Thank you so much...... Please share with others... Keep Supporting Please subscribe my channel... Please follow my blog: www.chiragbhalodia.com/2021/10/hill-cipher.html Full course of Network Security: www.chiragbhalodia.com/p/network-security.html Full course of Computer Network: www.chiragbhalodia.com/p/computer-network.html
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Thanks for the explanation. I have a question, what if it is given that A does not start with 0 but any random number like 17? Do we still do mod 26 and add 17 to the final answer to find the corresponding alphabet?
You are welcome.... Please share with others and subscribe my channel... Follow my blog: www.chiragbhalodia.com/2021/10/hill-cipher.html You should assign any number to any character (does not repeat number)...Process of encryption and decryption will be same....but you must check that table of A...Z (assigned number) is same during encryption and decryption....It should not be changed...
You have to given alphabets put in a 3x3 matrix and put a value infornt of character. Please share with others... Please subscribe my channel... Please follow my blog: chiragbhalodia.com
Encyption is easy as per video.... but I cannot make a video of decryption because it takes much time in calculation due to inverse matrix calculation.
Fow which exercise 1 or 2????? By the way your answer is wrong for both exercises... Try again tell me in comment. If again wrong I will give you the final answer with solution.
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bro thanks so much for making a tutorial that is clear with a good example
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from kurdistan regoin in iraq🇮🇶 seen vidoe very good thnks you❤
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Informative video 👍
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Best explained sir
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Thank you so much sir 🙏❤
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almost this is a great task but if possible you may explain this for us the transposition techniques with examples
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understand able👍
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thanks sir, the cipher of 2*2 matrix of SUNDAY IS=SEHWUS and 3*3 MATRIX IS = ECIEFV
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SEJZUS
true
Thanks for the explanation. I have a question, what if it is given that A does not start with 0 but any random number like 17? Do we still do mod 26 and add 17 to the final answer to find the corresponding alphabet?
You are welcome.... Please share with others and subscribe my channel...
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You should assign any number to any character (does not repeat number)...Process of encryption and decryption will be same....but you must check that table of A...Z (assigned number) is same during encryption and decryption....It should not be changed...
@@ChiragBhalodia Thanks for the reply sir 👍
You are welcome
Are the answers SEJZUS for 1 and FEMEFV for 2?
Yes....Your answer is absolutely right....
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Hey what to do if there's whitespaces in the plain text?
If there is white space in plain text, you can cosider the value of white space and then you can calculate....
how can we encrypt if the key of hill cipher is not a square matrix like plaintext="alphabets" and key="cryptography"
You have to given alphabets put in a 3x3 matrix and put a value infornt of character.
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SEJZUS right?
Correct....!!! Also try 2nd Example...
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what if the plain text is 5 letters? (in 2x2 matrix)
You can add letter "Z" to make a pair with last character...
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@@ChiragBhalodia what if 7letters and given matrix is 3x3 ??? Pls reply sir
You can add ZZ as last two characters...
please share the PPT Slide link also
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Plain text : pay
3*3 encryption and decryption value answer video potunga sir
Please
17 17 5
21 18 21
2 2 19
Intha value ku video potunga sir
Encyption is easy as per video.... but I cannot make a video of decryption because it takes much time in calculation due to inverse matrix calculation.
Oke
Thanx
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Hii sir
One help
nice information...
Let's visit & support each other .. thank you
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IS THE ANSWER SEHWXW
Fow which exercise 1 or 2????? By the way your answer is wrong for both exercises... Try again tell me in comment. If again wrong I will give you the final answer with solution.
It’s SEJZUS for exercise 1 and FEMEFV for exercise 2
Yes....Your answer is absolutely right....
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