Question 3rd numerical ... Focal length - 400/11 And power - 2.75 dioptre The lens is converging ( convex) Challenger question ans. Distant vision f - -18.18 Near vision f- +66.6
@@sabeehamazhar504use the freaking formula, take v as -80 and u as -25 use the lens formula to find focal length then find the power using the formula P=1/f.
Sir can you make another one shot video for 2023 boards including mcq and other necessary questions that are must for the school boards class10 I would be thankful to you🙂😉
Generally,we take focus in metres only in case of determining power and if we have been asked to find just focus then cm is used commonly. but if u want , u can find in metres also but don't forget to convert all the value in same units when u have to use lens formula
Sir you are 2nd best teacher of physics on TH-cam because the 1st on is unbeatable (Alakh Pandey Sir) but i love you teaching technique. I am in class 9 inside of this I caught every topic of this chapter very easily because of you Love ❤from Patna
Sir, in iris the amount of light entering the eye by adjusting the size of pupil ..... But u say that in pupil it regulates the amount of light entering to the eye ... Sir plz comment the answer that which one is right or wrong .... I also check in Google but iris help the amount of light entering to the eye ... Hai ... But knowing & research this I think that ur answer is wrong .... So plz answer my question sir ..... l hope you may answer the comment 🙏🙏🙏
human eye ncert pg no. 188 in the paragraph of ''power of accomodation'' in the 4th line its written that ''when the muscles are relaxed,the lens becomes thin''. but sir is telling the exact opposite in the video at 15:19 . i am really confused please reply
@@chaipeelo274😮Friendship is a devoted relationship between two individuals. They both feel immense care and love for each other. Usually, a friendship is shared by two people who have similar interests and feelings.
Sir I have a doubt as you said when ciliary muscle relaxed the lens become thick and the focal length become small . But in our text book when the ciliary muscles relax the lens become thin and the focal length increase.
Sir iam from Maharashtra board but i follow ncert by physics wallah. Your explanation is very realistic and it gives the power to imagine the physics because I love physics ❤❤❤❤ . Love you sir.
Are idiots dono answer thik hai bas cm aur m ka difference liya hai tumne parthsoni2118 ne m ke liye P = 1/f liya hai aur tumne cm ke liye P = 100/f liya hai . Be attentive in the physics wallah classrom ....😊😊
One of the best physics teacher in the country I have ever seen 🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳❤️❤️❤️❤️❤️❤️❤️🧡💛🧡💛🧡🧡❤️💛❤️💛❤️💛❤️💛❤️💛❤️💛❤️💛❤️💛❤️💛❤️🧡🎧🧡❤️💛❤️💛❤️💛❤️🧡🧡💛🧡💛🧡💛🧡💚🤎💚🤎💚🤎💚🤎💚🤎💚🤎💚🤎💚
I have very important question to ask! As you said In the video that for the correction lense the object Will be the real object but for the crystalline lens the object Will be the virtual or in other words the image of the correction lens! but how is it that the image of the correction lens has it behind of the lens!??
HERE THE VALUE OF (F) IS +400/11 AND THE VALUE OF (P) IS +2.75D. THEREFORE, THE LENS IS CONVEX LENS AND SINCE IT'S NATURE IS CONVERGING LENS. WONDERFUL 😃EXPLANATION BY YOU SIR I UNDERSTOOD ALL THE THINGS CLEARLY👍 LOTS OF LOVE FROM MY SIDE 💖❤🥰
@@KalpanaTandon4247kyuki wo cm me he to metre me 1/f hota ha but jab cm me hota he to m se cm jane se 100x hota he so upar 100 chala jata he . So P=100/f in cm
53:42 YAAR LOGO KO AISA Q LAGTA HAI KI GEETA RAMAYAN SIRF BUJURG HI PADHTE HAI? HAMARE PARIWAR ME TO SBHI NE PADHA HAI EVEN MAINE BHI AUR MERA DHRM BHI YAHI KEHTA HAI !! FIR HAMARE GRANTH BUDDHE LOGO KE LIYE HI SIMIT KYUN HAI?🙂
Neurosurgeon hu bai mai Mere bete ko muje padhata nai ata kyo ki muje high level ki baate he aate hai isliye usse samajh ahe isliye mai is channal ko use recommend karta hu because its best channel for learning
15:45 sir you said that when muscles are relax then lens is thick And when muscles contracts then the lens is thin But it is just opposite. But no problem, because every human being make mistakes I write this so that everyone can learn write thing who are depended on you and me also 😅
Rod and cone cells are present on retina and transfer the light signals to electrical signals and these electrical signals are interpreted by the brain. But in case of myopia or hypermetropia when image is formed behind or in front of retina then at that place no rod and cone cells are present So there is nothing to transfer the light signals into electrical signals so then no image should be formed But still a blurred image is formed???
