R Firing Circuit of SCR

[@jaisonkuriakose5683]

നാളെ exam ആണ്....malayalam explanation ആയിരുന്നു കുറച്ചു കൂടി നല്ലത് any way very very thanks for this lecture

[@ajmalmm3553]

Madam, if the position of the load is as given in the circuit, the current will flow through load-R1-R2-D-R during the positive half cycle, even if the SCR is off , right? Shouldn't we change the load position to the right side of node A for proper working?

[@garikapaticharan7068]

VERY VERY THANKS MAM FOR YOUR IN DETAILED EXPLINATION

[@fried-_-potatoes-l]

Thank you for the detailed explanation 👍🏻

[@akblog2861]

Hello

[@m.k.narendraprasad2384]

Thank u miss....xam eluppamakki thannenu❤️❤️

[@shanthanarkanti8275]

@Anetrose When 1 st case Vg< Vgt, i flows( small) , but the same current (i) isn't it the same current flowing through load as there is a closed path? Then how can Vo is 0? Pls answer me I'm very confused madam

[@shivankitss8396]

I'm no expert... But I think.
Consider the load to be Ra. And those resistors in series, combine them to from Rb.
Since she said R2 is very large. That means Rb>>>Ra. So consider Rb as infinity.
Now using voltage divider formula.
When you put Rb as infinity. Drop across Ra becomes 0.. ie drop across load Vo is zero.

[@Ram-vg5dt]

May I know the purpose of diode placed in that particular branch

[@anetjose2836]

Diode protects the gate drive circuit from reverse gate voltage during the negative half cycle of the supply

[@Ram-vg5dt]

@@anetjose2836 tq ..

[@bibinthomasa3306]

Eagerly waiting for your lectures on POWER ELECTRONICS 🙏

[@shaikabdulrasool1444]

Nyc explanation mam

[@lethalninja619]

Thank u so much ma'am..

[@amalvm1776]

thank you teacher

[@Ram-vg5dt]

Nice explanation

[@rabiulislam3406]

sister where are you from

[@aryanrawool5899]

Mam do you have notes /hand writen what u explain

[@christinmarkose]

Well explained

[@debojitdeori4837]

Aaanod and kaaaaadod

[@akblog2861]

Than you mem

[@prakharjain3211]

circuit -> circute

[@sathishdawan8492]

Good explanation