the intial temperature.
@@MichelvanBiezen thank you for your reply!
if you substitute n1=P1V1/RT1 and n2=P2V2/RT2 into the Pf equation, it simplifies into a very satisfying form Pf=(P1V1+P2V2)/(V1+V2)
Thank you.
Can Tf be expressed in an equation without n1 and n2 as well?
hello sir, do you know any good physic forum
Sir I have a question. What if two different volume of gases having same temperature and pressure. Can it be mixed? If yes how?
If pressure is same, gases cannot be mixed
@Shashwat Saxena how does that happen? Gases flow from high to low pressure and if theres no pressure gradient they wont mix, unless if you're talkinh practically where the two gasses are linked to each other and they mix there, but thats negligible.
sir i want to ask, where did you get U = n Cv T???
The internal energy depends only on 3 things. 1) The number of degrees of freedom which is represented by Cv 2) The number of mols of the gas represented by n and 3) The temperature of the gas.
Simply Outstanding.
Glad you like it!
Hmm ....... was an interesting question
Sir can you plz make a video on entropy of mixxing of 2 gases?
We have a few videos on entropy in a gas in this playlist: PHYSICS 32.5 - STATISTICAL THERMODYNAMICS We'll look into adding that one.
Thank you so much for your kindness. It saved me.✨🍀thank you,thank you
Glad you found our videos helpful. 🙂
Dr all of these thermodynamics videos are applied on the course for mechanical engineering???
I just had this question on a final exam and it was the only one I got wrong. No value was given for the specific volume. Only the initial pressure and temperature of both gases and final temperature of the mixture. The problem was to find the final pressure. The problem also did not state which ideal gas I was working with so there was no way to find the specific volume from a chart. How am I supposed to find the final pressure given that much information? If the specific volume was given, I would have been able to answer it.
You start with the equation: PV = nRT (This applies to any type of gas, monatomic, diatomic, etc.) Then you need to determine which of the 3 state variables remains constant. Based on what you describe, the volume probably remains constant (although not explicitly stated). Then the equation become P/T = rR/V = constant. Thus P1/T1 = P2/T2
Thanks you so much for the explanation, 😊
You're welcome 😊
Thank u so mush it helped me alotttt❤️❤️❤️
Glad it helped!
why no work?
Why can we assume that the gas is doing no work in order to expand?
Cuz the volume is constant
Thank you professor
You are very welcome
I think this video is missing from the main thermodynamics playlist. The states section ends with 9 of 10 :)
It is in the playlist, it may be missing from the website: PHYSICS 26 THE IDEAL GAS EQUATION
@@MichelvanBiezen Sry, I should have specified more: I mean the 137 video long complete playlist. In that one it is missing between Physics-Thermodynamics: States (9 of 10) Work Done By A Gas (Basics) and Physics - Thermodynamics: (1 of 22) What is the First Law of Thermodynamics
Great Lectures.
Hello professor this was really amazing. Well I wonder what will happen if they don't have specific heat?
OK that make sense.....but what happen when specific heat are different?
That makes the problem somewhat harder. You have to calculate the relative internal energy and find the weighted factor based on the amount of each gas.
Please.... make a video on it
Physics Guy It's not that hard. Send me an email to marvin.salguero.p@gmail.com and I'll send you an exercise about it
Do you have answer for it when both having same cv
@@MichelvanBiezen
More specifically use following equation for final temperature you will get :
T= f1.n1.T1+ f2.n2.T2/(f1n1 + f2n2)
f= Degree of freedom
n= no. of mole
T= temperature
wow this worked.
Impressive
Wow