Power of lens formula = p=100/f -5.5=100/f then f is multiple with -5.5 -5.5f=100 F=100/-5.5 F=-18.18 cm in m =- 0.18m Do this same process again next question:
Sir i have a doubt, In NCERT, it is given that when muscles are relaxed the lens become thin. And here u r telling that the becomes thick. I am confused about this now sir ,
Sir I have a doubt if maximum focal length is 2.5 cm and minimum 2.27cm then the lens 2f must be 5cm if the image always forms at 2.5cm then the object should be beyond C which is beyond 5cm then when we place object at 7or 8 why is the image blurr because image forms between F and 2f e
I am from AMU board and i always watching every chapter videos of physics from 9th class.your explanation is very well and easy to understand topics god bless you sir
1:07:18 Let first power be P1 and second be P2 and also P1's focal length be f1 and P2's focal length be f2 then, f1 = 1000/-55 = -18.19 cm (approx) f2 = 1000/15 = 66.67 cm (approx)
Sir very good teaching but when ciliary muscles relaxed the lens becomes thin but you said opposite to it I just want to make clear it for other students like me
Focal length = 36.36cm
Power = 2.75 dioptre
Nature = converging
Kese nikala
बहन सही ha
1:07:00
Numerical:
f=400/11
p=+2.75D
lens required- convex lens
nature- converging
Nice
Bhery Goot
super
1:08:20 boht acccha padhaye sir aap 🙂 best video lecture on human eye and the colourful world👍👍👍👍👍👍🙏I just wanna thank you
Tum hi top karoge yarr 🥰🤗
Question 3rd numerical ... Focal length - 400/11
And power - 2.75 dioptre
The lens is converging ( convex)
Challenger question ans.
Distant vision f - -18.18
Near vision f- +66.6
Power of convex lense is postive
Focal length is also positive
Q3 power= positive 2.75 nature=converging
Challengeer Q ....for distant F= -18.1 Cm for near vision F= 66.6cm.
😢
Q.3 = 2.75 D. Convex lens , converging type.
Plz explain
Ya it's right
Ya you are right
@@pcprashantchaudharygaming4896 kaisa hai
Good
🙏big fan of physicswallah team
I'm also
Biggest fan😎
I,m also🥰
i also
My name prateek jha same sir name
Q3- f=36.36 cm
P=+2.75 D
Nature is converging (convex)
How?
@@sabeehamazhar504use the freaking formula, take v as -80 and u as -25 use the lens formula to find focal length then find the power using the formula P=1/f.
Sir can you make another one shot video for 2023 boards including mcq and other necessary questions that are must for the school boards class10 I would be thankful to you🙂😉
😢😢😢🎉🎉🎉😢
😅
😅😊
🙏
🙏
Q3 == +2.75D nature of lens = converging
Challenger question==
Distant vision= -18.18 cm
Near vision= 66.66 cm
How do you know that answer will be in centimeters it can be in meters also
Generally,we take focus in metres only in case of determining power and if we have been asked to find just focus then cm is used commonly. but if u want , u can find in metres also but don't forget to convert all the value in same units when u have to use lens formula
How is answer 2.75D??
