Sir, you are the best teacher a student can get. Eagerly waiting for DBMS FURTHER TOPIC VIDEOS. Don't stop the DBMS Series . Please upload the remaining videos.
sir, thank you so much. from beginning i suffer in TOC but now my all concepts clear and hope it will carry on. you are really a best teacher in the world. thank you so much once again sir, i send you a mail please give me some time and give me reply if its possible for you. thank yo so much one again
After adding the trasition b on q1 and reach at q0 it is not only moving toward death state but also produce the ambiguity bcz there is already transition for b on q1
Thank you dear @Manish! ❤ Do like, subscribe & share the video, you can also visit our website www.knowledgegate.in for more amazing videos & contents👍😊
If we want to check for aaa......ther is loop on q1......it will take as many a's you want it to......for abaa q0-q1-q3_q1...........the last state is just temporary only to aid these kinda problems
Agr q1 state ke bad q2 state hamresa hi 'b' ata rhe kabhi a aaye hi na toh toh process ko dead state pe jana chahiye tha Means agar string 'a' se start ho rhi ho aur 'b' pe khatam ho rhi ho toh dead state nhi banegi kya ??
Thanks a lot dear, stay blessed ❤ keep supporting & stay connected for more amazing contents👍😊 You can also check out our course for all Computer Science subjects, sharing the link below: www.knowledgegate.in/learn/Zero-to-Hero-in-Computer-Science
For complete Theory of Computation, check out this video:
th-cam.com/video/9kuynHcM3UA/w-d-xo.html
Sir, you are the best teacher a student can get.
Eagerly waiting for DBMS FURTHER TOPIC VIDEOS.
Don't stop the DBMS Series .
Please upload the remaining videos.
Thank you Asha..
Will upload them soon.. Keep following & working hard..
i realize it is kinda off topic but does anyone know of a good website to stream new movies online?
@Stefan Ronin i use Flixzone. Just google for it =)
@Stefan Ronin try Flixzone. You can find it on google :)
@Stefan Ronin I use FlixZone. You can find it on google :)
sir,
thank you so much. from beginning i suffer in TOC but now my all concepts clear and hope it will carry on.
you are really a best teacher in the world. thank you so much once again
sir, i send you a mail please give me some time and give me reply if its possible for you.
thank yo so much one again
Sir kya padhate ho aap ,
bas dil jeet lete hain aap har baar !
Your teaching style is awesome.
Thank you sir for uploading videos with awesome explanation....
I have watched all the videos from TOC playlist.......
👍🏻😊😊
You are welcome.. Keep following & working hard.. I will be uploading regularly..
After adding the trasition b on q1 and reach at q0 it is not only moving toward death state but also produce the ambiguity bcz there is already transition for b on q1
i study one day before exam and score 90% because of yu sir...Thanks a lot..
very very nice excellent sir hatsoff thankyou to make easy explanation video of the tough subject theory of computation
Bestest explanation👍💯
Sir temperory state q3* hoga apne q2 likh dia..😅😅 but i understand and thanks for providing this lecture these are very helpful for us..✌️
can we send input B to the dead state at final state q1?
Sir you are 😍 No one can beat you r teaching style! Loved it❤
Thank you so much dear, keep learning & following for more content👍
Great question but Very easily explained.
Thanks sir ji😆
Million dollar thanks ❤️❤️❤️
Most welcome dear 😍Keep learning & supporting ! Do visit our website www.knowledgegate.in for more amazing courses & contents 👍😊
...u r..best teacher...
Too easy way to teach... THNAQ SIR
Excellent explanation......Love from Pakistan
The best Explainer 😀😀
Sir please work on data structure videos your way of teaching is suburb . Your Student from Pakistan
Sir as ma "aa" b to a sakhata ha 'a' sa start or end ho raha ha
Can't we have b transition from q1 to q0 instead of taking another State?
🥲♾️💜💜💜
Are you graduate now sis? 🧡
No, it causes a valid string to be in dead state, hence unaccepted.
No . a(a+b)*a is the regular expression so
Any combination of a and b can come between a and a
Eg:- abbba should be accepted by the machine
its explained in the video, were u not watching 😅
sir,really you are very very good teacher.
VERY NICE EXPLANATION SIR
DFA " for all words that must start and end on a " ko hm 2 states mai b bna skty hn na?
well explained sir. bahut acha kaam kr rahe ho aap sir ,thanks you
Sir agar q0 se b de k q1 pe aye or q0 par b ka self loop lagaye to kya galat hoga??
Sir please make videos on what series of courses which are coming from ur side
Few videos are deleted sir, why so? just yesterday I was watching, but today they are not available. please make them available.
Which are those videos Arjoo? Let me know..
