id like to know if there is a certain order for solving the unknown variables. Since if we could have started by solving Q before V @21:40 we could be using the assumed values of V2 instead of the new value of V2 obtained.
All steps (in detail) are explained in the following lectures: Newton-Raphson Method of Load Flow: th-cam.com/play/PLEVP-S4VFKO9HEb7Mozh_sEQzekft-DLn.html
I am a little confused on the part when you put values in the formulas of Vi^r and so on but still this video has helped me a lot in clearing the concept and the working of this method ...Thankyou so much Sir
Before solving the problem, first watch the following (theoretical parts) video lectures: Gauss-Seidel Method of Load Flow (In Hindi): th-cam.com/play/PLEVP-S4VFKO8MBMECe3UfdlIurue36pqa.html
Before solving the problem, you may watch the following lecture to understand the various steps: Gauss-Seidel Method of Load Flow (In Hindi): th-cam.com/play/PLEVP-S4VFKO8MBMECe3UfdlIurue36pqa.html
Yes, we need to check the Q-limits in each iteration. It will be treated as PQ bus in that particular iteration only (where it has violated Q-limits). For more details, you may watch following video lectures on Gauss-Seidel method of Load Flow: th-cam.com/video/cQXuQRvbZYw/w-d-xo.html th-cam.com/video/qxWeu7tUaqE/w-d-xo.html th-cam.com/video/HMuSkgtuFrc/w-d-xo.html th-cam.com/video/mmgdYwHVt1k/w-d-xo.html th-cam.com/video/KQBN9xVnzio/w-d-xo.html th-cam.com/video/eSBxPTldi0o/w-d-xo.html For these lectures in Hindi, you may watch th-cam.com/video/VJ-9-6bTUJ0/w-d-xo.html th-cam.com/video/6b87-cHemWY/w-d-xo.html
Sir in case of load bus the bus specifications Ie, p and Q values are in opposite signs then how to solve that problem sir... Hoping quick reply.. Having exam
Same rule will be applied. Before solving problems, you should watch the theoretical parts of this topic. If you wish, you may watch following lectures: Gauss-Seidel Method of Load Flow (In Hindi): th-cam.com/play/PLEVP-S4VFKO8MBMECe3UfdlIurue36pqa.html
Hello sir, I have a doubt... Suppose out of n buses (1- slack, m-PQ and n-m-1:PV) we run PF... Now if on one of the PV buses (lets say j between m+1 & n) the Q-limit violates, then we convert it to PQ bus... Now, do we keep it as same bus no. j in between m+1 and n or we club it with PQ buses and assign it bus no. m+1.... If we change that bus number, the Y-bus also changes
The bus no. of jth bus will still remain intact as j. Also, remember that we treat this jth bus as PQ bus in that particular iteration only (the iteration in which Q-limit is violated). In next iteration, this jth bus is treated as PV bus as usual unless it violates Q-limits again.
@@DrAfrozAlam Sir, then till m we know P&Q and V and ∆ are unknown... After m, we write in terms of ∆ since thry are PV till bus no. j, for bus j we write again as PQ bus and after j+1 we write all other as PV? I am correct ?
Yes, but in that particular iteration only. For detailed explanations, you may watch following video lectures on Gauss-Seidel method of Load Flow: th-cam.com/video/cQXuQRvbZYw/w-d-xo.html th-cam.com/video/qxWeu7tUaqE/w-d-xo.html th-cam.com/video/HMuSkgtuFrc/w-d-xo.html th-cam.com/video/mmgdYwHVt1k/w-d-xo.html th-cam.com/video/KQBN9xVnzio/w-d-xo.html th-cam.com/video/eSBxPTldi0o/w-d-xo.html For these lectures in Hindi, you may watch th-cam.com/video/VJ-9-6bTUJ0/w-d-xo.html th-cam.com/video/6b87-cHemWY/w-d-xo.html
dr. l was watching ur interesting tutorial but l have one question related to the given p and q values. are they specified values that means Pg-Pl and Qg-Ql?
