mera kal paper hai ior muhhe waqai me bohat faidah howa inki video dekh kar, me absent tha class me bohat pehle jab yeh mere sir ne parhaya tha ior class fellows ka sab ko pata hai ke university me stress hi dete hain magar fi ally mujhr pira samgh agaya hai yeh
Hello Sir... ek baat samjh nhi aa rhi Jaise AB line ka F.B. liya orr B.B. lia AB line ka jb bearing mines krte h to AB ka F.B. orr DA ka B.B. kyu nhi mines krege Table me AB ke samne vale se hi bearing kyu mines krte h
Mam my question In the WCB 180degree be added you. but in the paper problem to solve the way of quadrantel bearing and all values given in the quadrantel bearing then what should be added on 180 degree
(i) Fore bearing of AB = 20°30' (iii) Fore bearing of CD = 210°45' (iv) Fore bearing of EF = N 30°20' W (v) Fore bearing of DE = $ 20°30' E Find their back bearings with sketches Help me
if no line has the difference of 180 then watch this:- th-cam.com/video/7oywtV_h42Q/w-d-xo.html
Sir diagram bhi banaya karo... Baki yr video is supportive...
Sir if the last line will be free from Attraction then
@@priyasonar6670 phir starting se start krenge
Thanks a lot it helped me lot during exam. Tomorrow is my exam I will do it well because of u thanks again 😊😊😊
Yaa
Same
I watched a lot of videos on TH-cam,but your method is the very simplest.I have understood in one tima.THANKS FOR VIDIO
mera kal paper hai ior muhhe waqai me bohat faidah howa inki video dekh kar, me absent tha class me bohat pehle jab yeh mere sir ne parhaya tha ior class fellows ka sab ko pata hai ke university me stress hi dete hain magar fi ally mujhr pira samgh agaya hai yeh
sir bas ap dua kijiye ga kal ke paper ke liye kal mera Surveying ka hai paper.
Very helpful thanku so much
It is first time.. the way u solve the numerical easily way.. otherwise I'll even not trying to do numerical bcz I don't understand numerical problem.
Thanks sir...It's help me to understand to solve this type of numerical..
Thanks once again sir😍
Love from Pakistan dude
Well explained 😉
I am from pakistan ,Its help m in my exams numericals , thanks alot
Finally aab samaj me aaya !
TQ 🙂
Bhai Kya video h ek bar me samajh. Aap gya nic video ab tak ki
Thank you bro for teaching in easy way! Awesome job!
Thank you very much
Thankyou I was doing this problem more than 2hrs😁😁
You are the best surveyer sir thank you
May God bless you for making a great useful video thank you so much ...
Thanks dude. Was clear and easy to understand.
thank you so much sir for the making this video which supported us thank you so much.
Very Well Explained Thank you!!
Bro . Tq because of you i had written this problem ...
Very nice video !!!! Its very helpful for me. Thanks again sir
It is applicable for closed transverse
thnq so much sir... I prepared for compass survey for tomorrow exam from this video.
Bhot sahi smjhaya bhai
Appreciate that 🖒
Khatarnak sir ji
Thanku so much 😊 love you ❣️. Easy method to solve local attraction question, you can do much better continue sir g 🙂🙂
U explained this very well😀,, thank you sooo much and make more videos on survey problems
I like it and understand carefull
Thanks bro I have solve this problem from your help thanks a lot...
Very useful for exam preparation thanks sir 🤗
Thank you so much sir it really helped
Thanks brother... Excellent teaching 🙏🙌
bohat ache se smjhaya ...thanks
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for example FB =(S45' 30'E)(S60' 00'E)(N03' 20'E)(S85' 00'W)
BB=(N45' 30'W)(N60' 40'W)(S05' 30'W)(N83' 30'E)
Thank you it really helped me
Thanks sir ❤😘u bhut bhut sukriya eame mere ko prblm tha vo sol ho gya
Thanks alot sir...may God bless you...
