Quick Solution to a 9th Grade Exponent Problem
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- เผยแพร่เมื่อ 7 ก.พ. 2025
- In this equation, both exponents 3x+1 and x ,
x must be integers for the equation to be valid in the real number system. If they aren't integers, the expression may yield complex values, which could invalidate our ability to directly compare exponents.
As an eight grader, this is extremely easy, i solved x=1 in my head, and this is NOT a 9th grade problem, but an easy exponents and powers question
It’s actually a 9th grade problem , I believe u learn this again in 9th
@@Watashi-Wa-Kat-Desu I don't think we have a exponents chapter in class 9
@@nathanaaronfernandes9698 it’s like a number system chapter where exponents are revisited
@@nathanaaronfernandes9698I'm from Bangladesh, and we do have the chapter on 9th grade.
@@Xgamer3065OG Did you have it in 8th?
In the boards in my region these problems are in 7-8
bro is done with indians saying they learnt this in 9th grade
Bro says it is from class 9 while we learned two variable exponent equations and this question is just super easy.😂😂😂
@@Maths_Wonderlandok? Do u want a medal or something
@@code4ismynameappreciated if available
@@Maths_WonderlandSo what exactly is your point
@@Maths_Wonderlandgreat, now find who asked
🎉 THIS TYPES OF EQUATIONS ARE SO FUNNY AND MAJOR
This is 9th grade math in my countrys curriculum, along with variations, quadratic formulas and functions, advanced law of exponents, basic trigonometry, etc.
X=1
I learned this in 9th grade but even a dedicated 7 year old could learn calculus
Finally an accurate video
This infact was learnt in 9th grade
IT's wrong (-8)^(1/3)=undefined
cube root of negative numbers are defined. as cube of -2 is -8, cube root of -8 is -2.. u r confusing it with even roots which are undefined for negative bases
@@ItzMexx7 cube roots are defined, however you can't write (-8)^(1/3), because:
(-2)=(-8)^(1/3)=(-8)^(2/6)=((-8)^(2))^(1/6)=(64^(1/6)=2; -2=2
brother it is defined
=((-8)^(1/3))
=((-1)(8))^(1/3)
=(-1)^(1/3)(8)^(1/3)
=((-1)³)⅓((2)³)⅓
=(-1)(2)
=-2
@@LITHICKROSHANMS-gw2lx bro I just told why is it undefined
@@zinlaggg
Ok
But also
If you dealing this way
You notice this steps
=(-8)^(1/3)
=(-8)^(2/6)
=((-8)^(1/6))^(2)
=(((-1)³(2)³)^(1/6))^(2)
=(((-2)³)^(1/6))^(2)
=((-2)^(3/6))^(2)
=((-2)^(1/2))^(2)
=(-2)^(2/2)
=(-2)^(1)
=-2
∛(-1)=-1,-ω,-ω²
So it can be
∛(-8)=-2,-2ω,-2ω²
x = 1.
Song?
6/7-th grade
Not more
bro please give me the name of the background song.🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
You're an Indian? Just testing my gut feeling
@@AnOfficialcatAgent How the fuck does a song determine someone's nationality
@@AnOfficialcatAgent yes
@@aquilfarhan4198 I figured that out from the begging in that simple sentence
The other side
This is not 9th grade math
In India it is.
Yeah it's 7th grade
This was so easy, I’m thinking this is at least 7th grade
No it's 6th grade max
No. Its beggining of 9th grade math.@AzzurroBall
Got to be careful when raising negative numbers to a rational exponent
Do scary roots find x
هذه رياضيات الصف 12 في المملكة العربية السعودية يا خيبتي على مناهجنا الزق 😂😂 بس الحمدلله مع اختبار القدرات وضعت اساس لي في الرياضات
This is 11th grade math in iran
Please give more 9 questions but increase the difficulty level
And how to you define e^xln(-2) oops😂
Check the description♥️♥️
If u want to then u can use e^ix but this gives complex solutions
I solved this question in my mind very quickly and very easily 🤓 this question is very easy.
What is your prifession sir???
What will be the 1/3 of -2 sir ????
Not talking abt imaginary
This is 7th grade math
Ok
Did this in 8th lol
6th grade math in vietnam
This is more over so 10th grade tbh
It is very easy
In india 8th class student can solve this
Shut up bruh, it says 9th for a reason, a grade doesnt make a big difference
brush look I am *c-batch* 6th grade it's too ez for me lool in sri Chaitanya school India ha
Eazy
Ver very easy
x=1
Khooda pahaad nikli chuhiya 😂😂😂😂😂
1
It is 11th grade
X=3
1
I learnt in 9th grade but doing this without scratch paper is sort of unreliable bc you could mess up a lot by doing complex exponential equations in your head
Ha bhai 9th mein hi IIT JEE crack karwa de tu. 😂😂😂😂
In india these are the type of questions that could be done till you reach grade 9
I'm clearly say that you mistaken in the method and answer is also not properly correct 😅😅 is you interested to correct it then leave a heart and i will send it in the reply of this comment 😊😊
Check the description
😊😊 ok
That ain’t 9th grade lol, probably precal from the log stuff
Nah in india this is basic 9th grade math
@@adityataparia7026As a 9th grader in India I can confirm this is not at all basic maths, this is Olympiad level stuff
Bruh as an indian, if you didnt study this level math than sorry but its basic and not olympiad level lol.@@notraging
@@notraging nah bro im in 10th grade rn and i could solve this easily in 9th grade. Our techers gave us way nore complex questions than these in 9th grade
7th grade vietnamese solved in 30 seconds im cooking
Bro made it too complicated💀
Just do to the power of 3 on both sides, remove the bases, and solve for x, no need for extra shenanigans man