Loved the class sir! You are an excellent teacher!!!
True
100/true
Sath prate sath
Yes true
You are right
I just loved the way of teaching . Maja aa gaya sir 🙏🏻🙏🏻
Starting animantion was superb and give me thrill ❤️❤️❤️❤️ and ur voice was also changed😁😁
Sir you are 2nd best teacher of physics on TH-cam because the 1st on is unbeatable (Alakh Pandey Sir) but i love you teaching technique. I am in class 9 inside of this I caught every topic of this chapter very easily because of you
Love ❤from Patna
Pahle 9th padhlo
@@143_Prince-.😂
Sir, in iris the amount of light entering the eye by adjusting the size of pupil ..... But u say that in pupil it regulates the amount of light entering to the eye ... Sir plz comment the answer that which one is right or wrong .... I also check in Google but iris help the amount of light entering to the eye ... Hai ...
But knowing & research this I think that ur answer is wrong .... So plz answer my question sir ..... l hope you may answer the comment 🙏🙏🙏
1:07:07
Focal length= 400/11cm
Power= 2.75D
Lense= convex lens
Also converging
😅
human eye ncert pg no. 188 in the paragraph of ''power of accomodation'' in the 4th line its written that ''when the muscles are relaxed,the lens becomes thin''. but sir is telling the exact opposite in the video at 15:19 . i am really confused please reply
1:07:17 (i) Distinct Vision :- f=-0.181m
(ii) Near Vision =0.66m
Bhai kaise bnaya tune?
@@sukuna7890 focal length is reciprocal of power
Bhai, Challenger question to Mazak tha, Matlab Kya bolu🤣, bohot zyada easy tha
Dono ka ans -18.18
😂
(i)distinct vision = -18.18 cm= focal length
(ii)near vision= 66.66cm= focal length
Bhi galt ha
Focal length 3.2 CM
ha
@@darknightgaming7255bhai power dia hi hain uska reciprocal chahiye 😂
PW is a great team and working institute
1:07:11
Focal length is 36.36 cm
Power is 2.7 D
Nature : converging (convex)
Also
In last question :-
(i) -0.18m
(ii) 0.66m
By swati Sharma..
Concex 😂
How?
@@chaipeelo274😮Friendship is a devoted relationship between two individuals. They both feel immense care and love for each other. Usually, a friendship is shared by two people who have similar interests and feelings.
Power of the lens =Plus 2.75D
Type of the lens is converging lens
Thanks sir It helped a lot ...🙏
👌👌 very fast answer bro
Congratulations 🎇👍👏
15:50 Mistake! Pls make a correction everyone
When eye lens relax it becomes thin and when eye lens contracts it becomes thick.
Saste Nash mat karo😂😂
@@rohanraj7835he is saying true brother
Yes 🥰 all human sometimes makes mistakes. It should be tolerated...!!
@@rohanraj7835 Yes he is saying the truth only
Who cares
Thank you so much sir for teaching in such a great way...💯
Hi
Q3. P=+2.75D
Nature: Converging (convex)lens
Challenger question
I)-0.181m
ii)0.667m
01:7:23 q1- distant vision = -0.18m and near vision =+0.66m
Kaise aya bhai pls explain
Ye kese aaya ?
Power ki formula kya hai 1/f ya 100/f?
Aap gjb ke padhate ho sir ,dil se thank you 💯💞🙏
Sir ncert ke bahar ka bhi explain kar diya kariye achha hai hm competition wale bacche bhi aap ki class dekhte hain..
Thanks sir.
Sir I have a doubt as you said when ciliary muscle relaxed the lens become thick and the focal length become small . But in our text book when the ciliary muscles relax the lens become thin and the focal length increase.
Right
I have faced the same problem
Plz solve this problem
I have faced the same problem. Plz
Plz sir sort our this problem
Sir your teaching is super duper !!!!😊😊
The best physics teacher that i have ever seen is you sir
You are right
No Sanjiv sir is best
Alakh pandey ko jante ho ya MR sir ko
He is Second to alakh sir
@@studypoint2966 from edumantra ?