Thank you very much sir,👍👍👍👍
Awesome bro. Easy learning. Pls add some more videos in different problems
Thanks sir this video was really helpful for me 🤗🤗 TQ so much
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So well explained ..Thanks soo much☺️
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Fore bearing not front bearing 👍
Thank you very much bhai
Please make an video on second technique for correction
Yes sure soon
Thank you bro
Have more confidence in your speech
You will nail it! 👍
Definitely 🙏👍
Tnku so much bro good job 👍 very helpful for me
Plz upload on Reciprocal level, staff reading, volume of earth work
Thank you so much sir.......❣️❣️❣️
Explanation by u sir is just osw ....🤗
Hello Sir...
ek baat samjh nhi aa rhi
Jaise AB line ka F.B. liya orr B.B. lia
AB line ka jb bearing mines krte h to AB ka F.B. orr DA ka B.B. kyu nhi mines krege
Table me AB ke samne vale se hi bearing kyu mines krte h
Thank u sir it helped me a lot 👍
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Sure sir I will subscribe 😊
Very nice explanation 👌 👍
Many many thanks sir ji .nice 😘 concept with 💯%
thank you , was really helpful.
Khup chan banavli ahe video...
bhai video was very good...
thank you❤.....
lekin line me ni station me local attraction hota hai....
Thank u bro ....for explaining..
Thanku sir for explaining in such a easy way😇
thankyou so much sir...
Samaj Aagaya Thanks Bro 😊
Thanks bhai
Nice sir I'm understand tq u so much
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Bhai nervous kyu ho rhe ho pdhate hue 😂😂
All readings are same in my problem but given backbearing of AB is 39degree 30 minutes
bhai i love you..... you solve a big problem.
thanku bhAi bahut usefull Raha
thnku bro for this knownladge
What if FB-BB is not 180 of any line but BB-FB is 180 then what we have to do ? Please reply fast
tq bhai😊
THANK U SOO MUCH SIR
Thanks😊
Good job....acha hai....bt required some more improove. Well done.
Nice video ...🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳
Nice brother!
Sir isme kisimebi 180 nai he to k karna partahe
Do u get answer of this question ? Then please write here some hint so i can also solve it
Thanks a lot bhai
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Mam my question In the WCB 180degree be added you. but in the paper problem to solve the way of quadrantel bearing and all values given in the quadrantel bearing then what should be added on 180 degree
Sir
Sir u told that previous vedio in QB the same at 2parts but here is not
1st part is of Whole circle Bearing where there will be difference of 180° and 2nd part is when difference is not Equal to 180° that is QB
@@GaneshShegar but sir u told that in QB FB-BB= 0 That is free From local attraction is that always right???
Nice and thanks,,👍🏼👍🏼
thanks bro
Video length thodi short kar bhai.....
Thanx alot bhai
what about when no line has a difference of 180?
Thankyou so much sir 🙏
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Thanks u so much......
Thank you
thank u so much bro
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Vdo acha...he but sound thoda jyada chahia...plz sir sound thoda jyada kare
Sir plz video on when difference is not equal to 180
Exam hai
Link given in Description Box
Or click this :- th-cam.com/video/7rwHu_fUl6M/w-d-xo.html
Thank you sir
Explain clearly
If in the given question there is no line which is free from local attraction then how we can solve?
Check link given in Description Box if no line has 180° difference
Great
any pdf of your all tutorial..I.am from.Bangladesh
(i) Fore bearing of AB = 20°30'
(iii) Fore bearing of CD = 210°45'
(iv) Fore bearing of EF = N 30°20' W
(v) Fore bearing of DE = $ 20°30' E
Find their back bearings with sketches
Help me
Just add 180 on each one
Thankx brother
Very nice bhai
You are awsm bro ty 😊😊
What if the declination is 1°30' west??
please can i get the complete project for my Assignment
1:00 Plus nahi Minus karenge to 😊