You’re actually brilliant. You know enough about every subject to teach them all brilliantly and meticulously down to the detail. A true renaissance man.
I think it was awesome that you took the time to integrate out the proof instead of providing the solution. Really helped me conceptualize everything better than my professors teachings
@@domantas973 did great! managed to get an A on Physics II, i also happened to transfer universities. used to do software engineering in my home country now i do mechatronics engineering abroad. Thank you for checking up
@@shalinyvaleny2091 learning how the formulas work and how to use them in the situations that they should be applied in is key, also practice makes perfect! good luck in your exams! wish you the best of luck
I'm about to give this topic up, then I searched. In my mind, "I'm sure he has a video for this. I'm sure of it." Then I saw your vid. So thank you very much! Great help as alwaysss.
Same with me lol I started crying lol cuz I can't understand the same topic from my textbook* but he made me understand very easily *edited some spelling
Great video you didn't skip any steps and explained it all ty I was stuck on integration for ever until your video showed me there was trig sub in this problem
Good on you for showing how to solve the integral. My physics professors either said "look it up in an integral table" or they solved it in their head...
At 7:08 how he got the equation for dEx was by understanding that x/r is proportional to dEx/ dE. Therefor: dEx/dE = x/r dEx/dE = cos(theta) dEx = dE (cos(theta))
ik this comment is 3 years old and ur probably already an engineer that does this for breakfast, but in the video he explains how you can find Ex and Ey for a point not in the center using integration and then you can take the vector sum to find the field intensity vector
Am I the only one with a crazy enough prof that wants the proof of the final electric field problem on the answer sheet? why do I even need to memorise proofs in a physics class?
Very nice, however I am struggling with the situation where the point P in not on the x axis. This means that the charged rod is not centered under P. The y components of E do not cancel and the x components are not symmetrical either. This is a much more difficult calculation and one that I have not seen anyone do. Could you extend this lesson to the more general case of an electric field at some point over any place of a charged line?
Hey can you also take up the case where the point of observation (that is where we are supposed to find out the electric field) is not symmetrically placed , like what happens when the Y-component does not cancel out???
I believe that your comment (more of a question I believe) is very valid. To the best of understanding, the method shown only works for finding the electric field from a distance x from the center of the line charge. The y-components of the electric field for other points do not cancel as you pointed out. More complex integration is needed. In the numerical example near the end of the video, it asks specifically the electric field 80 cm away from the center of the rod.
at the 9 minute mark, i stopped and realized that this WHOLE half hour video was just to explain ONE single problem and ONE fucking crazy ass integral smgdh
quick question, at 16:52 when he sub dy and y values in integral, shouldn't his limits also change? why did he not write the limits for integral, x integrate cos(theta) d(theta)
what if the point upon which we want to find the electric field (point b) is not directly in front of the center of the finite rod, but is in front of the start of the rod. How do we find the electric field it there?
in 13:30, the derivative of y on the left hand side should be dy/dt but we just wrote it as the differential of y, dy. And then replaced it aswell in the integration. Am i missing something?
Hi, i dont understand why we take derivative? How does it help? And are calculating the Force the whole rod is pushing to p، ، it just a little part of it?
when sheet of charge is finite along z-direction from -z1 to +z1 and infinite along y-direction.find electric field intensity when we take point on x-axis??
Please factorizing x out of the integral was suppose to be 1/x not x multiplied by the whole integral please I don't why you multiplied x to the whole integration to get x cos it would been 1/x cos please explain
Physics Video Lessons: www.video-tutor.net/physics.html
Every engineering student is being taught singlehandedly by this legend.
true story
You’re actually brilliant. You know enough about every subject to teach them all brilliantly and meticulously down to the detail. A true renaissance man.
I don't understand how a single man can acquire this level of knowledge
@@Urbanstrangler He was only meant to learn Organic Chemistry but he went further
@@Urbanstrangler who sad he is alone
My wrap of 2020 on youtube is ready:
50+ hours watching The Organic Chemistry Tutor
You are amazing and I appreciate your channel!
I appreciate your passion for learning but if its for physics than i can't say much, you are one of a kind
Totally commendable
I think it was awesome that you took the time to integrate out the proof instead of providing the solution. Really helped me conceptualize everything better than my professors teachings
school is awful. Only thing I'm doing is paying those bastards for a piece of paper.
@@copperwater8456 school is good for you to have a syllibus or can see better path or target, but not a good place to study / learn
and just like that, enrolling physics 2 this semester in uni isn't regrettable anymore
Yess i took this lecture and i was lost
How did the exams go?