Sir iam from Maharashtra board but i follow ncert by physics wallah. Your explanation is very realistic and it gives the power to imagine the physics because I love physics ❤❤❤❤ . Love you sir.
Que3. Nature of lens is convex and Power is +2.5
Challenger. (i) 0.18 and (ii) 0.67
Thanks for the great session sir😇
Glt hai
@@aaryanrupa4158 18.18 hai kya sahi ?
Are idiots dono answer thik hai bas cm aur m ka difference liya hai tumne parthsoni2118 ne m ke liye P = 1/f liya hai aur tumne cm ke liye P = 100/f liya hai . Be attentive in the physics wallah classrom ....😊😊
galat hai3rd ka ans 2.75 D hai@@YASHSHARMA_045
Sir ,nature :-convex lens
Power:- +2.75 D
Bhai nature converging hoga.
Convex lens type hai lens ka .
@anshu70047
Thanks
Band kamre me Kam Karte Hai 😂😂😂 rakshk sir funny dialogue 😅😅😅😂😂😂😂😂😂
Ans of challenger question
(i) f= -18 cm or -0.18m
(ii) f = +66 cm or + 0.66 m
Hope it helps u 😊😊😊
Correct 💯
How??? Plz
@@manuchaudhary4849 Apply p= 1/f with sign
@@manuchaudhary4849 apply p=1/f for finding ans in metre and for finding ans in cm apply P=100/F
@@ethicalhackervishu6041 thanku💕
One of the best physics teacher in the country I have ever seen 🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳🥳❤️❤️❤️❤️❤️❤️❤️🧡💛🧡💛🧡🧡❤️💛❤️💛❤️💛❤️💛❤️💛❤️💛❤️💛❤️💛❤️💛❤️🧡🎧🧡❤️💛❤️💛❤️💛❤️🧡🧡💛🧡💛🧡💛🧡💚🤎💚🤎💚🤎💚🤎💚🤎💚🤎💚🤎💚
Where is purple heart
1:06:11
Ans - Converging lens (convex)
P = 2.75 Dioptre
Converging but how
@@mahi_536 bcoz it is convex lens and convex lens is converging lens.
Right 🤛
Because power is in +ve diapter convex lens
Bhai mera toh .00275 aa raha hai
What is hypermetropia? State two causes with help of ray diagram show a , this defect b, correction of this defect
Hi sir ap ke lecture bhot acha hai sir,,😮
I have very important question to ask! As you said In the video that for the correction lense the object Will be the real object but for the crystalline lens the object Will be the virtual or in other words the image of the correction lens! but how is it that the image of the correction lens has it behind of the lens!??
Write the question in the systamatic way to understand
@@itsmeayush3377 I mean the object what we are seeing through a corrective lens is a virtual right?
The eye itself sees this virtual image as if it was the actual object and creates the final real image on the retina of the eye.
@@laxmiparida4119 obviously no
@@laxmiparida4119 nope...we see real objects
HERE THE VALUE OF (F) IS +400/11 AND THE VALUE OF (P) IS +2.75D.
THEREFORE, THE LENS IS CONVEX LENS AND SINCE IT'S NATURE IS CONVERGING LENS.
WONDERFUL 😃EXPLANATION BY YOU SIR I UNDERSTOOD ALL THE THINGS CLEARLY👍 LOTS OF LOVE FROM MY SIDE 💖❤🥰
This chapter is deleted 🤔
@@shivasstories7239 No bro, it is in the syllabus of 2022-2023.
It was deleted for our seniors.
