Mistakes in last bouned variation implies monotonicity Monotonic + bdd is b.v. but ek nbhm k question main closed interval per monotonic diya hua h how it implies that function is of b.v.
at 49:41 function is not continuous only at 1 . Therefore discontinuity at only finite number of points this implies f is riemann integerable .Am i right? plz verify sir
@@nishayadav9717 as you say x is bv over (-infinity, infinity) then it implies that x is bounded over (-infinity, infinity) but x is not bdd over this domain
Great sir ...... I enjoy when you are solving questions within 15 sec. in almost every lecture. Thanks sir ❤❤
13:52 tan(3) to tan(8) is infinite for atleast one values as 3+(π/2)
great sir......Thankyou so much for giving all concept of bounded variation in one video.
Good explanation with good collection 👍👍
Superb 👍👍👍
Excellent explanation... Outstanding....in just one hr lecture each and every thing got Cristal clear ....thanks a lot sir jee.
Nice explanation sir
These lectures are very good. Thank you so much sir.
Excellent teaching sir. Thank you so much for your great lecture
❤❤❤ eske alawa kya hi likh den...kyuki sir se accha samjhane wala Aaj Tak dusra koi Mila nhi. Thank you sir. 🙏
Super explanation 👍
At time 34:10. In this question A is correct option.
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Gajab sir ❤❤❤
Thank you sir ❤
Mistakes in last bouned variation implies monotonicity
Monotonic + bdd is b.v. but ek nbhm k question main closed interval per monotonic diya hua h how it implies that function is of b.v.
Nice 👍👍
Great sir ❤
Thanku so much sir love from ❤❤ uttarakhand
God bless u .......
Nice
Thanks sir , next complex pleasr
Thankyou very much sir. I did not know about a single concept of bounded variation. After watching your video, it is very useful to me. 🤩😍
You are most welcome
Thank you so much for this important video 🙏🏼...
Thank you Sir
It is very helpful for us sir... keep it up,we are with you ❤😊🙏
NBHM 2014 For last option sir, we can say f is bounded by f(0) and below by f(1) therefore it is bdd.
thanku sir for this
Thank You very much sir, for guiding us selflessly.
Your videos are marvellous ! Very useful, clear and doubt solving.
at 49:41 function is not continuous only at 1 . Therefore discontinuity at only finite number of points this implies f is riemann integerable .Am i right? plz verify sir
@50:00 Sir if function is not continuous then need not be f is not reimann integrable
Apke lecture se pura topic revise ho jata + pyq to ho hi jate h
27.22 Problem (b) x=1 is not in the domain itself how can we find tan (pi/2)=infinity and we say it's not BV sir ?
Thank you so much sir 🙏🙏🙏🙏
44:14 option A is correct according to me
. 31:44 f'is bounded variation
Sir... Please this type of one by one topic video with short explanation of complex analysis subject...🙏🏼
Very nice sir
Kindly give on continous and differentiability uniform continuity topic sir before june 2024 csir pleaseeee
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My pleasure... Kindly like, subscribe and share the video with others students too...
Sure sir ☺️ @@DrHarishGarg
Thankyou so much sir,best youtube teacher i ever seen, ❤❤❤❤❤❤keep it sir, short time :=>max knowledge = Dr. HARISH GARG❤
Sir please give a lecture on lebesgue measure and lebesgue integrable function
Really very happy ... thank you for your great effort
Sinx is periodic function,so how you say it is monotonic?pls explain
You email is not active i want to ask one question
Sir if we get a function that asymptotically decreases at 1. how the function will become bounded on [0,1]?
Sir please upload an pyqs video on lebsigue integration
❤
Sir how sinx becomes monotonous on [0,2phi]?
48.59 min I’m confused how pointwish congt because it ls jo continuous
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I have a doubt sir
For the pointwise or piecewise continuous,is it enough to check limit exits or it must be both , limit exists and are same ?
just limit exists is enough....not necessary it should be same
If f is increasing on [a,b] then f is BV?
🙏🌷🌷🌷🌷🙏🌷🌷🙏
Why x is not of BV over (-♾️,♾️)....x is lipschitz over (- ♾️, ♾️) so x is of BV... please correct it sir
Here domain is unbounded , w
@@DrHarishGarg sir x is of BV over (- ♾️, ♾️)
Because derivative bounded throughout the domain
@@nishayadav9717 as you say x is bv over (-infinity, infinity) then it implies that x is bounded over (-infinity, infinity) but x is not bdd over this domain
Plzzzz sir phle kud confirm krke bad main hume bataye u r little bit confused
shi pakde h
Thank you sir.❤
Thank you sir 😊
Thank you sir
Thank you sir❤❤❤
thank you sir