@@domantas973 did great! managed to get an A on Physics II, i also happened to transfer universities. used to do software engineering in my home country now i do mechatronics engineering abroad. Thank you for checking up
@@kasiorap how did u get an A 😩
@@shalinyvaleny2091 learning how the formulas work and how to use them in the situations that they should be applied in is key, also practice makes perfect! good luck in your exams! wish you the best of luck
the point that was not clear to the whole class of 96 students
THANK YOU SIR
EXACTLY THE POINT I WAS LOOKING FOR
RESPECT RESPECT ...............
I'm about to give this topic up, then I searched. In my mind, "I'm sure he has a video for this. I'm sure of it." Then I saw your vid. So thank you very much! Great help as alwaysss.
Same with me lol
I started crying lol cuz I can't understand the same topic from my textbook* but he made me understand very easily
*edited some spelling
Love understand more in a single day than an entire year of university lectures.
Great video you didn't skip any steps and explained it all ty I was stuck on integration for ever until your video showed me there was trig sub in this problem
Good on you for showing how to solve the integral. My physics professors either said "look it up in an integral table" or they solved it in their head...
It is really helpful. Especially for our international student. It is very clear and step by step! thank you very much!
This guy is single handedly carrying my grade in 3 of my classes this semester
i like the irony of just being called the organic chemistry tutor when he literally tutors EVERYTHING
at 15:39 when you moved the x out in front of the integral, shouldn't it be a 1/x since it was in the denominator?
yeah. i noted the same
He corrected it after that already
I'm confused about this part too😂
Because it is treated as a constant and we are integrating with respect to theta that,s why he moved it out as a constant
Thank you for being able to clearly teach this in English!
I don't know how to thank you enough sir ❤
You've helped me so much
This channel is saving my life 😢❤️
at 15:36 should you not put 1/x to the front instead of x?
Now this is difficult, but giving up is not an option ,especially if you have JG as your tutor.
At 7:08 how he got the equation for dEx was by understanding that x/r is proportional to dEx/ dE. Therefor:
dEx/dE = x/r
dEx/dE = cos(theta)
dEx = dE (cos(theta))
The world's best teacher thanks
thank you man - U pinned what i was looking for :)
Thank God, you are here sir ❤
Who says physics is still difficult with all this explanation?❤
thanks a lot , its so helpful
god bless you
Yo man, thanks so much for this in depth explanation. Really helped my understanding.
Thank you very match
I benefeted more and
May allah bless you
Thanks brother I used the integral and now derived it for a wire not same length on both the side ....
This man could be the best damn professor of all time
Awesome teacher, you've helped us so much.
I realised you are on earth at 35:01
The dog.......
Thanks a lot , it's very important chapter and not everyone can explain it, it's challenging.
I’m so dumb...who the hell thought integration is a good idea
hahahahhahahah LOL!
It is not that you are lunatic or dumb whatever; it is that you are heedless and reckless about why things operate the way they do. 😊
It's simple
@@mohamadsherif701 yet in calculus class, I got 45 out of 100!
Simple indeed!!
so good of an idea they thought it would be good to teach everyone else
God bless you for this explanation
Owsum teaching style so much helpfull
this is really helpful, thank you!
This is great! Could you please do one for a point that's not at the center?
That would be stupidly difficult homie leave that to the computers to compute
ik this comment is 3 years old and ur probably already an engineer that does this for breakfast, but in the video he explains how you can find Ex and Ey for a point not in the center using integration and then you can take the vector sum to find the field intensity vector
at 15:45 wouldn't it be 1/x times the integral and not x times the integral?
Kyungseo Moon replied to Michael Adjei's comment below; he corrects it at 17:45. It is 1/x
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uarv ual an ,# @
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@@angelicasysnila5476 THATS when She said act ve
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dear brother thank you very much for the work you have done to explain to us clearly j aime tes video
1000th like from me
very important formula to calculate electric field on a distance to calculate electromagnetic wave which is an antenna communication
i like this explanation especially on integration part
I know nowt so found this very informative, many thanks.
Thank you so much!
Am I the only one with a crazy enough prof that wants the proof of the final electric field problem on the answer sheet? why do I even need to memorise proofs in a physics class?
Dude. Thanks.
your the best
Very nice, however I am struggling with the situation where the point P in not on the x axis. This means that the charged rod is not centered under P. The y components of E do not cancel and the x components are not symmetrical either. This is a much more difficult calculation and one that I have not seen anyone do. Could you extend this lesson to the more general case of an electric field at some point over any place of a charged line?