Mera P- 2.77 aara
Same answer
@@rishuvlogs5470 👍 good
Power is 2.75 d and nature is - convex lens , hypermetropic eye , converging work , real and inverted image on corrective and suitable power lens
Hi
@@madhav1550 hello
23:43 close room work 😂 by rakshak sir
sir the answer of the first given question by you is 2.74D and a convex lens with nature converging
Quesion no'3 = 2.75D ,
=Convex lens ,
=Converging type
Focal length:+400/11
Power:+2.74D correction : convex lens
🎉🎉
Power ko 100 upon f🧐🧐 kyu liya h 1 upon f kyu nhi liya
@@KalpanaTandon4247kyuki wo cm me he to metre me 1/f hota ha but jab cm me hota he to m se cm jane se 100x hota he so upar 100 chala jata he . So P=100/f in cm
sir your teaching level is awesome 🙏❤️
Q.3
P=2.75
Nature of lens = converging
Lens = convex lens
Yes, u are right👍
3 DAYS TO GO ✌🏻❤️✌🏻❤️ YOU WILL ROCK 💥
ALL THE BEST FOR YOUR EXAM 98%😃
Thanks brother
Tommorow
Thnx bhai
@Anu oh bro same mera school nhi khula but still studying
53:42 YAAR LOGO KO AISA Q LAGTA HAI KI GEETA RAMAYAN SIRF BUJURG HI PADHTE HAI? HAMARE PARIWAR ME TO SBHI NE PADHA HAI EVEN MAINE BHI AUR MERA DHRM BHI YAHI KEHTA HAI !! FIR HAMARE GRANTH BUDDHE LOGO KE LIYE HI SIMIT KYUN HAI?🙂
Sahe bola bhai
F-36.3,P-2.75D, convex lens because it helps converging the ray
Sir birds me bhi owl ke paas rodes cells present hote hai tabhi to wo night e bhi dekh sakte hai....*👌👌👍
And i am watching all ur physics classes.
Ur doing amazing sir.......
Focal length =36.36
Power of lens=2.7D
Nature =converging
Lens=convex lense
Distinct vision :p=100/f in Cm so f=100÷(_5.5) which is _18.18cm and similarly for near it is 66.6 cm
Shi h
You are right bro
Actually challenger question was easiest one🙂
1)-18cm is focal length(concave lens hai)
2)66cm focal length(convex hai)
Yeah you are wrong you did 100÷5.5 which is wrong 😅
@@dhararajpara9916 centimetre mei laane ke liye 100 se hi multiply krte h
you all are wrong
The both ans is -18.18
All teachers are amazing 😍😍
☺️☺️☺️
Nice
@@md_ankit_unique5957 hlo bro 💗
Neurosurgeon hu bai mai Mere bete ko muje padhata nai ata kyo ki muje high level ki baate he aate hai isliye usse samajh ahe isliye mai is channal ko use recommend karta hu because its best channel for learning
Sir really you teaches very well, I love your teaching style sir❤
Chalenger question:-
1) distant focal length = -1.81m(-181cm),
2) near focal length = 0.66m(66cm)
Galat
1st wala
Yes it is 0.1818..
@@meitnabhikhaasnahi1470 is 18.1 cm focal length correct?
yes it's correct
What are teachers of physics wallah ! amazing 🥰🥰
Sir you are amazing 👏 you are the best teacher of the world 🌎
Sir you're the only reason I love PW😭❤
Oho accha hai
Logo😂
@@raj.Khateek007 ??
@@YASEEN-SHEIKHlogo me suar ka chehra kon lagata he🤣
Yes I also ❤
This sir is the best in the whole team
Thank you very much, sir... always been interested in your teaching only
😂😂😂😂😂😂😂😂
P=2.75
Nature=converging
Lense=convex
Nahi aaya yarr
Correct vro 👍🏻
F=36.36 and,
P=2.7
Badhiya Bhai mujhe bhi ans check karna tha accha hua likh diya 👍👍
@@ranjeetsingh-fe7qn 👍👍
very interesting way of teaching art student hone k bd bhi boht ache se smjh me aya thank u sir
15:45 sir you said that when muscles are relax then lens is thick
And when muscles contracts then the lens is thin
But it is just opposite. But no problem, because every human being make mistakes
I write this so that everyone can learn write thing who are depended on you and me also 😅
Rod and cone cells are present on retina and transfer the light signals to electrical signals and these electrical signals are interpreted by the brain.