sir can u tell me how to find active n reactive loss in TL. according to book first it calculate current in each TL then useses i^2 R and i^2 X for active n reactive power for each TL and add it for overall. isn't there any short method? What if l subtract total active power generate in slack and generator bus to total active damand by all connected loads .pls help
Download lecture notes (pdf) using the following link:
drive.google.com/file/d/10_A3zXCcfjhpf32bLFA2vzmXjzmhV9Xf/view?usp=sharing
Thank you sir. I understand more from your lectures than in class
Receive good energy wherever you are Dr Afroz ! You have help me understand load flow very clearly.
id like to know if there is a certain order for solving the unknown variables.
Since if we could have started by solving Q before V @21:40 we could be using the assumed values of V2 instead of the new value of V2 obtained.
Thank you Keylel
All steps (in detail) are explained in the following lectures:
Newton-Raphson Method of Load Flow: th-cam.com/play/PLEVP-S4VFKO9HEb7Mozh_sEQzekft-DLn.html
Really clear. Now I am understanding it much better. Thank You Sir.
It's my pleasure
Sir thank you so much many of my doubts are cleared from your videos . Load flow & fault analysis
Your method of teaching is very good.
Love from Pakistan
Just loving your channel ♥️ never thought power system can be that much easy ,
Thank you very much sir
Thank you so much Shivam for the appreciation 💗
You just made it easier
Thanks
nice one... and this auto focus is killing me xD
Very much helpful sir, zazakallah
Nice explanation sir...
I am a little confused on the part when you put values in the formulas of Vi^r and so on but still this video has helped me a lot in clearing the concept and the working of this method ...Thankyou so much Sir
Before solving the problem, first watch the following (theoretical parts) video lectures:
Gauss-Seidel Method of Load Flow (In Hindi): th-cam.com/play/PLEVP-S4VFKO8MBMECe3UfdlIurue36pqa.html
For lectures in English, you may watch the following playlist:
Power System Analysis: th-cam.com/play/PLEVP-S4VFKO9skYbAegYfSQNXNJajL3oD.html
Very good explanation!
Thank you
This so helpful thank you sir
Great sir ji
Thank you so much sir!
super lecture sir
Sir THANKS a lot, You helped me a lot with this video, I'm going to SUBSCRIBE your channel sir ❤❤❤
Thank u sooooooo 💖 muchhhhh sir
Thank you very Dr
Thanks អរគុណ❤
Thank you sir🙏
Most welcome Mandeep
Thank u Uncle
You're correct
Thank you
Sir if q limit violated so while calculating v3(1) ,should I take v3(0) as 1.04 or 1 as it has loosed its pv nature??
Before solving the problem, you may watch the following lecture to understand the various steps:
Gauss-Seidel Method of Load Flow (In Hindi): th-cam.com/play/PLEVP-S4VFKO8MBMECe3UfdlIurue36pqa.html
very nice explanation ☺️☺️
🇳🇵🇳🇵🇳🇵🇳🇵🇳🇵🇳🇵
Thank you Tirth Joshi. Are you from Nepal 🇳🇵?