Q1 pe a,b dono self loop laga sakte hai
Sir can't we make self loop on q0 for b then we don't need extra state ..pls answer this sir
Sir agr end m b aya to Q3 se death state ki trf lekr jayege na isme?
very nice explanation sir,
definitely anyone can clear gate
Well explanation sir ✨😊
Thank you dear 😍 Keep learning & supporting ! Do visit our website www.knowledgegate.in for more amazing courses & contents 👍😊
Here in this DFA can't we have a self loop on final state for both values a and b instead of having an extra cost of additional state.
Then ab will be accepted..
Sir last state mein q2 pe self loop pe A bhi aa sakta hai na B ki jagah pe
7:40 self loop of b on initial state kar sakte hai na sir
Nhi kar sakte bhai abba kaise print hoga usme
sir a,a bhi to ho skta h string a ke baad a se strar
ting a se end?
Best explanation 🔥
Can we apply self loop of b & a in q1? .. I think that will also work
As q1 is final state it can accept a as starting and b as final on q1 and that will be wrong so we cannot do that..
Sir ye to AB ko bhi q2(right side wala) paas le jayega uska kya hoga???
sir kya aa v accept hoga ? ???
Sir isme aa nhi ho skta kya ??
sir ,2 final state bana kr nhi kar skte kya iss question ko.
you are great sir ;
thanks for this tutorial...
why "aa" string is not taken ???
It will accept.. You can check..
@@KNOWLEDGEGATE_kg can we solve using aa string? Will it be correct?
Best explanation
Sir aa is also possibe or not?
Sorry, agr q1 se b de k q0 pe aye or q0 pe b ka self loop lagaye to kya galat hoga?
qo pa b ka selfloop laga diya toh string condition ka voilation ho jyga
tab abba reject ho jaega jabki vo accept hona chahiye tha isliye bache yaad rakho us state par kabhi nai jaate jisse dead statee par jaate ho..
Nice explanation sir...
awesome sir!!
Thank you dear @Manish! ❤ Do like, subscribe & share the video, you can also visit our website www.knowledgegate.in for more amazing videos & contents👍😊
this example was awesome
Sir is mai kia 2 final state ly k kr skty hyn.?
Can anyone plz mention the video where he was explaining the design of DFA when a and b are NOT at start or end or something like that
Drop your query in our discussion forum t.me/KGgatefreeclasses, KG mentos will help you out !!
Dekha jaye to a strt bhi h n and a end bhi h sir to kya nhi ho skta sir
Thank you sir
Great!!
Thank you, keep learning & following😊
Sir how can we do if a is in between or how can we do aaa,abaa,...... because it terminate with 2nd a.
That is why we have additional state q3...(with self loop b)
If we want to check for aaa......ther is loop on q1......it will take as many a's you want it to......for abaa q0-q1-q3_q1...........the last state is just temporary only to aid these kinda problems
The problem will occur only when we counter b in the starting or at the last
Sir will aa be accepted ?
Sir, Can you plz upload videos on Software Engineering. Its a major subject when NET is considered.
Agr q1 state ke bad q2 state hamresa hi 'b' ata rhe kabhi a aaye hi na toh toh process ko dead state pe jana chahiye tha
Means agar string 'a' se start ho rhi ho aur 'b' pe khatam ho rhi ho toh dead state nhi banegi kya ??
Temporary state ka nature final nhi hai to dead hi consider krenge usey
Awesome 💞💞🌹🇮🇳🇮🇳🇮🇳
sir kya is language m doube a i.e. aa nahi aayga
Ayega
Thank You Sir
You're welcome dear. Do like, subscribe & share the video❤ Stay connected for more amazing upcoming contents👍😊
Can I make final state to q2?
Dear @Abdul, by making q2 as the final state, the machine will also accept 'ab' which we don't want.
Self referential note: this question is important
SIR PLZ UPLOAD CO PLAYLIST
On this language,can aa be not a string.??
it can be
Sir you defined q2 2 times
Thanks sir but also upload software engineering as net point of view thanks again sir
thank u so much sir
Mja a gya sir...
thank you
You're welcome, keep learning👍😊
Thnkkkk
Sir ke chran saprash.....kya knowledge h Sir
Thanks a lot dear, stay blessed ❤ keep supporting & stay connected for more amazing contents👍😊
You can also check out our course for all Computer Science subjects, sharing the link below:
www.knowledgegate.in/learn/Zero-to-Hero-in-Computer-Science
@@KNOWLEDGEGATE_kg Sir how can we do if a is in between or how can we do aaa,abaa,...... because it terminate with 2nd a.
AbbababA is not accepted why
bro it's accepted. Check the dfa once again.
Bro middle one is the final state plz recheck your solution
Dead state pe jaana dukh ki baat hai.....thanku
Thanks sir
You are welcome..
Kis kis ne notice Kiya ...muuli hogi 😃😃😃😃
arey bhai bhai bhai bhai
sir tussi great ho!