My professor never mentioned that point P next to the the middle of the line, so It was hard for me to get why Ey is 0
The video is great but, if you imagine E in y component is 0 only in case of equatorial line
Hey can you also take up the case where the point of observation (that is where we are supposed to find out the electric field) is not symmetrically placed , like what happens when the Y-component does not cancel out???
I believe that your comment (more of a question I believe) is very valid. To the best of understanding, the method shown only works for finding the electric field from a distance x from the center of the line charge. The y-components of the electric field for other points do not cancel as you pointed out. More complex integration is needed. In the numerical example near the end of the video, it asks specifically the electric field 80 cm away from the center of the rod.
this is really awesome
15:38 shouldn't it be 1/x in front of the integration symbol, not x?
Quick question, at 21:06 , why is 2 in front of k? Isn’t it supposed to be k times 2a(lambda)? Or did I miss something?
15:43 I think you made a mistake, it's supposed to be 1/x , not x
at the 9 minute mark, i stopped and realized that this WHOLE half hour video was just to explain ONE single problem and ONE fucking crazy ass integral smgdh
Thanks a lot mr!
Thank you once again.
THANK YOU
In the final integral (19:00) it should actually be x^2 on the bottom
(15:42) There is a mistake when solving for the integration..... you can't take out x but have to take out 1/x
yes and he fixed the mistake in 17:44
quick question, at 16:52 when he sub dy and y values in integral, shouldn't his limits also change? why did he not write the limits for integral, x integrate cos(theta) d(theta)
I'm probably too late but his original limits were in terms of y, so no they do not need to change
@@Tommyometer thanks hahaha. i took that mod 2 years ago.
what if the point upon which we want to find the electric field (point b) is not directly in front of the center of the finite rod, but is in front of the start of the rod. How do we find the electric field it there?
You are awesome. Thanks!
now do one with point P at the end and above some y distance of the rod(which lies on x axis)
thank you so much bro
Thanks a lot.
It really helped me to understand the topic :)
Couldn't you place a gouse shape around the rod and use gouse law instead? Like a cylinder for example?
Yes that would work
It's gauss's law
Thank you 😊🤲🏽
Can you make for us some videos related to Geometrical Optics Please ^^
Here you go:
th-cam.com/video/vkNF8tb3Guc/w-d-xo.html
th-cam.com/video/VKMswYSiyko/w-d-xo.html
The Organic Chemistry Tutor thank you so much man you're the best
tks very much
Do you have a video of distribution of charges: electric field and electric potential?
I had a similar question but the line of charge was a dipole, how would i got about solving?
physics vol 2 halliday resnick krane, that book right? phuck it big time xd
@@mentor1324 haha straight up
What if the rod is on the x axis? Would you have to use sin = 2a/r?
Exam saver.
thanks king
in 13:30, the derivative of y on the left hand side should be dy/dt but we just wrote it as the differential of y, dy. And then replaced it aswell in the integration. Am i missing something?
pretty sure it's dy = xsec^2(θ) dθ (with respect to θ) , not just dy.
thankyou so much
17:35 note this part
Hi, i dont understand why we take derivative? How does it help?
And are calculating the Force the whole rod is pushing to p، ، it just a little part of it?
well explained
is this video in a playlist??
When he solved the definite integral, wasn’t he supposed to also change the limits of the integral?
no cause he went from terms of x/y to terms of u and back to terms of x/y so you don't need to. If you keep it in terms of u then yes
when sheet of charge is finite along z-direction from -z1 to +z1 and infinite along y-direction.find electric field intensity when we take point on x-axis??
Please factorizing x out of the integral was suppose to be 1/x not x multiplied by the whole integral please I don't why you multiplied x to the whole integration to get x cos it would been 1/x cos please explain
I guess he corrected x cos to 1/x (cos) at 17:45, he made a mistake
@@kyungseomoon6538 that's right, thank you
Thank you sir...
Is the linear charge density symbol the same as that of lambda?
I think you got your Q wrong in the last problem. Off by a magnitude of power. I got 1.26E(-8)
Damn that integration was the one of the hardest so far or I forgot idk
Thank you!!!!!!!!!
ps: this is the 100th comment.
Lord bless this man!! omg
These topics are starting to get complex
You're not going to need to do this in class he's just showing the derivation.
Amazing*****
Gagandeep Kour yss
Can't this be simplified by using a cylinder as A, and using EA=q/epsilon(0)?
I think so but you are required to learn the prehistoric method by teachers.
Yeah a gaussian cylinder would be way easier, but most professors teach this before getting into Gaussian stuff
28:22
Review of lesson
thanks buddy
thanks!!!!
Thank you very much! :)
may allah bless your mind
sec= 1/ cos ?
Yep.... Reciprocal of cosine is secant or vice versa