@@DrAfrozAlam yes sir
Another doubt is that, suppose we have a network with PQ and PV buses and we have Q limits e.g. 1.0
Yes, we need to check the Q-limits in each iteration. It will be treated as PQ bus in that particular iteration only (where it has violated Q-limits). For more details, you may watch following video lectures on Gauss-Seidel method of Load Flow:
th-cam.com/video/cQXuQRvbZYw/w-d-xo.html
th-cam.com/video/qxWeu7tUaqE/w-d-xo.html
th-cam.com/video/HMuSkgtuFrc/w-d-xo.html
th-cam.com/video/mmgdYwHVt1k/w-d-xo.html
th-cam.com/video/KQBN9xVnzio/w-d-xo.html
th-cam.com/video/eSBxPTldi0o/w-d-xo.html
For these lectures in Hindi, you may watch
th-cam.com/video/VJ-9-6bTUJ0/w-d-xo.html
th-cam.com/video/6b87-cHemWY/w-d-xo.html
Sir in case of load bus the bus specifications Ie, p and Q values are in opposite signs then how to solve that problem sir... Hoping quick reply.. Having exam
P and Q will be substituted with their sign (whether signs are same or opposite)
@@DrAfrozAlam sir if 3 buses are there... P and Q of 3 buses are given different signs sir.. For load bus how to solve it sir
Same rule will be applied. Before solving problems, you should watch the theoretical parts of this topic. If you wish, you may watch following lectures:
Gauss-Seidel Method of Load Flow (In Hindi): th-cam.com/play/PLEVP-S4VFKO8MBMECe3UfdlIurue36pqa.html
Thank you. Please use MATLAB for solving.
Hello sir,
I have a doubt... Suppose out of n buses (1- slack, m-PQ and n-m-1:PV) we run PF... Now if on one of the PV buses (lets say j between m+1 & n) the Q-limit violates, then we convert it to PQ bus... Now, do we keep it as same bus no. j in between m+1 and n or we club it with PQ buses and assign it bus no. m+1.... If we change that bus number, the Y-bus also changes
The bus no. of jth bus will still remain intact as j. Also, remember that we treat this jth bus as PQ bus in that particular iteration only (the iteration in which Q-limit is violated). In next iteration, this jth bus is treated as PV bus as usual unless it violates Q-limits again.
@@DrAfrozAlam Sir, then till m we know P&Q and V and ∆ are unknown... After m, we write in terms of ∆ since thry are PV till bus no. j, for bus j we write again as PQ bus and after j+1 we write all other as PV? I am correct ?
Yes, but in that particular iteration only. For detailed explanations, you may watch following video lectures on Gauss-Seidel method of Load Flow:
th-cam.com/video/cQXuQRvbZYw/w-d-xo.html
th-cam.com/video/qxWeu7tUaqE/w-d-xo.html
th-cam.com/video/HMuSkgtuFrc/w-d-xo.html
th-cam.com/video/mmgdYwHVt1k/w-d-xo.html
th-cam.com/video/KQBN9xVnzio/w-d-xo.html
th-cam.com/video/eSBxPTldi0o/w-d-xo.html
For these lectures in Hindi, you may watch
th-cam.com/video/VJ-9-6bTUJ0/w-d-xo.html
th-cam.com/video/6b87-cHemWY/w-d-xo.html
@@DrAfrozAlam thank you sir
شكرااا
Sir how to find Y12 value in Casio
dr. l was watching ur interesting tutorial but l have one question related to the given p and q values. are they specified values that means Pg-Pl and Qg-Ql?
Yes, Pi=PGi- PLi and Qi=QGi-QLi. These were already discussed in the theoretical parts of this lecture series.
@@DrAfrozAlam okay 10q dr
thank's sir
Most welcome
sir can u tell me how to find active n reactive loss in TL. according to book first it calculate current in each TL then useses i^2 R and i^2 X for active n reactive power for each TL and add it for overall. isn't there any short method? What if l subtract total active power generate in slack and generator bus to total active damand by all connected loads .pls help
Yes, you can but take negative of that i.e. total generation minus total load.
Which college??
www.amu.ac.in/dshowfacultydata.jsp?did=31&eid=10062189
Where is delta 2 value?
I get Y12 equal to 53.8516anlgel -1.19028 but sir u got -68....
Why so sir ?
Y12=-y12=-10+j20=22.3606angle116.5651. This has already been evaluated at time stamp 7:20
@@DrAfrozAlam sir ,,Y12, on calculting On calculator ,the value comes different ...my question is that I got Y12 angle different and in minus sign
❤
Hello Sir, i have came across one power flow problem want your advise . Could you please share your email please.
alam7624@gmail.com
- Im mean what
'Im' means imaginary part
and the real part can say P?