But in case of myopia or hypermetropia when image is formed behind or in front of retina then at that place no rod and cone cells are present
So there is nothing to transfer the light signals into electrical signals so then no image should be formed
But still a blurred image is formed???
Challenger question- Focal length for lens of power -5.5D is -18.18cm and for power of 1.5 D is 66.66cm
How?
Power of lens formula = p=100/f
-5.5=100/f then f is multiple with -5.5
-5.5f=100
F=100/-5.5
F=-18.18 cm in m =- 0.18m
Do this same process again next question:
Distant vision - 0.18 m
Near vision - 0.67 m
Your answer is wrong
For near vision:1000/1.5
For distant vision:1000/-5.5
Best lecture for the topic thank you very much sir 👍👍👍👍
Sir you are the life of physics in 10th ❤❤
Now l am in 11th and l miss my 10th days 🎉
Why u watching dis
@@JAANY_GAMER for memories i suppose
@@goofyahhswastik anybody ask
@@JAANY_GAMER u literally asked??
@@abhi.108 bruh man
Gjb pdhaya sir ne sb numerical to bilkul clear ho gye
Ekdm shi
Best explanation sir! Thank you so much ☺️
Sir u r very cool🔥❤️❤️
39:48 (with great power comes great responsibility )
Sir l love your physics u r great teacher of physics 💓🙏
Jitna acha sir smjatai hi iss sai acha koi nhi sikhavai ga duniya mai best of luck sir❤❤❤❤❤❤
Q. No.-3
Focal length= 36.36cm
Power= 2.75D
Nature= Covex lens or converging lens
One of the best physics teacher 🤗🤗
we need teacher like you in our school
Thank you sir for this session and for helping us 😊
Sir aapki drawing se me khush ho gya love you sir❤❤❤❤😊😊😊😊
Sir i have a doubt,
In NCERT, it is given that when muscles are relaxed the lens become thin.
And here u r telling that the becomes thick.
I am confused about this now sir ,
Yes
Sir I have a doubt if maximum focal length is 2.5 cm and minimum 2.27cm then the lens 2f must be 5cm if the image always forms at 2.5cm then the object should be beyond C which is beyond 5cm then when we place object at 7or 8 why is the image blurr because image forms between F and 2f e
6 sns
❤️ Top notch explanation sir ❤️.
From Maharashtra board ( eng medium )
bro MH board me kitne percent aye?
@@SUMIT08-07 96.60%
I am from AMU board and i always watching every chapter videos of physics from 9th class.your explanation is very well and easy to understand topics god bless you sir
ham bhi amu se hi hain
Acchaa bhai
@@anees_khan338amu?
" Aligarh Muslim University " (Amu)
are phones allowed in amu class 9th hostel
1:07:18 Let first power be P1 and second be P2 and also P1's focal length be f1 and P2's focal length be f2 then,
f1 = 1000/-55 = -18.19 cm (approx)
f2 = 1000/15 = 66.67 cm (approx)
Thanks this was my 2nd time on this channel
And , I'm greatful sir that u have taught me the trick to solve numericals
Sir very good teaching but when ciliary muscles relaxed the lens becomes thin but you said opposite to it I just want to make clear it for other students like me
Ys same doubt
1:07:00
P=2.75 D
Convex lens - converging nature
Pls explain ki focal length -400/11 kaise aaya?
@@rudrakumar3037 ye 2.77 aayega na??
Thank you so much Sir for this amazing lecture
Focal length : 36.3
Power : 2.75 D
Thanks ans ke liye😊
23:35
It sounds different sir😛😛
F = 36.36
P= +2.75D
15:17 Actually there's a little correction the lens becomes thin when the cilliary muscles relaxes not thick as told by you.
Wrong
Gajab sir🤗🤗🤗🤗🤗🤗🤗🤗
Physics wallah foundation is great thank you physic team
Thanks sir this video is very helpful for me tomorrow is my paper and this video help me too much