Inertial and Non-Inertial Frames - The Equivalence Principle

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  • เผยแพร่เมื่อ 4 ม.ค. 2025

ความคิดเห็น • 14

  • @hershyfishman2929
    @hershyfishman2929 11 หลายเดือนก่อน +3

    8:53 For anyone not familiar with the term gradient as used in this context, it means the slope of the graph: T^2/l

  • @perdehurcu
    @perdehurcu 3 หลายเดือนก่อน

    Selamlar. Hocam Muhteşem dersler anlatmışsınız. Çok değerli bilgiler vermişsiniz. Teşekkürler.

  • @costaspournaras7821
    @costaspournaras7821 2 หลายเดือนก่อน

    Any recommendations for books?

  • @lowersaxon
    @lowersaxon ปีที่แล้ว

    Very good didactics.

  • @danjonsson9362
    @danjonsson9362 10 หลายเดือนก่อน

    This is just brilliant. Thanks!!

  • @drkpsatheesh
    @drkpsatheesh 7 วันที่ผ่านมา

    Better to reserve the term reference for coordinate system +time

  • @Kijozaneko
    @Kijozaneko ปีที่แล้ว

    34:37 I think you should take a closer look at this place. If it is a light clock, with the light source on one side of the spaceship is a lamp and when the light is on, the light will radiate throughout space in a spherical shape. Therefore, on the other side of the spaceship, if there is a sensor, it will definitely receive a signal and tick. In this case, the person in the red frame will see the light travel with the speed C. The person on the spaceship will see the light traveling from the side of the ship to the other at the speed C.(Delta t')/(Delta t') = C (Because of time dilation by velocity). Thus, both frames of reference see light traveling with speed C.
    But in the case of the ship replacing the light source with a laser, the result will be different because the laser beam has a direction, not a spherical propagation. If the blue spaceship is moving with velocity v, the laser beam will deflect downwards on the other side of the ship. Therefore, with this deflection angle, it is clear that the people on the spaceship will know how fast they are going.
    I have such an opinion.

    • @Kijozaneko
      @Kijozaneko ปีที่แล้ว

      Actually, I'm also concerned that even when the light source emits a sphere of light, the clock sensor will hardly work as ideal because of the probabilities in quantum mechanics.

  • @Kijozaneko
    @Kijozaneko ปีที่แล้ว

    36:56 Of course, the people on the spaceship didn't know that the light was traveling diagonally (in the case where the light source was not a laser). Although light must travel diagonally, due to time dilation, the ratio of distance divided by time on the spacecraft is still C.

  • @Kijozaneko
    @Kijozaneko ปีที่แล้ว

    38:40 In my opinion (geometrically provable of course), if the light source were a laser, when the spaceship traveled at a constant velocity, the path of the laser would be linear (which is diagonal, deviating downwards on the right side). across). In the case of an accelerating spaceship, the path of the laser beam will be a curve.

  • @babeksaber2702
    @babeksaber2702 4 หลายเดือนก่อน

    Brilliant thx

  • @kennethessenwanger268
    @kennethessenwanger268 ปีที่แล้ว

    Analogy of “Gravitational Flux” creates a paradox since the source was not well defined. Rho was identified as the source then rho on the line of flux was paradoxically equal to 0. Paradox in the context of an energy density Rho that is approaching a constant for flat universe and exponentially expansion, H = constant. Hence, I tend to avoid flux analogy in my theory, and derived equations.

  • @lowersaxon
    @lowersaxon ปีที่แล้ว

    My answer to floating in outer space and free falling in a grav. field being the same is: wait a second!

  • @benquinneyiii7941
    @benquinneyiii7941 7 หลายเดือนก่อน

    You won’t feel weightless for long